Coordinate Plane Flashcards
(38 cards)
Line a is perpendicular to line b. If the slope of line a is a positive integer, then the product of the slopes of lines a and b cannot equal
(a) -5
(b) -1
(c) 1
(c) 1
Lines a and b are perpendicular which means that their slopes are the opposite reciprocals of each other. Therefore, their product cannot be a positive number.
Which point is not going to be on the line described by the following equation y = kx + k?
(a) (1, 2k)
(b) (0, k)
(c) (2, 3k)
(d) (0, -k)
(d) (0, -k)
Realize that you are given the x and y coordinates of four points in question and the linear equation in the slope-intercept form. Plug in the coordinates of each point into the equation and find the point whose coordinates prove the equation false.
For example, plugging in choice (c) you get 3k = k * 2 + k; 3k = 3k which is true. Choice (d) results in -k = k which is false.
If point A with coordinates (x, y) is in quadrant III, then point B with coordinates (-x, -y) is in quadrant …?
(a) Q I
(b) Q II
(c) Q III
(d) Q IV
(a) Q I
Since point A is located in Q III, both x and y are negative. Negative of a negative is positive therefore, the coordinates of point B are both positive. In Q I both x and y coordinates are positive.
Write the equation of the line that is parallel to the line y = 36x - 12 and passes through the origin.
y = 36x
If the line passes through the origin, its y-intercept is zero. Two lines are parallel, therefore, their slopes are equal.
Line m is perpendicular to line p. If the slope of line p is a non-zero integer, then the slope of p divided by the slope of m could equal
(a) 1/9
(b) 9
(c) -1/9
(d) -9
(d) -9
Lines m and p are perpendicular which means that their slopes are the opposite reciprocals of each other. Therefore, their quotient cannot be a positive number. Eliminate choices (a) and (b).
Since the slope of line p is an integer, the slope of line m is a fraction. Dividing by a fraction is the same as multiplying by an integer. So, the right answer is an integer. The only choice that satisfies all conditions is choice (d).
There are four parallel lines. Each line has an integer slope. The product of their slopes could be…?
(a) negative
(b) prime
(c) 0
(d) 1/8
The product of their slopes could be 0, choice (c).
Parallel lines have equal slopes. The slopes of each of four lines can be positive or negative integers but their product will always be positive. Eliminate (a). The product of slopes cannot be a prime number since there are four factors. Eliminate (b). The product of four integers cannot be a fraction. Eliminate (d).
If the coordinates of the vertices of a rectangle are
A(2, 0), B(2, 4), C(5, 4), D(5, 0),
what is the distance between the vertices that lay on its diagonal?
The distance between two points on a diagonal of the rectangle ABCD is 5.
The diagonal vertices are A and C or B and D. Use distance formula to answer the question without graphing the rectangle.
Working with points A and C, you get (4 - 0)2 + (5 - 2)2 = 25. The square root of 25 equals 5. d = 5.
Find the midpoint between two points with the coordinates (5, 7) and (-3, -5).
The coordinates of the midpoint are (1,1).
You don’t have to memorize the formula as long as you know the concept that finding the midpoint is like finding the average of the x and the y coordinates of the two points in question.
So, 5 + (-3)/2 = 1
7 + (-5)/2 = 1
If A(4, 6) is the midpoint of DC with D = (1, 2) and C = (x, y), what are the values of x and y?
The value of x is 7, the value of y is 10.
Since A is the midpoint of DC,
(1 + <em>x</em>)/2 = 4
(2 + <em>y</em>)/2 = 6
Now solve for x and y.
Without graphing, find the x and y intercepts of the line described by the following equation.
y = -2x + 2
- The x-intercept of this line is 1
- The y-intercept of this line is 2
- y* equals zero at the x-intercept.
- 2x + 2 = 0 ⇒ x = 1
- x* equals zero at the y-intercept.
- y* = 2
What is a coordinate plane used for?
A coordinate plane is used to graph ordered pairs, straight lines and functions.
