Chem final 4, 5, 6, + 2 questions from others Flashcards
(43 cards)
Which element is oxidized in this reaction?
FeO+CO→Fe+CO2
remember this..
.. reduction means “reduction in charge”
.. “agents” are opposites
from which .. reduction means reduction in charge .. oxidation means increase in charge .. species reduced = oxidizing agent .. species oxidized = reducing agent
this problem
O in FeO is in the -2 state.. why? it has the higher electronegativity value and takes as
.. .. .. . ….many electrons as it needs from Fe to fill it’s outer orbital.
Fe in FeO is in the +2 state.. why? O is in the -2 state.. the overall molecule has zero net
.. . .. … ..charge (see any + or - after that FeO?) so Fe must be +2 to balance
.. .. .. .. …or better yet…. 1xFe + 1x(-2) = 0 =====> Fe = +2
C in CO is +2… same reasoning as above
O in CO is -2
Fe in Fe(s) is 0….. why? see any charge after that “Fe”?
C in CO2 is +4.. why? each O is -2… overall molecule = 0
.. .. . .. . … . . .1xC + 2x(-2) = 0 ===> C = +4
so..
.. .Fe went from +2 to 0 and was “reduced” (charge was reduced) and is the oxidizing agent
.. C went from +2 to +4 and was “oxidized”… . (charge increased).. and is the reducing agent
Strong acids
Some chemists say that there are six strong acids while others include chloric acid as a strong acid, making seven strong acids as listed below. All other acids are classified as weak acids. Strong acid Chemical formula Hydrochloric acid HCl Hydrobromic acid HBr Hydroiodic acid HI Chloric acid HClO3 Perchloric acid HClO4 Nitric acid HNO3 Sulfuric acid H2SO4
acids vs bases
As a general rule, acid leads with H, bases contain OH.
Many exceptions though
There are eight strong bases. All bases other than those found on this list are classified as weak bases.
Strong base Chemical formula Lithium hydroxide LiOH Sodium hydroxide NaOH Potassium hydroxide KOH Rubidium hydroxide RbOH Cesium hydroxide CsOH Calcium hydroxide Ca(OH)2 Strontium hydroxide Sr(OH)2 Barium hydroxide Ba(OH)2
Each of the following reactions shows a solute dissolved in water. Classify each solute as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. A(l)→A(aq) BC(aq)⇌B+(aq)+C−(aq) DE(aq)→D+(aq)+E−(aq) XY(s)→X+(aq)+Y−(aq) Z(s)→Z(aq)
Drag the appropriate items to their respective bins.
View Available Hint(s)
Strong electrolyte DE, XY Weak electrolyte BC Nonelectrolyte Z, A
nonelectrolytes
strong electrolytes
weak electrolytes
1. Ionic salts, strong acids, and strong bases are classified as .
2. Molecular compounds other than strong acids, strong bases, weak acids, or weak bases are classified as .
3. Weak acids and weak bases are classified as .
- Ionic salts, strong acids, and strong bases are classified as strong electrolytes.
- Molecular compounds other than strong acids, strong bases, weak acids, or weak bases are classified as nonelectrolytes.
- Weak acids and weak bases are classified as weak electrolytes
The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab shelf:
Beaker Contents
1 200. mL of 1.50 M NaCl solution
2 100. mL of 3.00 M NaCl solution
3 150. mL of solution containing 19.5 g of NaCl
4 100. mL of solution containing 19.5 g of NaCl
5 300. mL of solution containing 0.450 mol NaCl
Arrange the solutions in order of decreasing concentration.
4 > 2 > 3 > 1&5
#1 and 2 the concentrations are given: 1.50 M and 3.00 M respectively. #3 is (19.5 g / 58.44 g/mol) / 0.150 L = 2.22 mol/L = 2.22 M #4 is (19.5 g / 58.44 g/mol) / 0.100 L = 3.34 M #5 is 0.450 mol / 0.300 L = 1.50 M
*
According to the following reaction, what volume of 0.244 M KCl solution is required to react exactly with 50.0 mL of 0.210 M Pb(NO3)2 solution?
2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)
I’ll show you the process, let me know if you encounter any difficulties.
This is solved by using the formula ‘n=CV’, where n=number of moles, C = concentration of solution in moles per Litre, and V is volume in Litres.
So n=CV for Pb(NO3)2 is
0.050L x 0.210M = 0.0105 moles in solution.
Now since the stochiometry of KCl to Pb(NO3)2 is 2:1, there are 2 times the moles of KCl, so 0.0105x2=0.021 moles KCl.
To find the Volume of 0.244M concentration KCl required to react, just rearrange the formula and plug in the units:
n=CV so, V=n/c
0.021 moles /0.244M =0.086L
Which is 86.1mL
(to 3 significant figures)
*
Determine the percent yield of a reaction that produces 28.65 g of Fe when 50.00 g of Fe2O3 react with excess Al according to the following reaction.
