Consolidation Flashcards

(32 cards)

1
Q

why atomic radius for TM almost constant?

A
  • protons no. increases, nuclear charge increases.
  • Shielding effect increases because the additional electrons are added to the inner 3d subshell.
  • increase in shielding effect cancels out the effect of the increase in nuclear charge.
  • effective nuclear charge and attraction for valence electrons remains fairly constant.
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2
Q

What is transition element?

A

It is a d-block element with partially filled d subshells which forms one or more stable ions

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3
Q

TM higher BPMP than s block elements

A
  • 3d, 4d e- close in energy
  • both 3d, 4d avaliable for delocalisation into sea of e-
  • ↑ delocalised e- & ↑ charge density metallic bond stronger
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4
Q

TM why have variable oxidation state?

highest possible oxidation state = unpaired 3d + 4s e-

A
  • both 3d & 4s e- similiar in energy,
  • both 3d , 4s orbitals avaliable for for bond formation
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5
Q

Why are TM heterogeneous catalysts?

heterogeneous catalysts: catalyst and reactants different phases

A
  • partially filled 3d subshell allows the exchange of e- to and from the reactant molecules
  • facilitate formation of weak bonds with reactant molecules
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6
Q

what are ligands?

Ligands acct as Lewis Bases ( e- pair donor) and bond to Lewis Acid

A
  • ion or molecule containing at least one atom that has lone pair of e-
  • to be donated into a low-lying vacant orbital of metal atom or ion
  • forming a dative covalent bond
  • and forming a complex
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6
Q

Why are TM homogenous catalaysts?

A
  • can exist in differnet oxidation states
  • convert from one oxidation state to another
  • due to the similar energy of the 3d and 4s orbitals
  • this facilitates formation & decomposition of intermediates
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7
Q

what are complexes?

A

central metal ion linked to one or more ligands by dative covalent bonds.

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8
Q

why do TM form complexes?

A
  • have **low lying vacant orbitals ** to accommodate lone pair of e- from ligands to form dative covalent bonds (DCB)
  • small ionic radius and high charge density, → high polarising power and able to attract lone pair of e- from ligand to form DCB.
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9
Q

why are TM compounds coloured?

VERY SIGMA IMPTTT

A
  • in pesence of water ligands, partially filled 3d orbitals of TM split into 2 groups of different energy levels
  • e- that have lower energy d orbitals promoted to higher energy d orbitals as they adsorb energy from wavelength of visible light
  • colour observed is complementary to the wavelength of light absorbed
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10
Q

Balance redox rxn

A
  1. balance O2 by adding H2O
  2. balance H2 by adding H+
  3. balance charge by adding e-
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11
Q

Purpose of salt bridge in electrolysis

A
  • maintain electrical neutrality of each half cell
  • complete the circuit allowing ions to flow without mixing electrolytes
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12
Q

limitations of Standard Cell Potential (E°cell) to predict spontaneity

A
  1. kinetic factor not considered as E° cell measure POE, rxn thermodynamically feasible but not kinetically feasible
  2. Rxn take place under non-standard conditions
  3. side rxn can still occur
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13
Q

Mode of action of heterogeneous catalyst

SUPA DUPA IMPT

A
  • reactants adsorbed onto the active sites of the catalyst surface by forming weak interactions with catalyst
  • This increases the surface concentration reactant on catalyst
  • Adjacent (different) reactant molecules are brought close tgt and correct orientation
  • This weakens the Intramolecular covalent bonds in the reactants resulting in lower activation energy than the uncatalysed reaction.
  • Products formed diffuse from the catalyst surface, vacant active sites regenerated for adsorbing other reactants
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14
Q

Explain, with Boltzmann distribution, how the rate and rate constant is increased by a catalyst.

A
  • Catalyst provides an alternative reaction pathway which of lowered activation energy.
  • Thus, particles with energy equal to or greater than the actvation energy of the catalysed reaction E a(cat) increases or deduce from legend.
  • This results in an increase in frequency of effective collisions,
  • This results in a larger rate constant, k hence the reaction rate increases.
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15
Q

explain the trend in decomposition temperature from CaCO3 to BaCO3.

MUST QUOTE FROM DATA BOOKLET!!!!!

A

Down Group 2 from Ca to Ba, Ionic radii:
Ca2+ : 0.099nm Sr2+ : 0.113nm Ba2+ : 0.135nm

  • charges stay the same but the ionic radii of the Group 2 cations, M2+ increases from Ca to Ba.
  • As charge density = charge x radius , there is a decrease in the charge density of the Group 2 cations. Hence, the polarising power of the Group 2 cations decreases
  • This results in the electron cloud of the large CO 3 2 – anion to be distorted (or polarised) to a smaller extent and a smaller weakening effect on the CO bonds within the CO 3 2 – by the M2+ .
  • As more energy is required for decomposition (breaking down of the anion), the decomposition temperature increases from CaCO 3 to BaCO3 .
16
Q

bond strength from SP3 to SP hybridisation

A

bond strength increases:
* s-chracter of the hybrid orbital increases
* hybrid orbital is less diffused,
* e- more tightly held by the nuclei —>
1) (link to basicity) e- less available for dative bonding with H+ and is a weaker base
OR
2) (normal elab) e- overlap with the orbital of another atom more effective, bond is stronger and bond length is shorter

17
Q

state and explain the difference in bond angles using VSEPR.

