Chemistry - Rings, Polymers and Analysis Flashcards
(181 cards)
Define an Arene
A hydrocarbon with a ring of 6 carbon atoms and a delocalised π system of electrons e.g. Benzene
Define an Aromatic Compound
A compound containing a benzene ring (an arene)
What evidence is there to suggest that the Kekule formula of Benzene is not correct?
1) Benzene does NOT DECOLOURISE BROMINE IN THE DARK
2) ALL THE CARBON-CARBON BONDS ARE THE SAME LENGTH c=c bonds are shorter than c-c bonds
3) HYDROGENATION of benzene is LESS EXOTHERMIC than expected (hydrogenation of trienes have ∆H = -360, benzene has ∆H of -208
What does benzene’s ∆H show about its bonding?
MORE STABLE π BONDS than expected - due to DELOCALISED ELECTRONS
How reactive is benzene compared to alkenes, and why is this?
1) LESS REACTIVE
2) π-electrons DELOCALISED - spread out more - LOW ELECTRON DENSITY - LESS ATTRACTIVE THE ELECTROPHILES
Why are all of benzenes carbon-carbon bonds the same length?
LOW ELECTRON DENSITY - DELOCALISED electrons are spread out over the ring
Why does benzene have a lower ∆H than expected?
DELOCALISATION LOWERS ENERGY OF ∏-ELECTRONS
more stable state than isolated π-bonds - more energy is needed to break them - less favourable
What is the name of the mechanism where electrophiles react with aromatic rings?
ELECTROPHILIC SUBSTITUTION
Why don’t Arenes react with electrophiles by addition?
1) LESS REACTIVE than alkenes - delocalisation lowers electron density - electrophiles are less attracted 2) SUBSTITUTION MAINTAINS THE DELOCALISED ∏ - SYSTEM - more favourable
What is the overall equation for the Nitration of Benzene?
C6H6 + HNO3 -> C6H5NO2 + H2O
What conditions are necessary for the nitration of benzene?
50-60ºC CONC NITRIC AND CONC SULPHURIC ACID
How is the electrophile formed for the nitration of benzene?
HNO3 + H2SO4 (NO2)+ + H2O + HSO4-
Describe benzene’s structure:
1) PLANAR - all atoms on same plane, all c-c bond lengths the same 2) Each C forms 3 SIGMA BONDS - 2 to adjacent carbons, 1 to H 3) each carbon has 1 electron in a P ORBITAL above and below plane 4) P orbitals overlap and form a DELOCALISED ∏ - ELECTRON SYSTEM (cloud)
Describe the mechanism of the reaction of Nitric acid with benzene:
1) Curly arrow from inner circle edge of benzene ring to N on (NO2)+ 2) a) H and NO2 both bonded to one carbon b) inner circle now semicircle, +ve charge in circle opposite bonded c c) Curly arrow from H bond to where the circle edge was below bonded c 3) products: C6H5NO2 + H+
How is the catalyst regenerated in the Nitration of Benzene?
H+ formed in reaction combines with HSO4- formed in formation of electrophile HSO4- + H+ -> H2SO4
What conditions are necessary for the Halogenation of Benzene?
HALOGEN CARRIER catalyst AlBr3 or FeBr3
How does the halogen carrier catalyst aid halogenation of benzene?
Polarises the halogen -> stronger electrophile
Give the reaction for the formation of the electrophile in the halogenation of benzene:
1) Br2 + AlBr3 Br+ + (AlBr4)-
Describe the mechanism by which the Bromination of Benzene occurs:
1) Curly arrow from circle in Benzene ring to Br+ 2) a) H and Br bonded to same carbon in ring b) semicircle formed with + inside ring opposite bonded c c) curly arrow from H bond to where ring would be by bonded c 3) C6H5Br and H+ formed
How is the Halogen Carrier Catalyst reformed?
H+ released in reaction reacts with AlBr4- formed in generation of electrophile H+ + (AlBr4)- -> AlBr3 + HBr
What state is phenol at rtp, and what is the reason for this?
Solid - large surface area= lots of van der waals forces
How soluble is phenol in water?
Slightly soluble - OH group can form H bonds, but large non-polar surface area cannot
Why is phenol more acidic than water or ethanol?
The negative charge on the O of the Phenoxide ion is delocalised into the π - system of the aromatic ring, making the ion more stable - e.g. more favourable to the dissociation of H+. Ethanol and water do not have a π-system, and so the charge cannot be delocalised
Give an equation for the reaction of Phenol with Sodium Hydroxide:
C6H5OH(aq) + NaOH(aq) -> C6H5O-Na(aq)+ + H2O(l)