a. cathode
b. anode
c. rotor
d. rotating disk
Solution: a. cathode
The filament, the source of electrons during x-ray production, is located in the cathode.
REF: p.16
a. tungsten
b. rhenium
c. molybdenum
d. lead
e. nickel
Solution: a. tungsten
The cathode filament is made of tungsten.
REF: p.16
a. surrounds the anode.
b. has a positive charge.
c. has a negative charge.
d. focuses the x-ray beam.
Solution: c. has a negative charge
The focusing cup, surrounding the filament on three sides, has a negative charge, keeping the negatively charged electrons focused.
REF: p.16
a. One
b. Two
c. Four
d. An infinite number
Solution: a. One
Only one filament is energized at any one time during x-ray production.
REF: p.16
a. tungsten
b. rhenium
c. molybdenum
d. lead
e. nickel
Solution: e. nickel
The focusing cup is made of nickel.
REF: p.16
a. Saturation current
b. Space charge effect
c. mA rectification
d. Line focus principle
Solution: b. Space charge effect
The space charge effect limits the number of electrons in the space charge by preventing additional electrons from being boiled off the filament.
REF: p.24
a. anode
b. cathode
c. window
d. stream of electrons
Solution: a. anode
The anode is the positive side of the x-ray tube, and the cathode is the negative.
REF: p.17
a. 3200
b. 5000
c. 10,000
d. 20,000
Solution: c. 10,000
Rotating anodes rotate at a set speed ranging from 3000 to 10,000 revolutions per minute (rpm).
REF: p.17
a. Molybdenum
b. Tungsten
c. Rhenium
d. Graphite
e. A and B
f. A and D
Solution: f. A and D
The base of the rotating anode disk is made of molybdenum with a graphite layer.
REF: p.17
a. Focal spot
b. Focal point
c. Focal range
d. Any of the above
Solution: a. Focal spot
The focal spot is the fixed physical area on the focal track of the anode target where electrons strike.
REF: p.18
a. Stator
b. Rotor
c. Focusing cup
d. Rheostat
Solution: a. Stator
Located outside the envelope of the x-ray tube, the stator is an electric motor that turns the rotor.
REF: p.18
a. the thinnest portion of the part under the anode.
b. the thickest portion of the part under the anode.
c. the thinnest portion of the part under the cathode.
d. B and C.
Solution: a. the thinnest portion of the part under the anode.
The thinnest portion of a part should be placed under the anode, because the more intense X-rays are emitted toward the cathode end of the tube, where the thickest part should be placed.
REF: p.34
a. 100 mR per hour, measured 6 feet away
b. 10 mR per hour, measured 1 foot away
c. 1000 R per hour, measured at a distance of 4 meters
d. 100 mR per hour, measured at a distance of 1 meter
Solution: d. 100 mR per hour, measured at a distance of 1 meter
The maximum amount of leakage radiation from an x-ray tube is 100 mR per hour when measured at a distance of 1 meter.
REF: p.20
a. Photoelectric interaction
b. Bremsstrahlung interaction
c. Characteristic interaction
d. Pair production interaction
Solution: b. Bremsstrahlung interaction
Production of an x-ray photon as a result of a slowing down of the incoming electron due to the electrostatic force of the nucleus is due to a bremsstrahlung interaction.
REF: p.20
a. Photoelectric interaction
b. Bremsstrahlung interaction
c. Characteristic interaction
d. Pair production interaction
Solution: c. Characteristic interaction
Characteristic interactions involve the incident electron colliding with a K-shell electron and ejecting it from orbit. X-rays are produced as a result.
REF: p.21
a. Saturation emission
b. Thermionic emission
c. Filament transport
d. Proton emission
Solution: b. Thermionic emission
Thermionic emission is the emission of electrons (ion) as a result of heat (therm). The heating of the filament is due to the application of current.
REF: p.23
Solution: a. tube current
The tube current is the flow of electrons from cathode to anode within the tube.
REF: p.24
a. filament current
b. tube current
c. space charge
d. thermionic emission
Solution: b. tube current
mA or milliampere, is the unit of measure for the amount of current flowing from cathode to anode within the x-ray tube.
REF: p.24
a. Decrease the tube current.
b. Increase the speed of the electrons.
c. Increase the penetrability of the beam.
d. A and C.
e. B and C.
Solution: e. B and C
Increasing the kilovoltage (kVp) increases the speed of the electrons traveling between cathode and anode and results in an x-ray beam with greater penetrability.
REF: p.27
a. kVp
b. voltage ripple
c. mA
d. tube current
Solution: b. voltage ripple
The amount of variation of the voltage during an x-ray exposure is voltage ripple; it can vary from 100% to less than 1%, depending on the type of generator being used.
REF: p.28
a. Actual focal spot
b. Target focal spot
c. Filament focal spot
d. Effective focal spot
Solution: d. Effective focal spot
Based on the line focus principle, the effective focal spot size refers to the measurement of the focal spot from a point directly below the target.
REF: p.32
a. increased beam quality.
b. increased beam quantity.
c. lower average energy photons.
d. A and C.
Solution: a. increased beam quality
Beam filtration results in removing lower-energy x-ray photons, resulting in an x-ray beam with fewer photons but with a higher average energy.
REF: p.36
a. The oil in the transformer
b. The collimator mirror
c. The tube envelope
d. The oil surrounding the tube
Solution: a. The oil in the transformer
The oil in the transformer is not in the path of the x-ray beam, so it has no role in filtering the beam.
REF: p.35
a. wedge filtration.
b. HVL
c. mAs compensator.
d. TVL
Solution: b. HVL
HVL, or half value layer, is the amount of filtration needed to reduce the intensity of the x-ray beam to half of its original.
REF: p.36