Chapter 4 - DNA, RNA Flashcards

(39 cards)

1
Q

The central dogma

A

DNA -> RNA -> Protein

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2
Q

Nucleotide

A

Sugar, a phosphate, and one of four bases

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3
Q

DNA

A

Has a deoxyribose sugar and lacks an OH at carbon 2

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4
Q

Phosphodiester bridges

A

The 3’hydroxyl group of the sugar moeity of one nucleotide is joined the the 5’ group of the adjacent sugar

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5
Q

RNA

A

Is a long unbranched polymer with phosphodiester linkages. Ribose contains a 2’-hydroxyl group. RNA is uracil instead of thymine

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6
Q

Phosphodiester bridges

A

Have a negative charge. This negative charge repels nucleophilic species such as hydroxide ions, which are capable of hydrologic attack on the phosphate backbone

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7
Q

Nucleoside

A

Base and sugar joined by a glycosidic linkage

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8
Q

Nucleotide

A

Sugar, base and phosphate. Joined by ester linkages

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9
Q

Nucleotide triphosphates

A

The monomer that are linked to form RNA and DNA. The energy, ATP, released from it is used to power many cellular processes

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10
Q

Nucleotide functions

A

Energy for metabolism
Enzyme cofactors
Signal transduction

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11
Q

Nucleic acid function

A

Storage of genetic information
Transmission of genetic info (mRNA)
Processing of genetic info
Protein synthesis tRNA, rRNA

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12
Q

Double helix structure

A

Double helical structure facilitates the replication of genetic information

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13
Q

Watson Crick model of DNA

A

Right handed screw
Anti parallel strands, opposite directionality
Sugar phosphates on the outside, and purine and pyrimidines on the inside

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14
Q

Length of DNA

A

Bases are separated 3.4A
10.4 bases per turn of helix
20A diameter
Intermediate shape

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15
Q

The base pairs are held by

A

Hydrogen bonds which contribute stability in the helix due to their large numbers in a DNA molecule

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16
Q

Stacking of base pairs

A

Millions of bases together become very strong
Rings are planar.
Held by van der Waals

17
Q

For,action of the double helix

A

Is facilitated by the hydrophobic effect

Base stacking is favored by the confirmations of the somewhat rigid five ,embedded rings of th backbone sugars

18
Q

Supercooling is important because

A

Is more compact and less reactive

May hinder the capacity of the double helix to unwind

19
Q

DNA denaturing

A

Can happen by heating DNA or changing the ph.

20
Q

Melting temperature

A

When half of the DNA molecule helical structure is lost

21
Q

Helicases

A

Use chemical energy from ATP to disrupt the helix

22
Q

Denaturing

A

Covalent bonds stay intact
Hydrogen bonds are broken
Base stacking is lost

23
Q

Hydro chronic effect

A

Increase in absorption upon denaturing due to release of base pairing

24
Q

DNA is replicated by polymerase

A

Promote the formation of the bonds joining unite of the DNA backbone

25
DNA synthesis needs
Deoxynucleoside triphosphates -dATP, dGTP, dCTP, dTTP and Mg ion Preexisting DNA template Primer having a free 3’ hydroxyl
26
Nucleases
Enable DNA fidelity because it enables mismatched nucleotides
27
Polymerization is driven forward by
The hydrolysis if pyrophosphate to yield PPi
28
Where do you want to radiolabel?
In the alpha carbon
29
Reverse transcriptase
Makes viral DNA Possess several activities and catalyze the synthesis of a complementary DNA strand, the digestion of the RNA and the subsequent synthesis of the DNA strand
30
RMA polymerase
The synthesis of RNA from DNA is called Transcription and is catalyzed by the RNA polymerase enzyme
31
RNA synthesis
Does not require a primer of nuclear activity | Fidelity by base sequence studies
32
If RNA polymerase doesn’t have a promoter, how does it bind?
Bonds to promoter site
33
Cap structure
Guanosine nucleotide with a 5’-5’ triphosphates linkage
34
PolyA tail
Important to have because the cell can tell whether the mRNA was made correctly
35
Genetic code is degenerate
Amino acids are encoded by more than one codon
36
Important of degenerate code
The probability of mutation to chain termination would be much higher
37
What physical property is going to change between the prokaryotic start signal and eukaryotes?
There’s going to be a charge difference. | The N terminator, for euk, must be able to interact with glutamate so its needs that positive charge.
38
Splicing is carried out by
Spliceosomes
39
Introns
Start with GU and end with AU that precedes by a pyrimidine rich tract