Carbohydrates Flashcards

(23 cards)

1
Q

List three different roles of sugars in biology

A
  1. Carbohydrates are an important source of energy/stored fuels
    - Glycogen granules (dark patches) in a liver cell
  2. Carbohydrates provide structure to cells and organisms
    - Cellulose in plants and chitin in arthropods
  3. Cell Biology
    - Major component of the cell surface
    - Important in influencing the function of proteins
    - Important in specific recognition interactions
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2
Q

Provide examples of different roles of carbohydrates in biology

A

> Information molecules (The Sugar Code)
- Carbohydrates have enormous structural diversity
Cell surface sugars are important in:
- Cell-cell adhesion
- Bacteria adhesion
- Virus attachment to host cells
- Binding of toxins to cell surface
- Genes encode proteins – not sugars
- How are glycoconjugates synthesised

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3
Q

Explain the difference between aldose and ketose sugars.

A

Monosaccharides
- basic unit of carbohydrates
- are aldehydes or ketones that have two or more hydroxyl groups

> Aldose because it contains an aldehyde group
Glyceraldehyde has a single assymetric (chiral) carbon atom
- Two sterioisomers D- and L-glyceraldehyde are enantiomers or mirror images of each other
- most naturally occuring sugars belong to D-series

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4
Q

Explain the structural basis of the interconversion between the α and β anomers of cyclised sugars

A
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5
Q

Draw the Fischer and Haworth projections of D-glucose.

A
  • Provide a clear and simple view of the stereochemistry at each carbon centre
  • Horizontal lines project out of the plane
  • Vertical lines project behind the plane
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6
Q

Draw and recognise other sugars, based on their similarity to D-glucose.

A

D-glucose
- All OH on right hand side apart from C3

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7
Q

Be able to draw and/or identify glycosidic linkages in linear and branched oligosaccharides.

A

Linear Oligosaccharide
A linear oligosaccharide is a short chain of monosaccharide units connected in a straight, unbranched sequence by glycosidic bonds.

All sugars are connected end-to-end.

Each monosaccharide (except the ends) is linked to two others.

Example: Maltotriose (glucose–glucose–glucose via α(1→4) linkages).

Branched Oligosaccharide
A branched oligosaccharide contains monosaccharide chains that diverge from a central core, forming branch points.

At least one sugar is attached to more than two others.

Branched points usually occur at hydroxyl groups like C6 of a glucose unit.

Example: N-linked glycan chains on glycoproteins, or the branching in glycogen.

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8
Q

Identify reducing and non-reducing sugars in an oligosaccharide.

A

The redox activity of a sugar — its ability to act as a reducing agent — is specifically associated with the hemiacetal (or hemiketal) group at the anomeric carbon, not the acetal (or ketal) formed during glycosidic bond formation.

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9
Q

Explain how the linkages between glucose units in cellulose and glycogen give rise to their different properties.

A

Cellulose
- beta (1,4) bonds, homopolymer of glucose, has intrachain and interchain H bonds so forms stable and strong supramolecular fibres leading to insoluble molecule great for structure and rigiditiy of plant cell walls

Glycogen
- alpha (1,4) bonds, homopolymer of glucose, hollow open helix, branched, storage molecule

Cellulose’s β(1→4) linkages → straight chains → strong intermolecular H-bonding → tough, insoluble fibers.

Glycogen’s α(1→4) and α(1→6) linkages → flexible, branched chains → compact and easily mobilized for energy.

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10
Q

Draw the structural difference between cellulose and chitin.

A
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11
Q

List the amino acids that can act as glycosylation sites on proteins.

A

Carbohydrate chains can be attached to proteins to form glycoproteins
- Carbohydrate groups are covalently attached to many proteins
- Called glycoproteins
- Short oligosaccharide chains
- Many glycoproteins and glycolipids are components of cell membranes
- Oligosaccharides play important functions in recognition (e.g. cell adhesion)

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12
Q

Recognize N-linked and O-linked protein glycosylation.

A

Carbohydrates link to proteins in two ways:
1. Via Asparagine residues (N-glycans)
- sugars are linked to the amide side chain of asparagine
- therefore called N-linked oligosaccharides or N-glycans

  1. Via Serine or Threonine residues (O-glycans)
    - Sugars are linked to the oxygen atoms in the side chain of serine or threonine residues (O-linkage)
    - Therefore, called O-linked oligosaccharides or O-glycans

Sugar –> amino acid link –> type of glycosylation –> bond –> location

N-acetylglucosamine –> Asn –> N-glycan –> N glycosidic bond to amide nitrogen –> ER
O-acetylgalactosamine –> Thr/Ser –> O glycosidic bond to hydroxyl oxygen - Golgi

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13
Q

Describe the general reaction of a glycosyl transferase.