A
  • e- pairs arranged as far apart to minimise e- repulsion
  • lp-lp repulsion > lp-bp > bp-bp > lone e- -bp
  • increase in repulsion, bond angle decreases
18
Q

why is Al2O3 an amphoteric oxide?

A

Al 3+ has high charge density/polarizing power which is able to polarise the electron cloud of O2− /anion , hence giving the oxide some covalent character.

Therefore, Al2O3 has a giant ionic lattice structure with covalent character, making it an amphoteric oxide that reacts with both acids and alkalis.

19
Q

state the reactivity of oxides to acid/bases.

A

MgO is an ionic oxide. Hence it is basic and is able to react with acids.
MgO + 2HCl → MgCl 2+ H2O

SO 3 is a covalent oxide, hence it is acidic and is able to react with bases.
SO3 + 2NaOH → Na2SO 4+ H2O

Al2 O3 : amphoteric oxide hence it react with both acids and bases.
Al2O3 + 6HCl → 2AlCl 3+ 3H2O
Al2O3 + 2NaOH + 3H2O → 2Na[Al(OH)4]

20
Q

is lattice energy of CaCl2 more or less exothermic than that of NaCl?

quote values from DATA BOOKLET!!!

A

Ca 2+ (r + = 0.099 nm) is bigger than Na + (r + = 0.095 nm).

But CaCl 2 comprises doubly-charged Ca 2+ whilst NaCl comprises singlycharged Na+ .

Since ionic charge is the **predominant factor **in affecting magnitude of lattice energy, the lattice energy of CaCl 2 is more exothermic than that of NaCl.

lattice energy is the energy evolved (exothermic)

21
Q

formation of a dative bond

A

one atom must have lone pair of e- to be donated
another atom must have vacant, low-lying orbital to accept the pair of e-

22
Q

what is SP hybridisation?

from sp3 to sp, decrease in p orbitals that mix with 2s orbitals

A

sp hybridisation results when one 2s and one 2p orbital of C mix to form two sp hybrid orbitals. There are two unhybridised p-orbitals in C. (unhybridised p orbital forms the pi bond)

make sense there is 2 unhybridised as there are c triple bonds in SP

23
Q

why entropy increases when temp increase

A

there is a increase in disorder of the system:
* temp ↑, KE ↑
* broadening of the energy distribution of the particles
* more possible energy states particles can adopt at higher temperature
* increase in entropy

24
why entropy increase when changing from solid to liquid
there is a increase in disorder of the system: * ions are no longer held in fixed positions in the ionic lattice * as they become free-moving aqueous ions * increasing the disorder
25
Why does thermal stability of grp 2 peroxides decrease down the group?
* cationic radius increases, charge density decreases, weaker polarising power of the cations * decreasing extent of distortion of the electron cloud of the peroxide anion * decreasing extent of weakening of **covalent bond** within the peroxide anion * More heat energy is required to break the covalent bonds within the O 2 2– anion, causing the decomposition temperature to increase. * Hence, thermal stability of the Group 2 peroxides increases down the group. | distortion decrease as polarising power decrease
26
describe the thermal stability of Group 2 carbonates | SIGMA IMPTTTTTTTTTTt
Down Group 2, **cationic radius** increases, resulting in a **lower charge density** and **weaker polarising power** of the cations. consequently, there is decreasing **extent of distortion** of the electron cloud of the CO 3 2– anion and hence decreasing **extent of weakening** of covalent bonds within the CO 3 2– anion. more heat energy is required to break the covalent bonds within the CO 3 2– anion, causing the decomposition temperature to increase. hence, thermal stability of the Group 2 carbonates **increases**. | increase in thermal stability = increase temp needed for decomposition
27
Why does id-id and pd-pd arise
Electrons are constantly moving and at any given moment, the electron density of a phosgene molecule can be unsymmetrical, resulting in an instantaneous dipole, which induces a short-lived dipole in a neighbouring phosgene molecule, hence resulting in id-id interactions. Phosgene molecules are polar with permanent dipoles in their structures. Pd-pd interactions arise due to the electrostatic attraction between the + end of one phosgene molecule and the – end of the other phosgene molecule.
28
Why Kp remain unchanged when catalyst added?
A catalyst lowers the activation energy of both the forward and backward reactions to the same extent. Hence, the rates of both the forward and backward reactions are increased to the same extent, and the equilibrium position and Kp remains unchanged.
29
Why Kp remain unchanged when catalyst added?
A catalyst lowers the activation energy of both the forward and backward reactions to the same extent. Hence, the rates of both the forward and backward reactions are increased to the same extent, and the equilibrium position and Kp remains unchanged.
30
From F to Br state why do they deviate more from ideal gas down the group?
All 3 halogen has id-id attraction b/w its molecules Electron cloud size increase from F to Br Greatest distortion of e- cloud for bromine and stronger and more extensive idid in Br Br deviate most from ideal gas
31
why entropy decreases when no. of particles decreases?
* no. of particles decreases, decrease in the amount of ways to distribute energy in the gaseous particles, less disorder in the system, decrease in entropy