Chemical and Physical Foundations Flashcards
(73 cards)
Units
Physical quantity, base units, symbol
lengyh
mass
time
electric current
temperature
frequency
sound intensity
length–> metre–> m
mass–> kilogram–> kg
time–> Second–> s
electric current–> Ampere–> A
magnetic field–> Tesla–> B
temperature–> Kelvin–> K
frequency–> Hertz–> Hz
sound intensity–> decibel–> dB
wehn your equation has a constant (gravitational constant, planck’s constant, etc) this is an indication that you must use ___ units
SI
Prefixes
prefix, symbol, order of magnitude
nano
micro
milli
centi
kilo
mega
giga
nano–> n–> 10^-9
micro–> μ–> 10^-6
milli–> m–> 10^-3
centi–> c –> 10^-2
kilo–> k–> 10^3
mega–> M–> 10^6
giga–>G –> 10^9
angstrom (Å), unit of length, equal to:
1x10^-10 or 0.1nm (nanometer)
to convert from km/h to m/s _______ by 3.6
divide
to convert from m/s into km/h ______ by 3.6
multiply
The speed of light is
c = fλ relates the speed of light (c), its frequency (f), and its wavelength (λ)
for scientific notation, making the coefficient a bigger number means the exponent must get
smaller (or more negative)
when adding or subtracting scientific notiation, you want coefficients to have the ___ exponent
for multiplying in scientific notation, we ___ exponents and ___ the coefficients
to divide in scientific notation, we ___ exponents and ___ the coefficients
same
add, multiply
subtract, divide
for scientific notation, making the coefficient a smaller number means the exponent must get
bigger (or more positive)
how do you round intermediate calculations?
one up and one down
ex: 8.9x11.1=9x11=99=100
then for the next calculation, round down: 100x1.14=114=110
with fractions, try to round the numerator and denominator in the ___ direction to maintain consistency and why
same
this consistency will be important for fractions, because differences in the direction of rounding can be compounded in fractions. if you round one up and the other down, you’ve done 2 manipulations to make the final answer larger.
ex: 118/9.81=120/10=12 (real answer is 12.03)
how do you multiply and divide fractions
with fraction multiplication, you multiply the numerators and the denominators
when we divide fractions, we multiply by the inverse: (2/4)/(5/6)=(2/4)x(6/5)=(12/20=(3/5)
converting between logarithmic and exponential form
loga(c)=b
a^b=c
when logs have no specified base (a is not written), the assumption is log base 10
what do you do when the term inside the logarithmic function has an exponent
the exponent can be pulled out to become the coefficient
ex: log(10^3)= 3log(10)
how to add logs
combine the terms by multiplying them
log(a)+log(b)=log(axb)
how to subtract logs
combine the terms by dividing them
log(a)-log(b)=log(a/b)
when the number inside the lpg is 1x10^n, the log of that number is
n
general approach to logarithmic estimation
Look at which exponents our number lies between
determine which of those two numbers our value is closer to
make an educated guess as to the approximate value
figure out which two logs your number is between and then figure out which of the two exponent numbers is closer to the original number and then pick the answer closest to that number
ex: -log(3.0x10^-4)
3.0x10^-4 is a number between 1.0x10^-4 and 10x10^-4 (1.0x10^-3)
Therefore, the answer must be between 3 and 4
Since 3.0x10^-4, the answer must be closer to 4, so pick the answer closer to 4
scalar quantities
only have magnitude, but no direction
these quantities describe motion, but do not take into account movement on a grid
relevant examples: speed, work, pressure, energy, mass, etc
vector quantities
have a magnitude and a direction
vectors take into account the 2 or 3 dimensional space (for the MCAT, it will be 2 dimensional) for the direction of motion
generally speaking, we must separate the x and y components and treat them separately
relevant examples: displacement, velocity, force, weight, etc
vector components are based off:
right angle triangles and SOH CAH TOA
SOH CAH TOA
sin(θ)=O/H
cos(θ)=A/H
tan(θ)=O/A
to combine the vector components to get the resultant vector, we employ the
pythagorean theorem
C^2=A^2+B^2
H^2=A^2+O^2