Aromantic compounds Flashcards

1
Q

what is the molecular formula of benzene?

A

C6H6

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2
Q

when is phenyl used?

A

you get a phenyl group C6H5 by removing hydrogen from a benzene ring and the group will always be attached to something else e.g phenol,phenylethanone etc.

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3
Q

Explain Kekule’s ideas but the issues behind it

A

benzene was cyclic and had alternate single and double bonds
Issues:
1.benzene doesn’t undergo electrophilic addition reactions with bromine-alkenes do
2.Benzene has relatively low reactivity unlike alkenes.
3.Benzene has a regular planar structure with equal C-C bond lengths (C=C bonds shorter than C-C)

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4
Q

Evidence against Kekule: reaction with bromine

A

Benzene doesn’t undergo electrophilic addition with bromine like alkenes do. Bromine water remains orange unless it undergoes electrophilic substitution with the usage of a halogen carrier such as Fe,FeBr3,AlBr3 etc. to make Br+ more reactive

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5
Q

Evidence against Kekule: Bond length

A

Benzene has a regular structure with equal C-C bond lengths i.e. its planar. However Kekule didn’t have a regular structure with C=C bonds being shorter than C-C bonds.

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6
Q

Evidence against Kekule: Enthalpy of hydrogenation

A

its less exothermic than expected giving benzene greater stability. Therefore Kekule is wrong because he predicted a more exothermic enthalpy of hydrogenation

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7
Q

Explain structure of delocalised Benzene model

A
  • planar cyclic molecule
  • triganol planar 120 degrees around each C atom
  • 3 sigma bonds per C atom the 4th electron being in a p-orbital
  • p-orbitals overlap sideways above and below plane of ring forming pi bond.
  • 6 pi electrons delocalised over 6 C atoms leading to further stability
  • benzene doesn’t undergo addition reactions as stability would be lost.
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8
Q

Why are higher temperatures not used in nitration?

A

multi substitution would occur

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9
Q

Why are Friedel-Crafts reactions important?

A

leads to C-C bond formation

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10
Q

Why do phenols not react with metal carbonates?

A

Phenol isn’t acidic enough.

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11
Q

Comparison of alkene, benzene and phenol: electrons

A

alkene- pi electrons localised between 2 C atoms + high electron density
benzene-6 pi electrons delocalised over 6 C atoms + lower electron density than alkenes
phenol-6 pi electrons delocalised over 6 C atoms + lone pair in p-orbital on O delocalised into ring activating it + higher electron density than benzene

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12
Q

Comparison of alkene, benzene and phenol: attracting electrophiles

A

alkene-polarises Br2 molecule and attracts it
benzene-only weakly polarises Br2 molecule needs halogen carrier to make powerful electrophile Br+
phenol-polarises Br2 molecules and attracts it

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13
Q

Comparison of alkene, benzene and phenol: type of reaction

A

alkene-electrophilic addition colour change orange to colourless
benzene-electrophilic substitution
phenol-electrophilic substitution colour change orange to colourless and formation of white precipitate 2,4,6-tribromophenol

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14
Q

define activating group

A

lone pair delocalised into benzene ring activating it higher pi electron density of C 2 and 4

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15
Q

define deactivating group

A

withdraw electron density from benzene ring deactivating it. higher pi electron density at C 3

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16
Q

define aromatic compound

A

contains at least one benzene ring.

17
Q

define arene

A

a hydrocarbon containing at least one benzene ring.

18
Q

explain electrophilic substitution: halogenation

A

OE:benzene+Br2(AlBr3+heat and under reflux)–>benzene bromine + HBr
generation of electrophile=Br+AlBr3–>AlBr4- + Br+
regeneration of the catalyst:
H+ + AlBr4- –> AlBr3 + HBr

19
Q

electrophilic substitution:nitration

A

OE:benzene+HNO3(H2SO4/50 degrees)–>Benzene NO2 + H2O
generation of electrophile=HNO3+H2SO4–>NO2+ +HSO4- + H2O
regeneration of catalyst=H+ + HSO4- –> H2SO4

20
Q

electrophilic substitution: Friedel-crafts alkylation

A

OE:benzene+bromoethane(AlBr3+heat and under reflux)–>ethanebenzene+HBr
generation of electrophile=CH3CH2Br+AlBr3=AlBr4- + CH3CH2+
regeneration of catalyst=H+ + AlBr4- = AlBr3+HBr

21
Q

electrophilic substitution: Friedel-Crafts acylation

A

OE:benzene+bromoethanone(AlBr3+heat and under reflux)=benzeneethanone+HBr
generation of electrophile=CH3COBr+AlBr3=AlBr4- + CH3CO+
regeneration of catalyst=H+ + AlBr4-= AlBr3 + HBr

22
Q

How to answer relative resistance exam Q’s

A

-alkene pi e- localised between 2C atoms
-benzene 6 pi e- delocalised over 6C atoms
-phenol lone pair of e- on O atom delocalises into benzene ring
-benzene lower pi e- density than both alkene/phenol
-therefore benzene can’t attract electrophiles as strongly
(in terms of reaction mention electron density because higher density=attracts more strongly)