atomic structure Flashcards

(31 cards)

1
Q

What is the atomic number

A

The number of protons, it defines the element

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2
Q

What is the mass number

A

The protons and the neutrons

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3
Q

How do you calculate the neutrons

A

Mass number - proton number

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4
Q

What is the Bohr model

A

Atoms are made of three subatomic particles, protons, neutrons & electrons

E-s in shells surrounding the nucleus
Protons & neutrons in the nucleus

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5
Q

What is the relative mass & charge of the following

Proton
Neutron
Electron

A

Proton - 1, +1
Neutron- 1, 0
Electron - 1/1840, -1

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6
Q

Define isotope

A

Same number of protons, different number of neutrons

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7
Q

What are the chemical properties of isotopes

A

Isotopes have the same chemical properties
Because they have the same electronic configuration

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8
Q

What evidence was found to support Rutherfords model

A

Most of the alpha particles passed straight through the gold foil
Atoms are mainly empty space

Small number of particles bounced back
Atoms have a smalls positive nucleus

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9
Q

What are the key differences between Thompson’s model & Bohr’ model

A

Bohr model has e’s surrounding nucleus in shells
Small positive nucleus

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10
Q

Define ionisation energy

A

The amount of energy required to remove one mole of electron (E-s) from one mole of atoms in gaseous state

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11
Q

Give the first 3 ionisation energy of Na

A

Na (g) -> Na+ (g) + E-
Na+ (g) -> Na2+ (g) + E-
Na2+ (g) -> Na3+ + E-

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12
Q

What are the 3 factors that will influence ionisation energy

A

Nuclear charge, amount of protons-
More protons means a stronger attraction between the nucleus and the outer e-s
More energy is needed to remove the outer e-

Distance from the nucleus-
Outer e- is closed it the nucleus
Means there is a stronger attraction between the outer e- and nucleus
More energy needed to remove outer e-

Shielding -
More shielding
Weaker attraction between outer e- and the nucleus
Less energy needed to remove the outer e-

CONSIDER SHIELDING FIRST

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13
Q

What are the trends in the first IE across a period

A

Increases across a period

Atomic radius decreases across a period
Some shielding
Increases protons -> increasing attraction between protons & outer e-s

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14
Q

What is the electronic configuration for chromium

A

1s2, 2s2, 2p6,3s2,3p6,4s1, 3d5

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15
Q

What is the electronic configuration for copper

A

1s2, 2s2, 2p6,3s2,3p6,4s1, 3d10

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16
Q

Trends in ionisation energies across period 2

A

General increase in 1st IE
Shielding is the same for all atoms
Number of protons increase - increasing attraction between outer e- and nucleus

17
Q

Trends in ionisation energies in period 3

A

General increase in 1st IE
Shielding is the same for all atoms
Number of protons increase - increasing attraction between outer e- and nucleus

18
Q

How does ionisation energy change down a group

A

IE decreases down groups because
Atomic radius increases
Shielding increases
Outer e-s less attracted to nucleus

19
Q

State and explain the trend is atomic radius down a group

A

Atomic radius increases
Shielding increases
Outer e-s less attracted to nucleus

20
Q

Why does atomic radius get smaller from right to left across a period

A

Shielding stays the same
Number of protons increases
Outer electrons are more attracted to the nucleus

21
Q

How can time of flight be measured

A

T = d/v

T = d square root m/2KE

22
Q

What does KE equal
What does m equal
What does v2 equal

A

KE + 1/2 mv^2
M = KE / 1/2 v2
V2 = square root KE/ 1/2 m

23
Q

What two factors does the mass spectrometer measure

A

Relative abundance
Mass/charge ratio (m/z)

24
Q

Why are the sample particles ionised?

A

• So they can be accelerated towards the negatively charged plate
• So they generate a current when they hit the detector

25
How is the ion accelerated?
•Positive ions attracted to the negatively charged plate • All ions have the same kinetic energy
26
How are ions separated in the flight tube?
• lons travelling at higher speeds (small m/z) move ahead of those travelling more slowly (large m/z)
27
How are the ions detected?
• Each ions hits the detector • Ion gains an electron • Generates a current • Size of the current is proportional to the abundance of the ion
28
What is the formula for electron impact
X(g) —> X+ (g) + e-
29
What is the equation for electro spray ionisation
H+ —> XH+
30
Describe electrospray ionisation
The sample X is dissolved in a volatile solvent (eg water or methanol) and injected through a fine hypodermic needle to give a fine mist (aerosol). The tip of the needle is attached to the positive terminal of a high-voltage power supply. The particles are ionised by gaining a proton (ie an H + ion which is simply one proton) from the solvent as they leave the needle producing XH* ions (ions with a single positive charge and a mass of Mr + 1).
31
Describe electron impact
The sample being analysed is vaporised and then high energy electrons are fired at it. The high energy electrons come from an 'electron gun' which is a hot wire filament with a current running through it that emits electrons. This usually knocks off one electron from each particle forming a 1+ ion