Capicitor And Capicitance

Question 2

What happens when dielectric is introduced with battery connected?

Answer 2

Potential V remains constant
V = V0
C increases
Q increases
Electric field E remains constant

Question 3

What happens when battery is off and dielectric is introduced

Answer 3

Potential V decreases V = Q/C
Charge Q remains constant (Q = Q0)
Capacity increases C= KC0
Electric field E decreases E = V/D