C4 - Chemical changes Flashcards

1
Q

How are Metal Oxides formed?

WHat are redox reactions(Oxidation and Reduction)?

A
  • Metals react with oxygen in the air to produce metal oxides
  • Oxidation and reduction involve the addition or removal of oxygen from a substance and are called redox reactions
  • Oxidation is a reaction in which:
    • Oxygen is added to an element or a compound
  • Reduction is a reaction in which:
    • Oxygen is removed from an element or a compound
  • A common example is the reaction with red-brown copper metal to produce black copper oxide:

2Cu + O2 ⟶ 2CuO

  • In this reaction copper metal has been oxidised since oxygen has been added to it
  • Another example is the reaction of zinc oxide with carbon:

ZnO + C ⟶ Zn + CO

  • In this reaction the zinc oxide has been reduced since it has lost oxygen. The carbon atom has been oxidised since it has gained oxygen
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2
Q

What is The reactivity series?

A
  • The tendency of a metal to lose electrons is a measure of how reactive the metal is
  • A metal that is high up on the series loses electrons easily and is thus more reactive than one which is lower down on the series
  • Note that although carbon and hydrogen are nonmetals, they are included in the series as they are useful in extracting metals from their oxides by reduction processes
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3
Q

What happens when Metals react with Water?

A

metal + water → metal hydroxide + hydrogen

  • Some metals react with water
  • Metals above hydrogen in the reactivity series will react with water, but the reaction may be very slow
  • Metals that react with cold water form a metal hydroxide and hydrogen gas:

For example calcium:

Ca + 2H2O → Ca(OH)2 + H2

calcium + water → calcium hydroxide + hydrogen

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4
Q

Name the Reactivity series

A
  • There are several reactivity series mnemonics to help you remember the order of the metals
  • One that we like goes as follows:

Please

send

lions,

cats,

monkeys

and

cute

zebras

into

hot

countries

signed

Gordon

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5
Q

How do Metals react with Acids?

A
  • Only the metals below hydrogen in the reactivity series will not react with acids
  • When acids and metals react, the hydrogen atom in the acid is replaced by the metal atom to produce a salt and hydrogen gas:

metal + acid → metal salt + hydrogen

  • For example iron:

Fe + 2HCI → FeCl2 + H2

iron + hydrochloric acid → iron(II)chloride + hydrogen

  • In both these types of reactions (water and acids) the metals are becoming positive ions
  • The reactivity of the metals is related to their tendency to become an ion
  • The more reactive the metal the more easily it becomes an ion (by losing electrons)
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6
Q

Why do Non-metals appear in the Reactivity Series?

A
  • Why do non-metals appear in the reactivity series of metals?
  • A reactivity series will usually contain the elements carbon and hydrogen
  • This is beause these elements play different roles in our understanding the reactions of metals and our ability to predict how metals can be extracted from their ores
  • From the reactions with water and acids we have seen that whether a reaction takes place depends on the position of the metal in the reactivity series relative to hydrogen
    • A reaction takes place if the metal is able to displace hydrogen from water or acids
  • Carbon is a cheap reducing agent which can be used to remove oxygen from metal oxide ores
    • Placing carbon in the reactivity series allows us to see whether a metal oxide can be reduced or not by carbon
  • Metals below carbon can be extracted by heating the oxide with carbon
  • Metals higher than carbon have to be extracted by other methods, such as electrolysis
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7
Q

What is a Displacement reaction?

A
  • The reactivity of metals decreases going down the reactivity series.
  • This means that a more reactive metal will displace a less reactive metal from its compounds
  • Two examples are:
    • Reacting a metal with a metal oxide (by heating)
    • Reacting a metal with an aqueous solution of a metal compound
  • For example it is possible to reduce copper(II) oxide by heating it with zinc.
  • The reducing agent in the reaction is zinc:

Zn + CuO → ZnO + Cu

zinc + copper oxide → zinc oxide + copper

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8
Q

What happens in displacement reactions between metals & Aqueous soloutions?

