chapter 9 molecular geometry and bonding Flashcards

(44 cards)

1
Q

What is the molecular geometry of CH3F?
hint: electron domain geometry is different than molecular geometry
also, draw the molecule out to see if there are any lone pairs

a. trigonal planar
b. trigonal bipyramidal
c. trigonal pyramidal
d. tetrahedral
e. bent

A

d. tetrahedral

also, if there are no lone pairs, the electron domain geometry and molecular geometry are the same

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2
Q

What is the molecular geometry of NH3?
see study guide: I honestly don’t have these memorized

a. linear
b. trigonal bipyramidal
c. trigonal pyramidal
d. tetrahedral
e. bent

A

c. trigonal pyramidal

This molecule has 4 total electron domains and one of them is a lone pair.

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3
Q

What is the molecular geometry of SF6?

a. square planar
b. trigonal bipyramidal
c. trigonal pyramidal
d. tetrahedral
e. octahedral

A

e. octahedral

There are 6 electron orbitals with no lone pairs

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4
Q

What is the molecular geometry of XeF2?

a. linear
b. trigonal bipyramidal
c. trigonal pyramidal
d. tetrahedral
e. bent

A

a. linear

There are 5 total electron orbitals.
3 are lone pairs.

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5
Q

What is the molecular geometry of PCl5?

a. linear
b. trigonal bipyramidal
c. trigonal pyramidal
d. tetrahedral
e. bent

A

b. trigonal bipyramidal

There are 5 electron domains with no lone pairs.
The electron domain geometry and molecular geometry go by the same name.

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6
Q

What is the molecular geometry of OF2?

a. linear
b. trigonal bipyramidal
c. trigonal pyramidal
d. tetrahedral
e. bent

A

e. bent

This one is a little tricky. If you just remember that neither of these elements can exceed to octet rule, you’ll see that it doesn’t make sense for F to form any double bonds. Rather, the remaining 4 electrons will be lone pairs on oxygen.
So it’s 4 orbitals total, 2 of them being lone pairs.

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7
Q

What is the molecular geometry of IF3?

a. trigonal bipyramidal
b. trigonal pyramidal
c. see-saw
d. t-shaped
e. bent

A

d. t-shaped

There are five total orbitals.
Two of them are lone pairs.

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8
Q

What is the molecular geometry of XeF4?

a. trigonal bipyramidal
b. trigonal pyramidal
c. square planar
d. square pyramidal
e. octahedral

A

c. square planar

There are 6 total electron orbitals.
Two of them are lone pairs.

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9
Q

What is the molecular geometry of SOCl2?

a. trigonal planar
b. tetrahedral
c. trigonal pyramidal
d. bent
e. see-saw

A

c. trigonal pyramidal

There are 4 total orbitals.
One of them is a lone pair.

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10
Q

What is the approximate bond angle of a central atom with 3 electron orbitals… One of those orbitals is a double bond.
hint: this is sort of a trick question but mostly, there was a pretty good picture of a molecule that won’t copy over

a. 60 degrees
b. 90 degrees
c. 109.5 degrees
d. 120 degrees
e. 180 degrees

A

d. 120 degrees

It doesn’t seem like double bonds have much effect on the bond angle. They do. But minimal.
It the central atom had a lone pair, that would effect the bond angle much more.

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11
Q

What is the approximate bond angle of CH4?

a. 60 degrees
b. 90 degrees
c. 109.5 degrees
d. 120 degrees
e. 180 degrees

A

c. 109.5

There are no lone pairs.