The lines below have the same graph.
y = 4x - 6
1/2y = mx + b
Find the product of m and b.
m * b = ?
m * b = -6
The lines with the same graph have equal slopes and y-intercepts.
You can either divide the first equation by 2 or multiply the second equation by 2 to compare them.
- y* = 4x - 6
- y* = 2mx + 2b
Since the slopes and the y-intercepts are equal, conclude that 2m equals 4 and 2b equals -6.
- m* = 2; b = -3
- m * b* = -6
What is the definition of an ordered pair?
An ordered pair is two numbers written in a specific order.
It is used to locate a point on a coordinate plane.
Usually denoted (x,y) where x and y are the coordinates of the point.
Example:
A (3, -8)
B (-6, -2)
How do you plot a point on a coordinate plane?
To plot a point, you need to know the x and y coordinates of that point (the ordered pair).
- a point with (0,0) coordinates is the origin
- a point with (0,y) is the point on y-axis
- a point with (x,0) is the point on x-axis
The graph of y = 5 is perpendicular to the graph of?
(a) y = 0
(b) y = x + 5
(c) x = 5
(c) x = 5
There are four quadrants in a coordinate plane. They are labelled with Roman numerals I, II, III, IV, starting at the positive x-axis and going around anti-clockwise.
In which quadrant are both x and y coordinates of a point
- positive?
- negative?
- The x and y coordinates of a point are both positive in the first quadrant (QI)
- The x and y coordinates of a point are both negative in the third quadrant (QIII)
- x* > 0; y > 0 - first quadrant
- x* < 0; y < 0 - third quadrant
There are four quadrants in a coordinate plane. They are labelled with Roman numerals I, II, III, IV, starting at the positive x-axis and going around anti-clockwise.
In which quadrant(s) do the x and y coordinates of a point have different signs?
The x and y coordinates of a point have different signs in the second and the fourth quadrants (Q II and Q IV).
- x* < 0; y > 0 - second quadrant
- x* > 0; y < 0 - fourth quadrant
In which quadrant(s) lie the points with the coordinates x and y such as xy < 0?
Those points lie in the second and the fourth quadrants (Q II and Q IV).
The question is asking you to find the points with different sign coordinates since the product of x and y must be negative.
- x* < 0; y > 0 - second quadrant
- x* > 0; y < 0 - fourth quadrant
How do you find the slope of a line when given the coordinates of two points on that line?
point A (3;4)
point B (2;1)
The slope of a line is the rise of that line over the run.
The rise: yB - yA = 1 - 4 = -3
The run: xB - xA = 2 - 3 = -1
The slope is -3/-1 = 3.
What is true about the slopes of two perpendicular lines? (excluding vertical and horizontal lines)
(a) their quotient equals 1
(b) their product equals -1
(c) their absolute values are equal
(d) none of the above
(e) all of the above
(b) The product of the slopes of two perpendicular lines equals -1.
The slopes of perpendicular lines are the opposite reciprocal of each other.
What is true about the slopes of two parallel lines? (excluding vertical and horizontal lines)
(a) their quotient equals 1
(b) their product equals -1
(c) their absolute values are equal
(d) both (a) and (c)
(e) all of the above
(d) both (a) and (c)
The slopes of parallel lines are equal so their quotient equals 1. Naturally, the same numbers have the same absolute values.
If given an equation of a line, how do you find its slope?
ax + ky = c
To find the slope of a line from an equation, put the equation into the slope-intercept form.
y = mx + b where m is the slope
- ax + ky = c*
- ky = c - ax*
y = c/k - a/kx
This is the slope-intercept form of the standard form of the equation. The slope equals - a/k.
Which of the following lines is parallel to the line y = 7 - 5x?
- I. y = 7 + 1/5x
- II. y = -7 - 5x
- III. y = 7 + 5x
(a) I only
(b) II only
(c) III only
(d) none of the above
(b) II only
The slopes of parallel lines are the same. Only II has the same slope as the line given in the question stem.