A
  • This is easily seen as the more reactive metal slowly disappears from the solution, displacing the less reactive metal
  • For example, magnesium is a reactive metal and can displace copper from a copper sulfate solution:

Mg + CuSO4→ MgSO4 + Cu

  • The blue color of the CuSO4 solution fades as colorless magnesium sulfate solution is formed.
  • Copper coats the surface of the magnesium and also forms solid metal which falls to the bottom of the beaker
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9
Q

What are Redox reactions?

A

balanced equation for the reaction between magnesium and copper sulfate solution can be written in terms of the ions involved:

Mg(s) + Cu2+(aq) + SO42-(aq) → Mg2+(aq) + SO42-(aq) + Cu(s)

Sulfate ions, SO42-, appear on both sides of the equation, but they do not take part in the reaction. The equation can be rewritten without them:

Mg(s) + Cu2+(aq) → Mg2+(aq) + Cu(s)

This equation is an example of a balanced ionic equation. It can be split into two half equations :

Mg(s) → Mg2+(aq) + 2e- (oxidation)

Cu2+(aq) + 2e- → Cu(s) (reduction)

Notice that:

  • magnesium atoms lose electrons - they are oxidised
  • copper ions gain electrons - they are reduced

Reduction and oxidation happen at the same time, so the reactions are called redox reactions.

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10
Q

Oxidation is the ______ of Electrons, Reduction is _______ of electrons

A

Oxidation is the loss of electrons, and reduction is the gain of electrons.

It helps to remember OIL RIG - oxidation is loss of electrons, and reduction is gain of electrons.

Displacement reactions are just one example of redox reactions. Electrolysis reactions are also redox reactions.

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11
Q

How do we extract Metals?

A
  • The Earth’s crust contains metals and metal compounds such as gold, copper, iron oxide and aluminium oxide
  • Useful metals are often chemically combined with other substances forming ores
  • A metal ore is a rock that contains enough of the metal to make it worthwhile extracting
  • They have to be extracted from their ores through processes such as electrolysis, using a blast furnace or by reacting with more reactive material
  • In many cases the ore is an oxide of the metal, therefore the extraction of these metals is a reduction process since oxygen is being removed
  • Common examples of oxide ores are iron and aluminium ores which are called haematite and bauxite respectively
  • Unreactive metals do not have to be extracted chemically as they are often found as the uncombined element
  • This occurs as they do not easily react with other substances due to their chemical stability
  • Examples include gold and platinum which can both be mined directly from the Earth’s crust
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12
Q

How are Elements more reactive then Carbon extracted?
How are elements less reactive than Carbon but more reactive than silver Extracted?

How are Elements less copper extracted?

A
  • The most reactive metals are at the top of the series
  • The tendency to become oxidised is thus linked to how reactive a metal is and therefore its position on the reactivity series
  • Metals higher up are therefore less resistant to oxidation than the metals placed lower down which are more resistant to oxidation
  • The position of the metal on the reactivity series determines the method of extraction
  • Higher placed metals (above carbon) have to be extracted using electrolysis as they are too reactive and cannot be reduced by carbon
  • Lower placed metals can be extracted by heating with carbon which reduces them
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13
Q

How is Iron Extracted?

A

Extracting iron

Iron(III) oxide is reduced to molten iron when it reacts with carbon. One of the products is carbon monoxide:

iron(III) oxide + carbon → iron + carbon monoxide

Fe2O3(s) + 3C(s) → 2Fe(l) + 3CO(g)

This method of extraction works because carbon is more reactive than iron, so it can displace iron from iron compounds. Extracting a metal by heating with carbon is cheaper than using electrolysis.

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14
Q

How is Aluminium Extracted?

A

Extracting aluminium

Aluminium is more reactive than carbon so it must be extracted from its compounds using electrolysis. Even though aluminium is more abundant than iron in the Earth’s crust, aluminium is more expensive than iron. This is mainly because of the large amounts of electrical energy used in the extraction process.

Electrolysis of aluminium oxideThe electrolyte

Aluminium ore is treated to produce pure aluminium oxide. The electrolytes used in electrolysis are ionic compounds:

  • in the molten state, or
  • dissolved in water

Aluminium oxide is insoluble in water, so it must be molten to act as an electrolyte. However, the melting point of aluminium oxide is high. A lot of energy must be transferred to break its strong ionic bonds, and this is expensive. To reduce costs, powdered aluminium oxide is dissolved in molten cryolite. This ionic compound melts at a lower temperature than aluminium oxide, reducing costs. However, significant amounts of energy are required to melt the cryolite.