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12
Q

What is the apporximate bond angle of SO2?
hint: this is a weird looking molecule but it’s still just 3 electron orbitals

a. 60 degrees
b. 90 degrees
c. 109.5 degrees
d. 120 degrees
e. 180 degrees

A

d. about 120

There are 3 electron orbitals but one of them is a lone pair making this a ‘bent’ molecule

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13
Q

What are the bond angles in SF6?

a. 60 degrees
b. 90 and 180 degrees
c. 109.5 degrees
d. 90, 120, 180 degrees
e. 180 degrees

A

b. 90 and 180

There are 6 total electron orbitals and none of them are lone pairs. The shape is octahedral. Imagine 2 F’s sticking straight up and down at opposite ends of the sulfur atom and then the other 4 F’s are flat along the x and z axes.

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14
Q

What are the bond angles in NH3?
hint: draw it out

a. 90 degrees
b. slightly less than 109.5 degrees
c. slightly less than 120 degrees
d. exactly 109.5 degrees
e. exactly 120 degrees

A

b. slightly <109.5 degrees

There are 4 total electron orbitals. One of them is a lone pair. This lone pair will slightly push on the other ones.

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15
Q

What are the bond angles in PCl5?

a. 60 degrees
b. 90, 180 degrees
c. 109.5 degrees
d. 90, 120, 180 degrees
e. 180 degrees

A

d. 90, 120, 180 degrees

see study guide for picture
there are 5 total electron orbitals. none of them are lone pairs.

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16
Q

What are the bond angles around the central atom in CH3CN?
hint: there is a picture but you’ll just have to draw it out

a. slightly less than 109.5
b. slightly less than 120 degrees
c. exactly 109.5 degrees
d. exactly 120 degrees
e. 180 degrees

A

e. 180 degrees

Despite the triple bond with N, there are still only 2 electron orbitals and no lone pairs.

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17
Q

What are the bond angles in BH3?

a. slightly less than 109.5 degrees
b. slightly less than 120 degrees
c. exactly 109.5 degrees
d. exactly 120 degrees
e. 180 degrees

A

d. exactly 120 degrees

There are 3 electron orbitals with no lone pairs.

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18
Q

What is the hybridization of CCl4?
hint: 1s doesn’t count because a single orbital cannot be hybridized. So start with the 2s orbital and start counting (not the individual electrons) but the entire square

a. sp
b. sp^2
c. sp^3
d. sp^3d
e. sp^3d^2

A

c. sp^3

So there are 4 orbitals. You have the sp2 block and the 3 p blocks. That makes 4. The last block in that count is the p3 so…
That’s how you get sp^3

19
Q

What is the hybridization of H2O?

a. sp
b. sp^2
c. sp^3
d. sp^3d
e. sp^3d^2

A

c. sp^3

There are 4 total electron orbitals. You forget about s1
So count them. s2 sp1 sp2 sp3
sp3 is where it winds up so that’s your hybrid

20
Q

What is the hybridization of SeF4?

a. sp
b. sp2
c. sp3
d. sp3d
e. sp3d2

A

d. sp3d

There is one lone pair on Se so there are 5 total electron orbitals. Count them all the way up to d1 discounting the s1 orbital.

21
Q

What is the hybridization of OCS?

a. sp
b. sp2
c. sp3
d. sp3d
e. sp3d2

A

a. sp

Despite the double bonds, there are still only 2 total electron orbitals.

22
Q

What is the hybridization of XeF4?

a. sp
b. sp2
c. sp3
d. sp3d
e. sp3d2

A

e. sp3d2

There are six total electron orbitals. Don’t forget the 2 lone pair. Start with 2s and just count them up.

23
Q

What is the hybridization of BCl3?

a. sp
b. sp2
c. sp3
d. sp3d
e. sp3d2

A

b. sp2

There are 3 total electron orbitals (no lone pairs). Count the orbitals up starting with s2

24
Q

How many pi bonds are there in HCOCN?
hint: there’s a central C atom attached to an O, and H, and another C. The N atom is attached to the spin-off C. It would be a good exercise to draw it out but you could always cheat the Google it.

a. 0
b. 1
c. 2
d. 3
e. 4

A

d. 3

Bascially, the bond between the central C is a double bond resulting in one pi bond. And the bond between the spin-off C and the N is a triple bond resulting in 2 pi bonds so… 3