Fe2O3(s) + 2 Al(s) → Al2O3(s) + 2 Fe(s)
Correct Answer:
Correct
81.93%
- Lithium and nitrogen react in a combination reaction to produce lithium nitride:
6 Li(s) + (g) → 2 Li3N(s)
How many moles of lithium are needed to produce 0.31 mol of N when the reaction is carried out in the presence of excess nitrogen?
Correct Answer:
Correct
0.93
*
Identify the polyprotic acid.
Correct Answer:
Correct
H2SO4
*
What element is undergoing oxidation (if any) in the following reaction?
Zn(s) + 2 AgNO3(aq) → Zn(NO3)2(aq) + 2 Ag(s)
Correct Answer:
Correct
Zn
*
Identify the reducing agent.
2 Al3+(aq) + 2 Fe(s) → 2 Al(s) + 3 Fe2+(aq)
Fe
not Fe2+
*
What are the coefficients in front of NO3-(aq) and Ni(s) when the following redox equation is balanced in an acidic solution?
\_\_\_\_ NO3-(aq) + \_\_\_\_ Ni(s) → \_\_\_\_ NO(g) + \_\_\_\_ Ni2+(aq)
Correct Answer:
Correct
2, 3
* What mass (in g) of AgCl is formed from the reaction of 75.0 mL of a 0.078 M AgC2H3O2 solution with 55.0 mL of 0.109 M MgCl2 solution?
2 AgC2H3O2(aq) + MgCl2(aq) → 2 AgCl(s) + Mg(C2H3O2)2(aq)
Selected Answer:
Correct
0.838 g
*
Which one of the following compounds is insoluble in water?
Correct Answer:
Correct
Ag2SO4
*
According to the following reaction, what volume of 0.244 M KCl solution is required to react exactly with 50.0 mL of 0.210 M Pb(NO3)2 solution?
2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)
Correct Answer:
Correct
86.1 mL
*
A 12.39 g sample of phosphorus reacts with 42.54 g of chlorine to form only phosphorus trichloride (PCl3). If it is the only product, what mass of PCl3 is formed?
Selected Answer:
Correct
54.93 g
Enter the net ionic equation for the reaction that occurs when aqueous hydroiodic acid and aqueous ammonium sulfite are mixed.
Express your answer as a net ionic equation. Identify all of the phases in your answer.
2H+(aq)+SO32−(aq)→H2O(l)+SO2(g)
When 15.0 g of zinc metal reacts with excess HCl, how many liters of H2 gas are produced at STP?
- 3 L
- 14 L
- 229 L
- 458 L
Balanced equation: Zn+2HCl–>H2+ZnCl2
Find moles of Zn first, then convert to moles of H2, using balanced equation. From this, plug into PV=nRT to find the volume of H2 gas at STP.
Moles of Zn: [15.0 g Zn] x [1 mol Zn/65.4 g Zn] (according to periodic table, atomic weight of Zn is 65.4) =0.23 mol Zn
Moles of H2: [0.23 mol Zn] x [1 mol H2/1 mol Zn] (according to equation, mole-mole ratio of Zn to H2 is 1 to 1)=0.23 mol H2
Volume of H2: PV=nRT —> rearrange equation to become V=nRT/P, where R is the gas constant (0.082 Latm/Kmol)
Plug in moles of H2, and STP values: n (moles of H2)= 0.23 mol, P=1atm, R=0.082 Latm/Kmol, and T=273K.
This becomes V= [(0.23 mol) x (0.082 Latm/Kmol) x (273K)]/[1atm] = 5.14L
What is ΔH∘rxn for the following chemical reaction?
CS2(g)+2H2O(l)→CO2(g)+2H2S(g)
You can use the following table of standard heats of formation (ΔH∘f) to calculate the enthalpy of the given reaction.
Element/ Compound Standard Heat of Formation (kJ/mol) Element/ Compound Standard Heat of Formation (kJ/mol)
H(g) 218 N(g) 473
H2(g) 0 O2(g) 0
H2O(l) −285.8 O(g) 249
CS2(g) 116.7 H2S(g) −20.60kJ
C(g) 71 CO2(g) −393.5kJ
C(s) 0 HNO3(aq) −206.6
All in kJ:
(-393.5) + (2 x -20.60) - (116.7) - (2 x -285.8) = +20.2 kJ
The atmospheric pressure is 715 mm Hg. What is the pressure in torr?
715 torr
When 15.0 g of zinc metal reacts with excess HCl, how many liters of H2 gas are produced at STP?
5.14 L
The density of nitric oxide (NO) gas at 1.35 atm and 29.8°C is ________ g/L.
1.63