The electrolysis process

The diagram shows an electrolysis cell used to extract aluminium. Both electrodes are made of graphite, a form of carbon with a high melting point and which conducts electricity.

During electrolysis:

  • at the cathode, aluminium ions gain electrons and form aluminium atoms
  • at the anode, oxide ions lose electrons and form oxygen gas

The oxygen reacts with the carbon anodes, forming carbon dioxide. So the anodes are gradually oxidised. They must be replaced frequently, adding to the cost of producing aluminium.

Worked example - Higher

Explain, with the help of a half equation, how oxide ions are oxidised during the electrolysis of aluminium oxide.

The half equation is: 2O2- → O2 + 4e-. It shows that oxide ions lose electrons, and oxidation is loss of electrons.

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15
Q

What are Acids?

A

Acids

Acids form acidic solutions in water. Acids produce hydrogen ions, H+ in aqueous solution. For example:

HCl(aq) → H+(aq) + Cl-(aq)

Acidic solutions have pH values less than 7.

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16
Q

What are Alkalis?

A

Alkalis form alkaline solutions in water. Alkalis produce hydroxide ions, OH- in aqueous solution. For example:

NaOH(aq) → Na+(aq) + OH-(aq)

Alkaline solutions have pH values greater than 7.

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17
Q

What are Neutral Soloutions?

A

A neutral solution is neither acidic, nor alkaline. A neutral solution has a pH value of 7.

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18
Q

What is the pH scale?

A

The pH scale measures the acidity or alkalinity of a solution. The pH of a solution can be measured using a pH probe, or estimated using universal indicator and a colour chart.

Universal indicator is one example of an acid-alkali indicator. Indicators show whether a solution is acidic, neutral (pH 7) or alkaline. The table shows the colours for litmus paper.

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19
Q

What happens when Acids with Metals?

A
  • Only metals above hydrogen in the reactivity series will react with dilute acids.
  • The more reactive the metal then the more vigorous the reaction will be.
  • Metals that are placed high on the reactivity series such as potassium and sodium are very dangerous and react explosively with acids.
  • When acids react with metals they form a salt and hydrogen gas:
  • The general equation is:

metal + acid ⟶ salt + hydrogen

  • Some examples of metal-acid reactions and their equations are given below:
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20
Q

Are Metal & Acid Reactions Redox reactions?

A
  • Metal-acid reactions are redox reactions
  • Redox means reduction and oxidation at the same time
  • If we analyse the ionic equation for the reaction between zinc and hydrochloric acid:

Zn + 2HCl ⟶ ZnCl2 + H2

  • The ionic equation is:

Zn + 2H+⟶ Zn2+ + H2

  • This equation can be further split into two half equations illustrating oxidation and reduction individually:

Zn → Zn2+ + 2e

2H+ + 2e→ H2

  • The zinc atoms are thus oxidised as they lose electrons.
  • The hydrogen ions are thus reduced as they gain electrons.
  • Both reactions are occurring at the same time and in the same reaction chamber hence it is a redox reaction
21
Q

What is a Base?

A

Bases and alkalis

A base is any substance that reacts with an acid to form a salt and water only. This means that metal oxides and metal hydroxides are bases.

Bases that are soluble in water are called alkalis and they dissolve in water to form alkaline solutions. For example:

  • copper oxide is a base, but it is not an alkali because it is insoluble in water
  • sodium hydroxide is a base, and it dissolves in water so it is also an alkali
22
Q

What are Neutralisation reactions?

A

A neutralisation reaction is a reaction between an acid and a base. Remember:

  • acids in solution are sources of hydrogen ions, H+
  • alkalis in solution are sources of hydroxide ions, OH-

In acid-alkali neutralisation reactions, hydrogen ions from the acid react with hydroxide ions from the alkali:

H+(aq) + OH-(aq) → H2O(l)

Pure water is neutral (its pH is 7). A neutral solution can be produced if the correct amounts of acid and alkali react together. The change in pH during a neutralisation reaction can be measured using a pH probe and meter, or estimated using universal indicator solution and a pH colour chart.

