Chapter 16: the Molecular Basis of Inheritance Flashcards

1
Q

What are the two chemical components of chromosomes?

A

DNA and Protein

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2
Q

DNA replication allows genetic information to be inherited from a parent cell to daughter cells by_____________ and from generation to generation by _____________.

A

mitosis
starting with meiosis

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3
Q

Why did researchers originally think that protein was the genetic material?

A

Until the 1940s, the case for proteins seemed stronger: Biochemists had identified proteins as a class of macromolecules with great heterogeneity and specificity of function, essential requirements for the hereditary material. Moreover, little was known about nucleic acids, whose physical and chemical properties seemed far too uniform to account for the multitude of specific inherited traits exhibited by every organism.

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4
Q

Define transformation.

A

Transformation is a change in genotype and phenotype due to the assimilation of external
DNA by a cell. When the external DNA is from a member of a different species, transformation results in horizontal gene transfer.

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5
Q

Distinguish between the virulent and nonvirulent strains of Streptococcus pneumoniae studied by Frederick Griffith

A

The S (smooth) strain can cause pneumonia in mice; it is pathogenic because the cells have an outer capsule that protects them from an animal’s immune system. Cells of the R (rough) strain lack a capsule and are nonpathogenic.

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6
Q

Summarize the experiment in which Griffith became aware that hereditary information could be transmitted between two organisms in an unusual manner.

A

Frederick Griffith studied two strains of the bacterium Streptococcus pneumoniae. To test
for the trait of pathogenicity, Griffith injected mice with the two strains independently, and
then injected a mixture of nonpathogenic R bacteria that had been incubated with
heat-killed pathogenic S bacteria.

Griffith concluded that the living R bacteria had been transformed into pathogenic S bacteria by an unknown, heritable substance from the dead
S cells that allowed the R cells to make capsules.

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7
Q

What was transferred from the heat killed S strain to the living R strain in Griffith’s experiment in 1928?

A

DNA - that controlled the production of the lethal protein in the S strain

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8
Q

What did Oswald Avery, McCarty, and MacLeod determine to be the transforming factor?

A

DNA

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9
Q

What is a bacteriophage?
How is it structured?

A

These viruses are called bacteriophages (meaning “bacteria-eaters”), or phages for short. Viruses are much simpler than cells. A virus is little more than DNA (or sometimes RNA) enclosed by a protective coat, which is often simply protein. To produce more viruses, a virus must infect a cell and take over the cell’s metabolic machinery.

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10
Q

Describe the means by which Hershey and Chase established that only the DNA of a phage
enters an E. coli cell. What conclusions did these scientists draw based on these observations?

A

Separate samples of the nonradioactive E. coli cells were allowed to be infected by the
protein-labeled and DNA-labeled batches of T2.

The researchers then tested the two samples shortly after the onset of infection to see which type of molecule—protein or DNA—had entered the bacterial cells and would therefore be capable of reprogramming them. Hershey and Chase found that the phage DNA entered the host cells but the phage protein did not. Hershey and Chase concluded that the DNA injected by the phage must be the molecule carrying the genetic information that makes the cells produce new viral DNA and proteins.

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11
Q

What are Chargaff’s rules?

A

Chargaff’s rules (base pairing rules) are:
1. The base composition varies between species.
2. Within a species, the number of adenines approximately equaled the number of thymines, and the number of guanines approximately equaled the number of cytosines

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12
Q

List the three components of a nucleotide.

A

Phosphate, sugar (deoxyribose or ribose), nitrogenous base

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13
Q

Who are the two men who built the first molecular model of DNA and shared the 1962
Nobel Prize for the discovery of its structure?

A

James Watson and Francis Crick

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14
Q

What was Rosalind Franklin’s role in the discovery of the double helix?

A

Rosalind Franklin, a very accomplished X-ray crystallographer, conducted critical experiments resulting in the photograph that allowed Watson and Crick to deduce the double-helical structure of DNA. She took the first X-ray defraction photo of DNA. Photo 51

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15
Q

Distinguish between the structure of pyrimidines and purines.

A

Purines—adenine (A) and guanine (G)—are characterized by a six-membered ring fused to a five-membered ring.
Pyrimidines—cytosine (C), thymine (T), and uracil (U)—are characterized by a
six-membered ring.

