Block 1 - Foundations Flashcards

(44 cards)

1
Q

Anhydride functional group

A

O O
ll ll
C-C-O-C-C

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2
Q

anhydride nomenclature

A

alkanoic anhydride

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3
Q

nitrile functional group

A

-C=_N

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4
Q

nitrile nomenclature

A

alkane nitrile

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5
Q

thiol functional group

A

-C-SH

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6
Q

thiol nomenclature

A

alkane-n-thiol

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7
Q

phenol functional group

A

benzene ring with -OH

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8
Q

phenol nomenclature

A

alkylphenol

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9
Q

nomenclature priority

A

-COOH > ester > amide > nitrile > -CHO > ketone > alcohol > amine > C=C > alkyne > alkane > ether > alkyl halide = alkyl

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10
Q

DBE formula

A

1/2 (2n4 + n3 - n1 + 2)

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11
Q

newman projection terminology

A

staggered vs. eclipsed (anti, gauche and syn)

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12
Q

electrostatic potential map colours

A
red = electron-rich (high electron density)
blue = electron-poor (low electron density)
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13
Q

types of intermolecular forces

A
  • momentary dipole-dipole attractions (dispersion forces)
  • dipole-dipole interactions
  • hydrogen bonding
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14
Q

chromatography components

A
  • solvent/mobile liquid phase = relatively non-polar

- absorbent/solid stationary phase = polar

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15
Q

chromatography mechanism

A

if solute is:

  • polar = more strongly attracted to polar stationary phase thus moves slowly
  • non-polar = less attracted to polar stationary phase thus moves rapidly
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16
Q

substitution bond changes

A

same type of bonds (sigma) broken and formed

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17
Q

substitution DBE changes

A

DBE remains same

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18
Q

addition bond changes

A

1 pi bond broken and 2 sigma bonds formed

19
Q

addition DBE changes

A

DBE decreases

- product less unsaturated/more saturated

20
Q

elimination bond changes

A

2 sigma bonds broken and 1 pi bond formed

21
Q

elimination DBE changes

A

DBE increases

- product more unsaturated

22
Q

reaction subclassifications

A

1) polar/non-polar
2) nucleophilic/electrophilic reagent
3) nature of substrate (alkyl - chain base, aryl - aromatic ring etc.)

23
Q

conditions of aromatic ring

A
  • planar
  • cyclic
  • all atoms have p orbital
  • ring contains pi electrons
24
Q

non-polar reactions

A
  • reactions of free radicals

- bond breaking/making may take place simultaneously

25
free radicals
neutral species with an unpaired electron
26
polar reactions
- one bonding partner supplies electron pair while the other receives it to form a new bond - reaction between nucleophile and electrophile to form a new covalent bond
27
nucleophile
- nucleus (+ve charge) lover | - electron rich: either neutral or -vely charged and have either lone e- pair or e- in pi bonds
28
electrophile
- electron lover | - neutral or +vely charged
29
types of bond cleavage
- symmetrically: homolytic bond cleavage | - unsymmetrically: heterolytic bond cleavage
30
homolytic bond cleavage
- 1 e- ends up on each formerly bonded atom | - non-polar reactions
31
heterolytic bond cleavage
- both e-s end up on one of the formerly bonded atoms - polar reactions - e- s move towards more electronegative atom - carbocations more common than carbanion as C is not very electronegative
32
determination of nucleophilic/electrophilic reactions
determined by reagent/species doing the replacing | - if unsure, check other reactant as they will be opposites
33
reaction mechanisms
detailed pathway by which reactants are converted to products - often require multiple steps (elementary reactions) that require multiple steps - reactive intermediates are unstable and short-lived (formed in one step then used up in the next)
34
types of nucleophilic substitution
Sn1 and Sn2
35
Sn1
stepwise so bond breaking THEN bond making
36
Sn2
single step so bond breaking/forming simultaneous
37
alkenes and alkynes are
nucleophiles (electron rich - e-s in pi bond) thus undergo electrophilic addition
38
bonds in benzene
in reality, 6 identical 1.5 bonds but drawn as 1 of 2 resonance forms
39
resonance energy
conjugated double bonds give extra stability
40
simple benzene nomenclature
___benzene (e.g bromobenzene)
41
complex benzene nomenclature
phenyl____
42
benzene common names
- NH2 = aniline - CHO = benzaldehyde - CO2H = benzoic acid - OH = phenol - CH3 = toluene
43
disubstituted benzenes
- 1,2-substituted = ortho - 1,3-substituted = meta - 1,4-substituted = para
44
why are double bonds more polar?
relative mobility of pi electrons as they are not held as tight being further from the nuclei