C6 The chemical basis of drug action 3 Flashcards

(32 cards)

1
Q

what does omeprazole inhibit and how?

A
  • inhibits the proton pump in parietal cells
  • binds irreversibly to the proton pump
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2
Q

which is more basic: pKa 4 or 0.79?

A
  • pKa 4 is more basic
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3
Q

the pKa of omeprazole is 4. describe the percent ionisation at pH 2, 3, 4, 5 and 6.

A
  • pH 2 = 99% therefore largely charged and minimally absorbed
  • pH 6 = 1% and maximally absorbed
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4
Q

compare and explain absorption differences of omeprazole in the stomach and duodenum

A
  • stomach: high extent of ionisation and minimal absorption
  • duodenum: lower pH, less ionisation and more absorption
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5
Q

describe the pathway of omeprazole absorption starting at the stomach

A
  • stomach
  • duodenum
  • blood
  • parietal cells (extracellular space, adjacent to proton pumps)
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6
Q

explain what occurs at the stomach stage of omeprazole absorption

A
  • pH 1-2
  • protected by enteric coating
  • remains as prodrug
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7
Q

explain what occurs at the duodenum stage of omeprazole absorption

A
  • pH 6-6.5
  • unchanged
  • easily absorbed
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8
Q

explain what occurs at the blood stage of omeprazole absorption

A
  • pH 7.4
  • uncharged
  • systemic circulation
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9
Q

explain what occurs at the parietal cells stage of omeprazole absorption

A
  • pH ≤ 2
  • ionised
  • forms active drug
  • reacts with target
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10
Q

explain the ion trapping of omeprazole

A
  • omeprazole crosses into parietal cell (extracellular) when unionised
  • then becomes ionised in the acidic environment of the parietal cell
  • can then not cross back to intracellular environment
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11
Q

what kind of drug is omeprazole? (not PPI)

A

prodrug (needs to be activated to become the active drug species)

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12
Q

describe omeprazole in acid

A
  • unstable
  • undergoes a reaction to produce the active drug molecule
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13
Q

what does activated omeprazole form?

A
  • covalent (disulphide) bond with an accessible cysteine amino acid in the proton pump
  • disulphide bridge forms between cysteine residue in proton pump and activated omeprazole to block proton pump
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14
Q

explain the stereochemistry of omeprazole

A
  • sulphur can be a chiral centre which allows for S and R configurations
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15
Q

what are me-too drugs?

A

similar to structural similarity in H2 receptor antagonist drugs

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16
Q

what is the chemical equation for the 13C urea breath test?

17
Q

what is the urease enzyme produced by? what does it do?

A
  • H. pylori
  • protects bacterium from acid by producing NH3 which neutralises stomach acid
18
Q

compare 12C and 13C

A
  • both naturally occurring
  • both non-radioactive isotopes of carbon
  • slightly higher stomach pH from produced urea allows bacteria to survive
19
Q

track the isotopic carbon in the equation for the urea breath test and describe the start and beginning

20
Q

how is the 13C enriched carbon dioxide detected?

A
  • 13CO2 : 12CO2 ratio measured in both breath samples obtained
  • mass spectrometry
  • infrared spectroscopy
  • 2 above techniques can detect small difference in mass
21
Q

what difference is detected between the 1st and 2nd breath samples in the urea breath test?

A

to see if 13C carbon dioxide proportion has increased

22
Q

explain the hydrolysis of urea by the equations (3 equations). also state where the product is absorbed into and how its eliminated

23
Q

what is a common feature of NSAIDs?

A

weak, organic acids

24
Q

in this image, 2 NSAIDs are shown. describe them at physiological pH

A

these will be essentially completely ionised

25
explain the interactions that NSAIDs have and what they target / inhibit
- reversible ionic interaction - NSAIDs target COX enzyme and inhibit it via the ionic interaction - NSAIDs inhibit COX-1 and COX-2 by preventing binding of arachidonic acid
26
describe some structural features of NSAIDs involved in binding
27
describe what happens to arachidonic acid and COX enzymes
28
which NSAID is the exception to the reversible ionic interaction?
- aspirin - irreversible inhibition instead
29
describe the nucleophilic substitution reaction in the irreversible inhibition by aspirin
30
describe the hydrolysis of aspirin
- nucleophilic substitution - water is the nucelophile - acid catalysed - addition-elimination reaction
31
why are there delta - and + present in the mechanism for aspirin hydrolysis?
- due to electronegativity of oxygen in carbonyl group - in an acidic environment, the electrons in this dipole are happy to accept protons which makes the carbon more delta + - therefore nucleophiles are more likely to attack this carbon due to protonation of oxygen atom
32
describe the mechanism image for aspirin hydrolysis with curly arrows