Ch.6 (not Complete)

Question 1

Directly proportional to radiation quantity exiting the x-ray tube
Inversely related to exposure time to maintain exposure to image receptor (IR)

Answer 1

Milliamperage (mA)

Question 2

Directly proportional to radiation quantity exiting the x-ray tube
Inversely related to mA to maintain exposure to IR

Answer 2

Exposure time (TIME)

Question 3

Directly related to radiation quality and quantity exiting the x-ray tube
Inversely related to radiographic contrast

Answer 3

Kilovoltage (kVp)

Question 4

Milliamperage and exposure time have a _______ proportional relationship when discussing quality

Answer 4

Direct

Question 5

Increasing mA = _____ time = _______ quality

Answer 5

Increase, increase

Question 6

**mAs is INVERSELY related to exposure but DIRECTLY related to quantity

Answer 6

!!!

Question 7

Increasing or decreasing the mA results in a _____ change in mAs.

Answer 7

Proportional

Question 8

T or F - MAs does not control brightness

Answer 8

TRUE

Question 9

In order to maintain exposure, by increasing your mA you will need to ______ time

Answer 9

Decrease

Question 10

MA and exposure time have an _____ proportional relationship when maintaining mAs.

Answer 10

Inverse

Question 11

Increasing kVp= ______ penetration = ______ absorption = _______ contrast

Answer 11

Increases, decreases, decreases

Question 12

Increasing kVp _____ subject contrast

Answer 12

Decreases

Question 13

Decreasing kVp ______ subject contrast

Answer 13

Increases

Question 14

What is the 15% rule?

Answer 14

By increasing your kVp by 15%, it is the equivalent of doubling your MAs.

Question 15

Increase for 15% rule

Answer 15

1.15

Question 16

Decrease by 15% rule

Answer 16

0.85

Question 17

How to maintain exposure to the IR

Answer 17

1. Increase mA and proportionally decrease time
2. Increase time and proportionality decrease
3. Increase kVp 15% and decrease MAs by half
4. Decrease kVp 15% and increase MAs by two times

Question 18

Image brightness is _______ on MAs and kVp

Answer 18

Not dependent

Question 19

Image contrast is _________ on kVp

Answer 19

Not dependent

Question 20

Image brightness and image contrast are both

Answer 20

Dependent on the computer

Question 21

With too little MAs and/or kVp, computer processing will adjust image brightness and contrast BUT

Answer 21

Quantum noise is visible, therefore the image will need to be repeated.

Question 22

For digital, using _____kVp and _____ MAs values.

Answer 22

Higher, lower

Question 23

With too much kVp/mAs, computer processing with adjust the image brightness and contrast BUT

Answer 23

The patient is overexposed.

Question 24

Increasing MAs= ______ noise

Answer 24

Decrease

Question 25

Secondary factors include

Answer 25

- focal spot size - SID - OID - Part/IR alignment - Grids - Beam restriction - generator output - tube filtration - compensating filters - patient factors

Question 26

The size of the focal spot affects ______ and _______ _______ recorded in the image.

Answer 26

Unsharpness and spatial resolution

Question 27

Increasing focal spot size, unsharpness ______ and spatial resolution _______

Answer 27

Increases, decreases

Question 28

Decreasing focal spot size _______ unsharpness and _______ spatial resolution.

Answer 28

Decreases, increases

Question 29

SID and radiation intensity are ______ related.

Answer 29

Inversely

Question 30

Changing the SID requires a change in ____ to maintain consistent radiation exposure to the image receptor

Answer 30

MAs

Question 31

SID affects _________ and __________

Answer 31

Distortion and recorded detail/spatial resolution

Question 32

Increasing SID= ______ magnification and _____ spatial resolution

Answer 32

Decrease, increase

Question 33

Decreasing SID= ______ magnification= ________ spatial resolution

Answer 33

Increases, decreases

Question 34

What is the formula for the direct square law?

Answer 34

MAs2=mAs1x(D2/D1)^2

Question 35

What is the formula for exposure maintenance?

Answer 35

MAs1/mAs2= (SID1/SID2)^2

Question 36

OID affects

Answer 36

Radiation intensity reaching the IR Amount of scatter radiation reaching the IR Magnification Spatial Resolution (Increase mag.=decrease SR)

Question 37

Increasing OID will have what effect on beam intensity ?

Answer 37

It will decrease beam intensity, hence decreasing exposure. Once exposure to the IR is decreases, you will need to INCREASE MAS

Question 38

An ________ will decrease the intensity of radiation and scatter reaching the IR without the use of a grid.

Answer 38

Air Gap

Question 39

Increasing OID=______ IR exposure=______contrast and magnification= _______ SR

Answer 39

Decreases, increases, decreases

Question 40

Decreasing OID= ________ IR exposure= _______ contrast and magnification= _______ SR

Answer 40

Increases, decreases, increases

Question 41

What is the formula to find the magnification factor?

Answer 41

MF= SID/SOD MF= Image size/Object size

Question 42

What is the formula to solve for SOD?

Answer 42

SOD=SID-OID

Question 43

What is the best magnification factor?

Answer 43

1

Question 44

Shape distortion can occur from any misalignment of the CR alongside these three factors:

Answer 44

1. X-ray tube 2. Part being radiographed 3. IR

Question 45

Improper CR alignment causes shape distortion, as well as (ON TEST)

Answer 45

1. Incorrect SID 2. Off centered CR 3. Angled CR

Question 46

What effect do grids have on spatial resolution ?

Answer 46

Increases spatial resolution

Question 47

Less scatter=______ contrast

Answer 47

Increase

Question 48

When using the magnification factor formula, what formula would be used in order to find the object size?

Answer 48

Obj. Size= image size/MF

Question 49

What is the formula for Grid Conversion?

Answer 49

Mas1/mAs2=grid ratio 1/grid ratio 2

Question 50

What is the formula for grid ratio ?

Answer 50

Grid ratio=height of lead strips/distance btw strips

Question 51

The more effective the grid, the _______ the mAs

Answer 51

GREATER