Biological Molecules - Carbs And Lipids Flashcards
(37 cards)
What is a monomer?
small identical/similar molecules condensed to make larger molecules called polymers
eg: alpha glucose, aa, nucleotides
What is a polymer?
Large molecules made by joining 3 or more identical or similar monomers together
eg: proteins, polysaccharides, polynucleotides
define condensation reactions
- joins two monomers together to form a - chemical bond
- removal of one water molecule
eg: alpha glucose -> starch
define hydrolysis reaction
- breaks a chemical bond between two monomers
- via addition of water molecule
eg: cellulose -> beta glucose
DNA -> DNA nucleotides
disaccharide/dimer equation
C6H12O6 + C6H12O6 -> C12H22O11 + H2O
Where do condensation reactions occur in monomers?
0H group of C4 and C1 H of other group
maltose
alpha glucose + alpha glucose
maltase enzyme
lactose
galactose + glucose
lactase enzyme
sucrose
glucose + fructose
sucrase enzyme
differences between monosaccharides
a-glucose: both OH (hydroxyl groups) down
galactose: both OH up
B-glucose: one OH down, one OH up
fructose: pointy top
starch
- insoluble, doesn’t affect water potential
- helical, so compact
- large so doesnt diffuse out of cells
- branched so high surface area for rapid hydrolysis to release glucose for respiration
amylose
a (1-4) glycosidic bonds
- linear chains of a glucose
- compact and helical, so good for storage
- insoluble, doesnt affect water potential
amylopectin
branched
a(1-4) and a(1-6) glycosidic bonds
large SA for rapid hydrolysis
isnoluble doesnt affect water potential
large so doesnt diffuse out of cells
glycogen
- shorter chains
- more branched
-larger SA
-humans/animal cells
-short chains so more rapidly hydrolysed into glucose for RP
-insoluble, doesnt affect water potential - large, so doesnt diffuse out of cells
a strach molecule has a spiral shape. explain why this shape is important to its function in cells.
helical so compact
insoluble, no effect in WP
large molecule so cant leave out of cell
structure of cellulose is related to its role in plant cell walls. explain how.
- long straight unbranched chains of beta glucose
- joined by many weak hydrogen bonds
- form microfibrils
- provides strength
cellulose structure
- long straight unbranched chains
- every other b glucose inverted 180 degrees
- b (1-4) glycosidic bonds
- weak Hydrogen bonds form cross links between chains
- forms microfibrils (that form cellulose fibres, stregnth and support in plant cell walls)
hydrogen bonds are important in cellulose molecules. explain why.
hydrogen bonds forms cross links between chains
-form microfibrils
- provides strength and rigidity
-weak hydrogen bonds provide strength in large numbers
reducing sugars
galactose
glucose
lactose
maltose
fructose
non reducing sugars
sucrose
describe how the student would show that a reducing sugar was present in a solution
- add equal volumes of benedicts solution
- and heat to 95 degrees celsius
- red/orange PPT is a positive result
2 different reducing sugar solutions (A+B) of same concentration have an enzyme added before benedicts. They both produced red PPT.
After 20 minutes, B had twice as much PPT as A. Suggest why.
A is a monosaccharide and B is a disaccharide
- enzyme hydrolysed glycosidic bonds in disaccharide, releasing 2 monosaccharides
- both monosaccharides are reducing sugar, PPT doubled in B
describe how the student would show a non-reducing sugar was present in a solution
- complete benedicts test and observe a negative result (blue solution)
- add acid (HCl) and heat to 95 degrees
- then neutralise with alkali
- add benedicts solution again and then heat to 95
- red/orange PPT is positive result
describe how you would produce a calibration curve for a reducing sugar of unknown concentration and use it to obtain results
- make up several known concentrations of [R sugar]
- carry out benedicts test
- use a colourimeter to measure the colour absorbance of each solution
- and plot a calibration curve:
X: known conc
Y: absorbance/transmission - find conc of unknown sample using calibration curve