CGS 2021 Flashcards

1
Q

The woman is infertile. With reference to Fig. 1.1 (collapsed oviduct wall), explain why this is so. [2] (CGS 2021)

A
  • The oviduct is blocked/ occluded/ sealed/ closed off [1]
  • Fertilisation cannot occur as ovum cannot be moved to meet/ fuse with the sperm due to the blocked oviduct. [1]
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2
Q

A woman’s progesterone levels rise after day 14 and peak around day 24. Suggest and explain a time range during the menstrual cycle when implantation would be likely to be most successful. [3] (CGS 2021)

A
  • Between day 21-24; [1]
  • Progesterone functions to maintain the thickness of the uterine lining; [1]
  • During this period, progesterone level is increasing towards peak, indicating uterine lining is most likely the thickest. [1]
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3
Q

Explain one way in which the structure of the villus is adapted for its function. [2] (CGS 2021)

A

ANY one of below
- Epithelium of the villus have numerous microvilli; [1] to increase surface area to volume ratio for faster absorption of digested
food [1].
- Epithelium/ wall of villus is one cell thick [1] to reduce diffusion distance for faster absorption of digested food [1].
- Contains a lacteal which continually
transports fats away from ileum [1] to maintain a steep concentration gradient for faster absorption of fats [1].
- Well-supplied with blood capillaries which continually transports digested food away from duodenum [1] to maintain a steep concentration gradient for faster absorption
of digested food [1].

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4
Q

Adults who suffer from coeliac disease are easily fatigued.
With reference to Fig. 2.1 and Fig. 2.2, explain how coeliac disease can cause fatigue in adults. [2] (CGS 2021)

A

The villi in person with coeliac disease is shorter, thus has smaller surface area to volume ratio [1].
Less glucose absorbed into bloodstream, resulting in less respiration, releasing less energy, hence causing fatigue [1]

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5
Q

Toxic chemicals from the soil slow down the rate of respiration. Plants that absorb these toxic chemicals do not grow as well as those growing in toxin-free soils.
Explain why. [3] (CGS 2021)

A
  • When the rate of respiration slows down, less energy is released resulting in less active transport [1].
    Less active transport results in less translocation of sucrose and amino acids from leaves to the rest of the plant for growth [1].
  • Less respiration results in less energy for cell activities such as photosynthesis to produce
    glucose, reducing plant growth [1].
  • Less mineral ions absorbed/ ions absorbed more slowly at the roots by active transport [1]. Less nitrate ions causes less amino acids/ protein results in less protoplasm/ growth;[1]
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6
Q

Explain why transpiration rate increased when the plant was placed next to the fan. [3] (CGS 2021)

A

The wind blows away the water vapour that accumulates outside the leaf. [1]
This causes a steeper water vapour
concentration gradient
between the inside of the leaf and the atmosphere. [1]
This allows water vapour to diffuse out of the leaf faster [1], increasing rate of transpiration.

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7
Q

Explain how wilting reduces the rate of transpiration. [1] (CGS 2021)

A

The leaf folds up, reducing exposed surface area to reduce rate of transpiration OR
stomata closes, reducing rate of
transpiration. [1]

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8
Q

Describe two ways in which a flower is adapted for pollination by the bee. [2] (CGS 2021)

A

Has a large and conspicuous petal [1]
Non-pendulous anther and compact stamen; [1]
Non-feathery and compact stigma; [1]

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9
Q

The bee visited this flower after leaving another flower of the same plant.
Identify the type of pollination involved.[1]

A

Self-pollination

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9
Q

Species P relies on cross-pollination.
Describe two ways in which flowers from species P may be adapted to increase the likelihood of pollination. [2]

A

Any [2]
· Plants bear either male or female
flowers.
· Anthers and stigmas in the same plant mature at different times.
· Stigmas are situated far away from the anthers in the same plant.
· Pollen grains of a flower have no
fertilizing effect on the stigmas of the same plant.

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10
Q

The average concentration factor of urea in urine of a healthy individual is x 60.0.
Suggest an explanation for the difference in his concentration factor of urea in urine from that of a healthy individual. [2]

A

High protein diet/ protein-rich diet/ meals [1]
Higher amount of/ More excess amino acids are deaminated to produce more urea [1]

(i rejected low water intake as it only specifies urea.)

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11
Q

When the blood clot blocks the vessel in the lungs, it would eventually lead to the death of the cells in the lungs. Explain why. [2]

A

Less/ No oxygen will be transported to these cells and cells will undergo less/ no aerobic respiration [1]
Less/ No energy is released for cellular activities [1]

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12
Q

Explain how the lipid coating on capsules ensures that the enzymes are not released until the capsule reaches the small intestine. [2]

A

There is no lipase produced / found [1] in stomach / mouth / before small intestine [1]
OR
Lipase only produced / found [1] in the by epithelial cells / intestinal juice in the small intestine [1]

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13
Q

In an experimental set-up, a plant is watered with water radioactively labelled with isotope 18O. The plant is then placed in a sealed chamber and the radioactivity of 18O in the chamber is measured over time.
Explain the change in radioactivity in the chamber as shown in Table 8.1. [4]

A
  1. Radioactive water (R: solution) enters root hair cell by osmosis and transported upwards in xylem; [1]
  2. Moves out of xylem to mesophyll cells; [1]

[Photosynthesis] Radioactive water used for photosynthesis (R: water is photolysed) ; [1]
Radioactive oxygen gas produced and
diffuses out of leaves; [1]
OR
[Transpiration] Thin film of moisture around spongy mesophyll evaporates; [1]
Radioactive water vapour diffuses out of leaves [1]

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14
Q

Compare and contrast between the process of mitosis and meiosis. [4]

A

Similarities (at least [1])
· Both involve nuclear division
· Both form / produce new daughter cells
· Both involve prophase, metaphase,
anaphase and telophase
R: both involve metaphase/ only one parent
cell/ centrioles/ doubling of chromosome number

differences:
- number of nuclear divisions
- number and type of daughter cells (diploid/haploid)
- genetically identical?
- crossing over of alleles?
- occurs in?
- pairing of homologous chromosomes?
- independent assortment?`

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15
Q

State how meiosis can lead to variation in offspring. [4]

A
  • In prophase I, crossing over [1]
  • between non sister chromatids of homologous chromosomes occur, resulting in different combinations of alleles. [1]
  • In metaphase I, independent assortment [1]
  • of chromosomes occur, resulting in gametes having different combinations of chromosomes/ different pairing of chromosomes/ random arrangement of chromosomes.[1]
16
Q

Describe the relationship between genes, DNA and chromosomes. [4]

A
  • DNA is the chemical that makes up the genetic material in living organisms. DNA is organised into highly coiled (condensed) structures called chromosomes [1] in the nucleus of cells.
  • A gene is a sequence of nucleotides and it is made up of a small segment of DNA [1] in a
    chromosome. [1]
17
Q

Describe how homozygous and heterozygous differ [1]

A

identical alleles versus different alleles [1]

18
Q

Describe how phenotype and genotype differ [1]

A

A trait expressed in outward appearance (OR expressed and can be seen) versus genetic combination (OR combination of alleles) in an individual [1]
R: genetic makeup

19
Q

Describe how gene and allele differ [1]

A

unit of inheritance versus alternative form of a gene [1]