An acid-alkali neutralisation is the reaction between hydrogen ions and hydroxide ions, forming water.

23
Q

What happens when Metal Hydroxides and Metal oxides react with an acid?

A

Reactions of Acids with Metal Oxides and Metal Hydroxides

  • Metal oxides and metal hydroxides act as bases
  • When they react with acid, a neutralisation reaction occurs
  • In all acid-base neutralisation reactions, salt and water are produced
  • The following are some specific examples of reactions between acids and metal oxides / hydroxides:

2HCl + CuO ⟶ CuCl2 + H2O

H2SO4 + 2NaOH ⟶ Na2SO4 + 2H2O

HNO3 + KOH ⟶ KNO3 + H2O

24
Q

What happens when Acids react with Metal Carbonates?

A
  • Acids will react with metal carbonates to form the corresponding metal salt, carbon dioxide and water
  • These reactions are easily distinguishable from acid – metal oxide/hydroxide reactions due to the presence of effervescence caused by the carbon dioxide gas

The following are some specific examples of reactions between acids and metal carbonates:

2HCl + Na2CO3 ⟶ 2NaCl + H2O + CO2

Reactions with carbonates

A salt, water and carbon dioxide are produced when acids react with carbonates. In general:

Acid + carbonate → salt + water + carbon dioxide

For example:

Hydrochloric acid + copper carbonate → copper chloride + water + carbon dioxide

2HCl(aq) + CuCO3(s) → CuCl2(aq) + H2O(l) + CO2(g)

H2SO4 + CaCO3⟶ CaSO4 + H2O + CO2

25
Q

How do you predict the names of the salt produced?

A

Salts

  • A salt is a compound that is formed when the hydrogen atom in an acid is replaced by a metal
  • For example if we replace the H in HCl with a potassium atom, then the salt potassium chloride is formed, KCl
  • Salts are an important branch of chemistry due to the varied and important uses of this class of compounds
    • These uses include fertilisers, batteries, cleaning products, healthcare products and fungicides

Naming salts

  • The name of a salt has two parts
  • The first part comes from the metal, metal oxide or metal carbonate used in the reaction
  • The second part comes from the acid
  • The name of the salt can be determined by looking at the reactants
  • For example hydrochloric acid always produces salts that end in chloride and contain the chloride ion, Cl
  • Other examples:
    • Sodium hydroxide reacts with hydrochloric acid to produce sodium chloride.
    • Zinc oxide reacts with sulfuric acid to produce zinc sulfate
  • A list of the common ions and their formulae is shown below

Salts have no overall charge since the sum of the charges on the ions is equal to zero

  • From the table of the common ions it is clear the charges on each the Group I elements is always +1, Group II is +2, Group VI is -2 and Group VII is -1
  • If you know the ions present in a salt you can identify the formula from balancing the charges
26
Q

What is the formula of magnesium phosphate?

A

Answer

Step 1: Write out the formulae of each ion, including their charges

Mg2+ and PO43-

Step 2: Balance the charges by multiplying them out:

(Mg2+) x 3 = +6 and (PO43-) x 2 = -6; so +6 – 6 = 0.

So the formula is Mg3(PO4)2

27
Q

Naming Salts

A

Naming salts

The name of a salt has two parts. The first part comes from the base, alkali or metal carbonate. The second part comes from the acid:

  • hydrochloric acid produces chloride salts HCL
  • nitric acid produces nitrate salts HNO3
  • sulfuric acid produces sulfate salts H2SO4
28
Q

How do you produce salts from insoluble substances?

A

Making soluble salts from insoluble substances

A soluble salt can be prepared by reacting an acid with a suitable insoluble reactant including:

  • a metal
  • a metal oxide
  • a metal hydroxide
  • a carbonate

The insoluble reactant chosen depends upon the particular salt required.

For example, copper does not react with dilute acids, so this metal cannot be used. On the other hand, sodium is too reactive to be used safely.

As the reaction between metals and acids produces flammable hydrogen, chemists usually make salts by reacting a metal oxide or a metal carbonate with an acid.

Choosing reactants

The table shows some examples of the salts produced by different combinations of insoluble reactants and acids.