25
How many sigma bonds are in a molecule with 4 single bonds and 2 double bonds? hint: there's a picture of a molecule but I don't even know what it is. a. 5 b. 6 c. 7 d. 8 e. 9
b. 6
26
Which of the following molecules is polar? I. XeF4 II. CH4 III. XeF2 hint: they're drawn out in the example but the picture didn't copy over. it's a good exercise to draw them out and check out the molecular geometry a. I only b. III only c. I and III d. I, II, and III e. none of these
e. none of these if you draw them out, you can see that they're all symetrical and therefore, non-polar
27
Which of the following molecules is polar? I. BF3 II. CO2 III. CHCl2 a. I only b. III only c. I and III d. I, II, and III e. none of these
b. III only I took an educated guess here and got it right. Here is the book's explanation... BF3 is trigonal planar and the 3 bond dipoles ‘cancel’ resulting in a nonpolar molecule CO2 is linear and its bond dipoles are 180˚ apart and ‘cancel’ resulting in a nonpolar molecule. CH2Cl2 is tetrahedral and has bond angles of 109.5˚ (not 90˚ and 180˚). The bond dipoles are therefore not 180˚ apart and do not completely ‘cancel’ each other making CH2Cl2 polar.
28
Which of the following molecules is polar? I. CCl4 II. HCCl3 III. CClH3 a. I only b. II only c. I and II d. II and III e. I, II, and III
d. II and III This is the book's answer which isn't very good: II and III are both polar as the individual bond dipoles do NOT cancel overall. I is nonpolar as all the individual bond dipoles all cancel. Me again: So they each have 4 electron orbitals with no lone pairs but I guess, since there are different types of atoms pulling on II and III, that's what makes them polar
29
Which of the following molecules is polar? I. NH3 II. H2O III. CF2H2 a. I only b. II only c. I and II d. II and III e. I, II, and III
e. I, II, and III This one I could sort of intuit. NH3 has a lone pair on top so that's going to throw off the molecular geometry causing it to be polar. H2O is famously really polar because it's 'bent' And CF2H2 (I'm probably not writing that right) is polar even though the Lewis drawing makes it look like it wouldn't be. It's 4 orbitals with no lone pair BUT, they'e all at 109.5 with one orbital sprouting out the top and the rest making sort of a tripod.
30
Which of the following molecules is polar? I. BCl3 II. CF4 III. NF3 in the book, this is the first question like this where it makes you draw them out so... Be on the lookout for lone pairs a. I only b. III only c. I and III d. II and III e. I, II, and III
b. III only I guessed! And I got it. After drawing them out. BCl3... Cl is the only type of atom connected to B and they're all pulling an even 120 degrees so; non-polar CF4... There are no lone pairs and all the atoms are pulling at an even 109.5 In a previous question, there was a similar one where there were two each of different types of atoms connected to the carbon and this made it polar any way you sliced it so just keep that in mind.. It was like CCl2H2 or something And lastly, NF3 has a lone pair so it's going to push on the other 3 F atoms making it polar
31
Which of the following is non-polar? I. SeF4 II. XeF2 III. IF3 a. I only b. II only c. I and III d. II and III e. I, II, and III
b. II only I feel like I'm getting better at these finally. It helps to use the study guide with the pictures of the molecular geometry. SeF4 has a lone pair on the Se so that's going to throw off the symetry. XeF2 is non-polar even though there are 3 lone pairs on Xe. However, the F's will pull at 180 degrees aprt and then the lone pairs, all on their own plan, will pull in perfect 3rd's of each other. IF3 has 2 lone pair but one of the F's will be on the lone pairs' plane also so that will tip things in one direction.
32
How many electron domains are there around the carbon atom of CO2? a. 3 b. 2 c. 4 d. 6 e. 8