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16
Q

Explain why adenine bonds
only to thymine

A

Adenine bonds only with thymine because adenine is a purine, and thymine is a pyrimidine. Always pairing a purine with a pyrimidine results in a uniform diameter in the double helix.
Additionally, each base has chemical side groups that can form hydrogen bonds with the appropriate partner. Adenine can form two hydrogen bonds with thymine and only thymine.

17
Q

How did Watson and Crick’s model explain the basis for Chargaff’s rules?

A

Watson and Crick began building models of a double helix that would conform to the
X-ray measurements and what was then known about the chemistry of DNA, including
Chargaff’s rule of base equivalences. Through trial and error, Watson and Crick deduced that the nitrogenous bases of the double helix are paired in specific combinations—adenine (A) with thymine (T), and guanine (G) with cytosine (C)—and they reflected these findings in their model. Whenever one strand of a DNA molecule has an A, the partner strand
has a T. When a G is in one strand it is always paired with a C in the complementary
strand. Therefore, in the DNA of any organism, the amount of adenine equals the amount
of thymine, and the amount of guanine equals the amount of cytosine - helping to explain Chargaff’s rules.

18
Q

Explain what is meant by 5ʹ and 3ʹ ends of the nucleotide.

A

The two free ends of the polymer are distinctly different from each other. One end has a
phosphate attached to a 5’ carbon, and the other has a hydroxyl group on the 3’ carbon. We refer to these as the 5’ end and the 3’ end, respectively.

19
Q

What do we mean when we say the two strands of DNA are antiparallel?

A

Their subunits run in opposite directions.

20
Q

Fill in the blanks

A
21
Q

Name the five nitrogenous bases. Are they purines or pyrimidines?
Also indicate if the base is found in DNA, RNA, or both.

A

Adenine - Both
Thymine - DNA
Guanine - Both
Cytosine - Both
Uracil - RNA
Purines - Adenine and Guaning
Pyrimidines - Thymine, Cytosine, Uracil

22
Q

What DNA base is complementary to adenine?

A

thymine

23
Q

What DNA base is complementary to guanine?

A

Cytosine

24
Q

What did the Meselson and Stahl experiment confirm?

A

They demonstrated that E. coli replicates DNA via the semiconservative model.
It confirmed the semiconservative model.

25
Q

Define the origins of replication.

A

Site where the replication of a DNA molecule begins, consisting of a specific sequence of
nucleotides.

26
Q

Label the following image and understand each component

A
27
Q

Distinguish between the leading and the lagging strands during DNA replication.

A

The leading strand is the new complementary DNA strand synthesized continuously along
the template strand toward the replication fork in the mandatory 5’ —> 3’ direction.

The lagging strand is a discontinuously synthesized DNA strand that elongates by means of Okazaki fragments, each synthesized in a 5’–>3’ direction away from the replication
fork.

28
Q

A new DNA strand can only be synthesized in one direction. Why? What is the direction
of synthesis of the new strand?

A

Because of their structure, DNA polymerases can add nucleotides only to the free 3’ end of
a primer or growing DNA strand, never to the 5’ end. (see Figure 16.15).
The direction of synthesis of the new strand is 5’ → 3’.

29
Q

What are Okazaki fragments? How are they welded together?

A

Okazaki fragments are short segments of DNA synthesized away from the replication fork on a template strand during DNA replication. Many such segments are joined together by
the enzyme DNA ligase to make up the lagging strand of newly synthesized DNA.

30
Q

Helicase

A

untwists and separates strands at the replication fork by breaking the hydrogen bonds that hold the bases of the parent strand together.

31
Q

Single-strand binding
proteins

A

holds DNA strands apart
binds to and stabilizes single stranded DNA

32
Q

Primase

A

synthesizes RNA primer which act at the starting point for DNA synthesis.
It creates the free Hydroxyl group that DNA Polymerase III needs (3’ end)

33
Q

DNA polymerase III

A

adds DNA nucleotides to new strands (using the parent strand as a template) on 3’ end

34
Q

Topoisomerase

A

relieves strain caused by unwinding ahead of replication fork

35
Q

Ligase

A

joins DNA fragments together
covalently joins together Okazaki Fragments in the lagging DNA strand

36
Q

DNA polymerase I

A

removes RNA primer and replaces it with DNA