Making a salt

To make a soluble salt from an acid and an insoluble reactant:

  1. Add powdered insoluble reactant to acid in a beaker, one spatula at a time, stirring to mix. Continue adding powder until it is in excess (some unreacted powder is left over). All the acid has now reacted.
  2. Filter the mixture in the beaker to remove the excess solid. The filtrate now contains only the salt and water.
  3. Heat the solution in an evaporating dish over a water bath. Stop heating when small crystals start to appear around the edge of the evaporating basin. The solution is now saturated.
  4. Leave the saturated solution at room temperature for a day or two. This gives time for large crystals to form.
  5. If necessary, dry the crystals by dabbing gently with filter paper.
29
Q

Preparing A soluble salts

A
  • A soluble salt can be made from the reaction of an acid with an insoluble base
  • During the preparation of soluble salts, the insoluble reactant is added in excess to ensure that all of the acid has reacted
  • If this step is not completed, any unreacted acid would become dangerously concentrated during evaporation and crystallisation
  • The excess reactant is then removed by filtration to ensure that only the salt and water remain
  • Since all of the acid has reacted and the excess solid base has been removed then the solution left can only be salt and water
  • If a carbonate was used as the solid base instead of an oxide or hydroxide, then any carbon dioxide gas produced would have been released into the atmosphere
  • A common example is the preparation of copper(II) sulfate which can be made with copper(II) oxide and dilute sulfuric acid:

CuO (s) + H2SO4 (aq) ⟶ CuSO4 (s) + H2O (l)

  • The acid could also be reacted with a metal to produce the salt, as long as the metal is above hydrogen in the reactivity series and not too reactive so that a dangerous reaction does not take place
30
Q

What is the difference between a Strong and Weak Acid?

A

Strong and weak acids

Acids in solution are a source of hydrogen ions, H+. The hydrogen ions are produced when the acid dissociates or breaks down to form ions.

Strong acids

Strong acids completely dissociate into ions in solution. For example, hydrochloric acid is a strong acid. It ionises completely to form hydrogen ions and chloride ions:

HCl(aq) → H+(aq) + Cl-(aq)

Nitric acid and sulfuric acid are also strong acids.

Weak acids

Weak acids only partially dissociate in solution. For example, ethanoic acid is a weak acid. It is only partially ionised to form hydrogen ions and ethanoate ions:

CH3COOH(aq) ⇌ H+(aq) + CH3COO-(aq)

The ⇌ symbol is used in the equation to show that the reaction is a reversible reaction and does not go to completion.

31
Q

What is the significance of Hydrogen Ion Concentration?

A

pH and hydrogen ion concentration

The pH of a solution is a measure of its concentration of hydrogen ions:

  • the higher the concentration of H+ ions in an acidic solution, the lower the pH
  • the lower the concentration of H+ ions in an acidic solution, the higher the pH

This means that, for a given concentration in aqueous solution, the stronger an acid, the lower the pH.

The more concentrated the solution of an acid, the lower its pH will be.

If the hydrogen ion concentration in a solution increases by a factor of 10, the pH of the solution decreases by 1 unit.

pH of alkaline solutions

The higher the concentration of OH- ions in an alkaline solution, the higher the pH.

32
Q

What is relative Acidity?

A
  • We have already seen that pH is a measure of the concentration of H+ ions in solution
  • The pH scale is logarithmic, meaning that each change of 1 on the scale represents a change in concentration by a factor of 10
  • Therefore an acid with a pH of 3 has ten times the concentration of H+ ions than an acid of pH 4
  • An acid with a pH of 2 has 10 x 10 = 100 times the concentration of H+ ions than an acid with a pH of 4
  • From this we can summarize that for two acids of equal concentration, where one is strong and the other is weak, then the strong acid will have a lower pH due to its capacity to dissociate more and hence put more H+ ions into solution than the weak acid
33
Q

What is a Titration?