b. 2 depite the double bonds made to improve the formal charge, there are still only 2 electron domains
33
How many electron domains are there around phosphorus in a PO3^3- ion? a. 3 b. 6 c. 8 d. 4 e. 5
d. 4 There are 26 total electrons. Phos has 5 valence. 3(6) oxygens make 18 valence. Plus 3 extra because it's a polyatomic ion. This will leave 2 extra for one lone pair.
34
What is the molecular geometry of CF4? a. square planar b. tetrahedral c. pyramidal d. linear e. octahedral
b. tetrahedral There are four domains with no lone pairs. The molecular geometry and electron domain geometry would have the same name.
35
What is the molecular geometry of NO2? a. bent b. linear c. pyramidal d. tetrahedral e. trigonal planar
a. bent There is one lone pair making that 3 electron domains total. Because one of the domains is a lone pair, the shape and name will be different than it would for just the electron domain geometry.
36
What is the molecular geometry of KrBr4? a. tetrahedral b. see-saw c. octahedral d. square planar e. octahedral
d. square planar There are 6 total electron domains. Two of those domains are lone pairs. Kr has 8 valence. Br has 4(7) = 28 electrons. IF! the question was asking what the electron domain geometry was, it would be octahedral so just keep that in your back pocket.
37
What is the electron domain geometry of BrF3? a. see-saw b. t-shaped c. octahedral d. trigonal bipyramidal e. trigonal planar
d. This is almost a trick question. It's asking for the electron domain geometry not the molecular geometry so the fact that there are two lone pairs doesn't make a difference in this case.
38
What are the bond angles in BCl3? a. 107 degrees b. 109.5 degrees c. 120 degrees d. 90 degrees e. 180 degrees
c. 120 I honestly don't have these memorized but who cares? I know where to quickly find it in the study guide. BCl3 has 3 electron domains with no lone pairs (B is going under the octet rule which is common for it) which makes the angles 120
39
What is the angle between the lone pairs in XeF4? a. 90 degrees b. 120 degrees c. 107 degrees d. 180 degrees e. 45 degrees
d. 180 degrees Again, just refer to the study guide. There are 6 total electron domains, 2 of them being lone pairs. This makes the molecular geometry square planar. The 4 F's are all 90 degrees apart but the lone pairs sprout out from each vertical end like north and south so... 180
40
Which of the following hybrid orbitals are used by carbon to bond to each of the hydrogen atoms in CH4? a. s b. sp c. sp3 d. sp2 e. sp3d
c. sp3 I felt like this was a trick question but... Just s isn't a hybrid orbital so, despite the other atoms being hydrogens, you're still going to need an actual hybrid because there are 4 of them. 4 obritals (excluding s1)... Just count the boxes. s2 p1 p2 p3 = sp3
41
What is the hybridization of sulfur in SO3^2- a. s b. sp c. sp2 d. sp3 e. spd
d. sp3 There is a lone pair so there are 4 total orbitals. When you count the boxes, you'll end up in the 3rd 'p' box. So... sp3
42
Which of the following best describes the 3 bonds that comprise a triple bond? a. 1 sigma, 1 pi b. 3 pi bonds c. 3 sigma bonds d. 1 sigma and 2 pi bonds e. 2 sigma and 1 pi bond
d. 1 sigma and 2 pi The first bond is a sigma. Any bonds after that are pi
43
Which of the following is polar? a. BH3 b. NH3 c. BF3 d. SO3 e. CF4
b. NH3 This is because NH3 has a lone pair which slightly warps the symmetry required for something to be considered 'non-polar'
44
Which of the following molecules does not have a dipole moment? a. H2O b. CH2Cl2 c. NH3 d. BCl3 e. HBr
d. BCl3 I guessed and got it right. It was between that and CH2Cl2 which seems like, with the central atom being carbon, the other two atoms could sprout out perpendicular to each other but that's kind of far-fetched. BCl3 is just straight up 'the Cl's are pulling it evenly into 3rds