chem exam 2 (chapter 3-5) Flashcards

(68 cards)

1
Q

principle quantum number

A

energy = distance

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2
Q

angular quantum number

A

shape of orbit (which orbital it is)

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3
Q

magnetic quantum number

A

how many of each shape

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4
Q

spin quantum number

A

represents whether an electron is spin up in a magnetic field or spin down

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5
Q

Pauli Exclusion Principle

A

no 2 electrons can have the same 4 quantum numbers

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6
Q

paramagnetic

A

has a magnetic moment

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7
Q

diamagnetic

A

no magnetic moment

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8
Q

Hund’s Rue

A

electrons fill orbitals 1 at a time with parallel spin orbital diagrams

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9
Q

Zeff formula (effective nuclear charge)

A

number of protons - shielding electrons

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10
Q

Zeff trend

A

how strongly the nucleus is holding onto the electrons. Goes up as you go up and to the right

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11
Q

Ex: find the Zeff of Na and write the electron configuration

A

Zeff = # protons - # shielding electrons = 11 - 10 = +1

Electron config: [Ne]3s^1

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12
Q

Aufgau Principle

A

when filling electron shells, fill from the lowest energy level and move up

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13
Q

Ionic Bonding

A

between a metal and a non metal. metal gives electrons to non metal

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14
Q

Lewis Dot Models

A

represent valence electrons on an atom

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15
Q

Electronegativity

A

how tightly an atom hangs onto its valence electrons

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16
Q

electronegativity trend

A

an atom with a smaller radius or more valence electrons is more electronegative because the nuclear force is greater and/or the atom wants to gain electrons to fill its shell (up and to the right)

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17
Q

electron affinity

A

energy associated with an atom gaining an electron

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18
Q

electron affinity trend

A

more negative electron affinity the higher the attraction is for electrons (kj/mol) trend is up and to the right

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19
Q

anion

A

an ion with a negative charge (gains electrons). larger than a cation

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20
Q

cation

A

an ion with a positive charge (loses electrons). smaller than an anion

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21
Q

atomic radius

A

radius of the atom

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22
Q

atomic radius trend

A

increasing down and to the left of the PT because more shells and EN means the nucleus holds tighter to the electrons and the radius gets smaller

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23
Q

ionization energy

A

the energy required for an element in the gaseous stage to lose an electron

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24
Q

Kaddy corner effect

A

vertical wins over horizontal in periodic trends

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25
Ex: which has the most negative electron affinity, C or N? (affinity exceptions)
1) degenerative state? YES 2) do electron configuration (orbital diagram) notice when C and N become aninons (-1 chg) N has 1 pair in its p orbital and 2 unpaired while C has only unpaired electrons i C has a more negative electron affinity since the carbon is entering a more stable state it will give off more energy than nitrogen which is leaving a stable state
26
Degenerate element groups
alkali earth metals (2A), hallogens (7A), 5A
27
Ionic nomenclature
1) the most electropositive element goes 1st 2) most electronegative element goes last and changes suffix (always the nonmetal) 3) # elements in a formula results from balancing the charge
28
Transition metals in ionic molecules
transition metals can have multiple oxidation states (can have different charges)
29
stock system
a roman numeral follows the t metal to show charge
30
latin system
suffix of a t metal changes - ic for larger charge - ous for smaller charge
31
covalent bonding
sharing of electrons (since both elements are non-metals) to reach the noble gas configuration
32
single bond
sharing of 2 electrons between elements
33
double bond
sharing of 4 electrons between elements
34
triple bond
sharing of 6 electrons between elements
35
mono
1
36
di
2
37
tri
3
38
tetra
4
39
penta
5
40
hexa
6
41
hepta
7
42
octa
8
43
nona
9
44
deca
10
45
Molecular Molar Mass
sum of all individual atomic molar masses that make up the molecule
46
Atomic Molar Mass Formula
#atoms of an element x atomic mass
47
% of an element in a molecule formula
(# element)(atomic molar mass)/total molecular molar mass x 100
48
Ex: calculate % N in Fe(NO3)3*5H20)
``` N = 3(14g/mol) = 42g/mol NO3 = 331.8g/mol %N = 42/331.8 x 100 = 12.6% N ```
49
Ex: how many mols hydroxide are there in 10.5 mols of aluminum hydroxide?
hydroxide = OH^-1 chg of Al = +3 --> Al(OH)3 | (10.5 mols Al(OH)3/1)*(3 mols OH/1 mol Al(OH)3) = 31.5 mol OH^-1
50
Ex: how many g of O in 12.5 g of Al(OH)3?
(12.5g/1)*(1 mol Al(OH)3/78.0 g Al(OH)3)*(3 mol O/1 mol Al(OH)3)*(16g O/1 mol O) = 7.69 g O
51
true formula/molecular formula
actual representation of # elements making up a molecule
52
empirical formula
simplest version of the true formula
53
Ex: find the empirical formula for 2.0g copper chloride containing 0.945g Cu and 1.055g Cl
(0.945g Cu/1)*(1 mol Cu/63.5g Cu) = 0.01488 mols Cu (1.055g Cl/1)*(1 mol Cl/35.5g Cl) = 0.0297 mol Cl Cu(0.01488/0.01448)Cl(0.297/0.01448) = CuCl2
54
Ionization energy trend
the amount of energy needed to remove an electron from an atom increases as you go up and to the right on the PT because smaller atoms = higher ionization energy (nucleus has a better hold on electrons)
55
metallic character trend
the ability for an electron to lose an electron (opposite of ionization energy) increases as you go down and to the left on the PT because larger molecules (metals) have less electronegativity (nucleus's hold on the electrons) and want to give their electrons away
56
formal charge
valence electrons - (# lone pairs + 1/2 bonding electrons)
57
Lewis dot structure
an electronic representation of the valence electrons for a given element... electrons are shown as dots and you can have paired or unaired electrons
58
pure covalent bond
same on either side so same EN (= sharing of bonding electrons)
59
bond dipole
unequal sharing of electrons, still shared so still covalent
60
ionic bond
bonding of electrons not being shared because of drastic difference in EN
61
bond lenth
single bonds > double bonds > triple bonds
62
bond strength
single bonds < double bonds < triple bonds
63
radicals
elements that possess 1 unpaired electron
64
incomplete octets
elements that can't reach 8 electrons
65
expansion of octets
elements in the n >/= 3 have at their disposal empty d orbitals to use in bonding... elements possess the ability to share > 8 electrons (so long as n>/= 3)
66
expansion
breaking up lone pairs to increase the # bonds an element can make
67
resonsnace
a delocalization of electrons within a molecule, resulting in more stability for the molecule. drawing a molecule with resonance often deciphers correct structures from the incorrect - a charge (+/-) next to a double bond
68
Valence Shell Pair Repulsion (VSPR)
electron groups (atoms, lone pairs, bonds) naturally repel each other so these electron groups want to be as far away from each other as possible --> 3D geometry