A
  • Titrations are a method of analysing the concentration of solutions
  • Acid-base titrations are one of the most important kinds of titrations
  • They can determine exactly how much alkali is needed to neutralise a quantity of acid – and vice versa
  • You may be asked to calculate the moles present in a given amount, the concentration or volume required to neutralise an acid or a base
  • Titrations can also be used to prepare salts or other precipitates and in redox reactions
  • Indicators are used to show the endpoint in a titration
  • Wide range indicators such as litmus are not suitable for a titration as they do not give a sharp enough colour change at the end point
  • Some of the most common indicators with their corresponding colours are shown below
34
Q

What do you have to calculate in Titrations?

A
  • Once a titration is completed and the average titre has been calculated, you can now proceed to calculate the unknown variable using the formula triangle as shown below
35
Q

How do you make salts from Acids and Alkalis?

A

A soluble salt can be prepared by reacting an acid with a dilute solution of an alkali such as sodium hydroxide or ammonia. The main steps are:

  1. Carry out a titration. This is to determine the volumes of acid and alkali that must be mixed to obtain a solution containing only salt and water.
  2. Mix the acid and alkali in the correct proportions, as determined in step 1, but this time without including an indicator.

Pure dry crystals can be produced by crystallisation, followed by drying on a watch glass or in a warm oven.

Carrying out a titration to find out volumes of acid and alkali solutions that reactApparatus

The apparatus needed includes:

  • a pipette to accurately measure the volume of a reactant before transferring it to a conical flask
  • a burette to add small, measured volumes of one reactant to the other reactant

Method

This is an outline method for carrying out a titration in which an acid is added to an alkali. The method is the same for sulfuric acid, hydrochloric acid and nitric acid.

  1. Use the pipette and pipette filler to add a measured volume of sodium hydroxide solution to a clean conical flask.
  2. Add a few drops of indicator and put the conical flask on a white tile.
  3. Fill the burette with hydrochloric acid and note the starting volume.
  4. Slowly add the acid from the burette to the alkali in the conical flask, swirling to mix.
  5. Stop adding the acid when the end-point is reached (when the indicator first permanently changes colour). Note the final volume reading.
  6. Repeat steps 1 to 5 until concordant titres are obtained. More accurate results are obtained if acid is added drop by drop near to the end-point.

Readings should be recorded to two decimal places, ending in 0 or 5 (where the liquid level is between two graduations on the burette). The titre is the volume added (the difference between the end and start readings).

Analysis

At least two concordant titres should be ticked (✔) in the table above. These are titres within 0.20 cm3 (or sometimes 0.10 cm3) of each other.

Worked example

Calculate the mean titre from the table above. Ignore the rough run, and run 2 (because they are not concordant):

Mean titre = (24.60 + 24.70)/2

= 24.65 cm3

36
Q

What are Electrolytes?
What is an Electrode?
What is an Anode?
What is an Anion?
What is a cathode?
What is a Cation?

A
  • Covalent compounds cannot conduct electricity hence they do not undergo electrolysis
  • An electrolytic cell is the name given to the set-up used in electrolysis and which consists of the following:
    • Electrode: a rod of metal or graphite through which an electric current flows into or out of an electrolyte
    • Electrolyte: ionic compound in molten or dissolved solution that conducts the electricity
    • Anode: the positive electrode of an electrolysis cell
    • Anion: negatively charged ion which is attracted to the anode
    • Cathode: the negative electrode of an electrolysis cell
    • Cation: positively charged ion which is attracted to the cathode
37
Q

Where do the ions move in Electrolysis?

A
  • During electrolysis the electrons move from the power supply towards the cathode
  • Electron flow in electrochemistry thus occurs in alphabetical order as electrons flow from the anode to the cathode
  • Positive ions within the electrolyte migrate towards the negatively charged electrode which is the cathode
  • Negative ions within the electrolyte migrate towards the positively charged electrode which is the anode
38
Q

How are the products of electrolysis formed?

A

Products of electrolysis

When ions reach an electrode, they gain or lose electrons. As a result, they form atoms or molecules of elements:

  • positive ions gain electrons from the negatively charged cathode
  • negative ions lose electrons at the positively charged anode

Molten lead bromide, PbBr2(l), is an electrolyte. During electrolysis:

  • Pb2+ ions gain electrons at the cathode and become Pb atoms
  • Br- ions lose electrons at the anode and become Br atoms, which pair up to form Br2 molecules

So lead forms at the negative electrode and bromine forms at the positive electrode.