A

Specific enzymes are responsible or oligosaccharide assembly
- Nucleotide-monosaccharide (UDP-Glc) + Acceptor (carb) –> (glyosyl (sugar) transferase) –> monosaccharide-acceptor + nucleotide
Note: monosaccharide is transferred from the nucleotide sugar to the non-reducing end of the carbohydrate acceptor

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14
Q

Describe the structural difference between A, B and O group blood antigens

A
  • Human ABO blood groups are carbohydrate antigens
  • Carbohydrates are attached to glycoproteins (and glycolipids) on surfaces of red blood cells
  • ABO blood group antigens are glycosphingolipids
  • A and B blood group antigens differ from O antigen by one extra monosaccharide

All blood groups antigens have:
- Ceramide group consisting of sphingosine and fatty acid
- A chain of monosaccharides

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15
Q

Identify/draw A, B and O antigens.

A
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16
Q

Predict the blood group type of an individual, based on the functional properties of the ABO glycosyltransferase alleles they have inherited.

A

Glycosyltransferases and blood groups
- There is a single gene controlling the synthesis of ABO blood groups
- The ABO blood group gene encodes a glycosyltransferase (enzyme)
- Three forms (or alleles) of this exist in the human population
- An individual has one allele inherited from their mother and one allele inherited from their father

  • The single gene controlling ABO blood groups encodes a glycosyltransferase

o A allele: encodes an active glycosyltransferase
 GalNAc transferase
o B allele: encodes an active glycosyltransferase
 Gal transferase
o O allele: encodes a dead enzyme
 No active transferase

17
Q

Explain ABO blood group incompatibility.

A
  • The only difference between blood group A and B antigens Is the substitution of C2 of the terminal galactose
  • Antibodies are highly specific and very small chemical differences in oligosaccharide structure binding change affinity
  • Antibodies to A and B group antigens occur naturally in individuals
18
Q

Predict the outcome of blood transfusions.

A
  • antibodies will cross link the “foreign” RBCs (agglutination)
  • incompatibility leads to hemolysis and can be deadly
19
Q

Describe, with an example, the interaction between a C-type lectin and a carbohydrate.

A
  • Antibodies are not the only proteins which can recognise oligosaccharides
  • Lectins
    o Broad family of proteins that recognise carbohydrates
    o Animals, plants and micro-organisms
    o One large class of lectins are known as C-type lectins
  • C-type lectins- How do they recognise carbohydrate?
    o C type for calcium binding
    o A common 120 amino acid domain responsible for carbohydrate binding
    o Calcium acts a bridge between the protein and the sugar through direct interaction with sugar hydroxyl groups

o Different C-type lectins have different carbohydrate-binding specificities
o Changes in residues that interact with the sugar alter the carbohydrate-binding specificity of the lectin

  • C-type lectins and cell-cell adhesion
    o Selectins are C-type lectins
    o Are involved in cell-cell adhesion
    o Bind white blood cells to sites of injury and allow movement of cells from bloodstream to site of infection
20
Q

Explain how the antiviral drug Relenza interferes with the influenza life cycle.

A

Many animal viruses attach to host cells via carbohydrate
- To infect a host cell, viruses need to bind to receptors on the cell surface
- In some cases these receptors are carbohydrates
- For example, influenza virus recognise sialic acid residues present on cell surface glycoproteins

 Influenza virus binds to sugar residues on the host cell surface
o The sugar-binding site of sialic acid binding proteins has been the target of “carbohydrate-based drug design”
o Influenza antivirals
o The anti-flu drug “Relenza” is a sialic acid analogue

  • Relenza inhibits the enzyme neuriminidase from flu virus
21
Q

Use the GLUT1 glucose transporter as an example of passive transport by an integral membrane protein.

22
Q

Describe the model for conformational change allows GLUT 1 to able to translocate glucose across membranes.

A

Glucose uptake occurs by GLUT transporters
- Two conformational states – T1 and T2
- As the concentration of glucose goes up outside the cell the rate of transport gets faster and then plateaus

23
Q

Be able to rationalize the kinetic properties of GLUT family transporters with their tissue distribution and functional role.