Chapter 6: Boltzmann statistics Flashcards
Boltzmann factor
$e^{-E(s)/kT}$
P(s)
$P(s) = \frac{1}{Z}e^{-E(s)/kT}$
The prob that system is in state S (one microstate at equilat given temp T)
P(s) ranges with T
^^T => $e^{E(s)/kT} = e^{-E(s)/big} \approx e^0 \approx 1$ linked to more probable state
low T => $e^{E(s)/kT} = e^{-E(s)/small} \approx e^-\infty \approx 0$ linked to LESS probable state
P(s) range with E
Plot P(s) vs E(s) and see tht high E is less probable Ground state most likely with \$\$P(s) = \frac{1}{Z}\$\$
Partition function
sum over all the boltzmann factors
$Z = \sum_s e^{E(s)/kT}$
Comments on partition func dep
Independent of state (s) - constant for a system
Dependent on Temperature
“counts” how many states accessible to an atom weigting each in proportion to its probability
Z rel to temp
^T => $Z = \sum_s e^{-E(s)/kT}$ =>
$Z = \sum_s e^{-E(s)/big}$ => $Z \approx \sum_s 1$ => Z»_space; 1
low temp => $Z = \sum_s e^{-E(s)/kT}$ => $Z = \sum_s e^{-E(s)/small}$ => $Z = \sum_s e^{-big} \approx 0$ so summing all up we get that
low T => $Z \approx 1$
Average energy
$E_{avg}(s) = \frac{1}{Z} \sum_s E(s) e^{-E(s)/kT}$
Average quantity X(s)
$X_{avg}(s) = \frac{1}{Z} \sum_s X(s) e^{-E(s)/kT}$
Additivity of avgs
$$U_{total} = NE$$
where N is # particles
E is avg energy of 1 particle
Magical formula eqn 6.25
$\bar E = - \frac{1}{Z} \frac{\partial Z}{\partial \beta}$
Helmholtz free energy
$$F = U - TS$$
Related F to entropy
$$(\frac{\partial F}{\partial T})_{V,N} = -S$$
derive from taking partial of
F = U - TS
Relate paritiaion func and free energy
$$F = -kT\ln{Z}$$
i.e. $$Z = e^{-\frac{F}{kT}}$$
Relate partition functions for distinguishable non interacting sytems
$Z_{tot} = Z_1 Z_2 Z_3 … Z_N$