Example

Predict the products of electrolysis of molten calcium chloride.

Positively charged calcium ions move to the negative electrode. Here, they gain electrons to form calcium atoms, so calcium is formed at the negative electrode.

Negatively charged chloride ions move to the positive electrode. Here, they lose electrons to form chlorine atoms. The atoms join up in pairs to form Cl2 molecules, so chlorine gas is formed at the positive electrode.

During the electrolysis of molten salts, a metal forms at the cathode and a non-metal forms at the anode.

39
Q

How do you use electrolysis on Lead Bromide?

A
  • Lead(II) bromide is a binary ionic compound meaning that it is a compound consisting of just two elements joined together by ionic bonding
  • When these compounds are heated beyond their melting point, they become molten and can conduct electricity as their ions can move freely and carry the charge
  • These compounds undergo electrolysis and always produce their corresponding element
  • To predict the products of any binary molten compound first identify the ions present
  • The positive ion will migrate towards the cathode and the negative ion will migrate towards the anode
  • Therefore the cathode product will always be the metal and the product formed at the anode will always be the non-metal

Method:

  • Add lead(II) bromide into a crucible and heat so it will turn molten, allowing ions to be free to move and conduct an electric charge
  • Add two graphite rods as the electrodes and connect this to a power pack or battery
  • Turn on the power pack or battery and allow electrolysis to take place
  • Negative bromide ions move to the positive electrode (anode) and lose two electrons to form bromine molecules. There is bubbling at the anode as brown bromine gas is given off
  • Positive lead ions move to the negative electrode (cathode) and gain electrons to form grey lead metal which deposits on the bottom of the electrode

Electrode Products:

Anode: Bromine gas

Cathode: Lead metal

40
Q

How do determine the Method of Extraction?

A
  • The position of the metal on the reactivity series determines the method of extraction
  • Higher placed metals (above carbon) have to be extracted using electrolysis as they are too reactive and cannot be reduced by carbon
  • Lower placed metals can be extracted by heating with carbon which reduces
  • Electrolysis is very expensive as large amounts of energy are required to melt the ores and produce the electrical current
  • The reactivity series of metals is shown below with the corresponding method of extraction
41
Q

How is Aluminium Extracted?

A

Raw Materials:

  • Aluminium Ore (bauxite)
  • Cryolite (sodium aluminium fluoride)

Explanation:

  • The bauxite is first purified to produce aluminium oxide, Al2O3
  • Aluminium oxide has a very high melting point so it is first dissolved in molten cryolite producing an electrolyte with a lower melting point, as well as a better conductor of electricity than molten aluminium oxide
  • This reduces the costs considerably making the process more efficient
  • The electrolyte is a solution of aluminium oxide in molten cryolite at a temperature of about 1000 °C
  • The molten aluminium is siphoned off from time to time and fresh aluminium oxide is added to the cell
  • The cell operates at 5-6 volts and with a current of 100,000 amps
  • The heat generated by the huge current keeps the electrolyte molten
  • A lot of electricity is required for this process of extraction which is a major expense
  • The overall equation is:

2Al2O3 (l) ⟶ 4Al (l) + 3O2 (g)

  • Some of the oxygen produced at the positive electrode then reacts with graphite (carbon) electrode to produce carbon dioxide gas:

C (s) + O2 (g) ⟶ CO2 (g)

  • This causes the carbon anodes to burn away, so they must be replaced regularly
42
Q

How are Inert Electrodes used in Electrolysis?

A
  • Aqueous solutions will always have water (H2O)
  • In the electrolysis of aqueous solutions, the water molecules dissociate producing H+ and OH ions:

H2O ⇌ H+ + OH

  • These ions are also involved in the process and their chemistry must be considered
  • We now have an electrolyte that contains ions from the compound plus ions from the water
  • Which ions get discharged and at which electrode depends on the relative reactivity of the elements involved
  • Concentrated and dilute solutions of the same compound give different products
  • For anions, the more concentrated ion will tend to get discharged over a more dilute ion
43
Q

What happens at the Positive electrodes during Electrolysis?

A

Positive Electrode (anode)

  • Negatively charged OH ions and nonmetal ions are attracted to the positive electrode
  • Either OH or nonmetal ions will lose electrons and oxygen gas or the gas of the nonmetal in question is released e.g. chlorine, or bromine
  • Therefore at the anode, oxygen gas will be produced unless the ionic compound contains halide ions, in which case the halogen will be produced
44
Q

What happens at the Negative electrodes during Electrolysis?

A

Negative Electrode (cathode)

  • Positively charged H+ and metal ions are attracted to the negative electrode but only one will gain electrons
  • Either hydrogen gas or the metal will be produced
  • If the metal is above hydrogen in the reactivity series, then hydrogen will be produced and bubbling will be seen at the cathode
  • This is because the more reactive ions will remain in solution, causing the least reactive ion to be discharged.
  • Therefore at the cathode, hydrogen gas will be produced unless the positive ions from the ionic compound are less reactive than hydrogen, in which case the metal is produced
45
Q

How do you determine what gas is produced?

A

Determining what Gas is Produced

  • The gas produced can be tested to determine its identity
  • If the gas produced at the cathode burns with a ‘pop’ with a lighted splint then the gas is hydrogen
  • If the gas produced at the anode relights a glowing splint dipped into the gas then the gas is oxygen
  • The halogen gases all produce their own colours (bromine is red-brown, chlorine is yellow-green)
46
Q

Required Practical: To investigate what happens when aqueous solutions are electrolysed using inert electrodes

A

Hypothesis:

A metal will be produced at the negative electrode because metal ions are positive

Materials:

  • Test tubes
  • Electrolyte solutions
  • 100 cm3 beaker
  • Stand and clamp
  • Two carbon rod electrodes
  • Two crocodile / 4 mm plug leads
  • Low voltage power supply
  • Blue litmus paper

Practical Tip:

Make sure the test tubes do not cover the electrodes completely and fall to the bottom of the cell or the conductivity will fall considerably and the rate of electrolysis will be very slow

Method:

  1. Set up the apparatus as shown in the diagram
  2. Add the aqueous solution to the beaker
  3. Add two graphite rods as the electrodes and connect this to a power pack or battery
  4. Turn on the power pack or battery and allow electrolysis to take place
  5. Record the results in a suitable table (see below) and repeat for another solution, checking the electrodes in between runs to see if any metal has been deposited
  6. The following aqueous solutions are suitable for this investigation: copper chloride, copper sulfate, sodium chloride, sodium bromide, sodium nitrate
  7. The gases produced can be collected in the test tubes to be tested later

Results: Record your results in a suitable table:

Electrolyte: Dilute NaCl

Observation at Anode and gas test results: Effervescence, no colour, split relights therefore gas is O2.

Observation at Cathode and gas test results: Effervescence, no colour, squeaky pop therefore gas is H2.

Evaluation:

The gases and corresponding tests are:

  • Hydrogen – lighted splint goes out with a squeaky pop
  • Oxygen – a glowing splint relights
  • Chlorine – damp blue litmus paper turns red and is then bleached white

Conclusion:

Describe how the results obtained compare with the expected results based on the hypothesis

47
Q

What is the Half equation at the electrodes of the Electrolysis of molten lead(II)bromide

A

Electrolysis of molten lead(II)bromide

  • In the electrolysis of molten lead(II) bromide the half equation at the negative electrode (cathode) is:

Pb2+ + 2e ⟶ Pb

  • At the positive electrode (anode) bromine gas is produced by the discharge of bromide ions:

2Br- – 2e⟶ Br2

OR

2Br- ⟶ Br2 + 2e

48
Q

What is the Half equation at the electrodes of the Electrolysis of aluminium oxide?

A
  • Aluminium ions are discahrged at the negative electrode (cathode) and the aluminium is collected at the bottom of the cell:

Al3+ + 3e ⟶ Al

  • At the positive electrode (anode) oxygen gas is produced:

2O2- – 4e⟶ O2

OR

2O2- ⟶ O2 + 4e

  • Half equations illustrate the transfer of electrons during a chemical process as they provide a more detailed picture of the redox processes taking place
  • Half equations combine to give the ionic equation for an electrolytic cell.
  • The example below illustrates how this is done for the sodium chloride: