Core Organic Chemistry Flashcards

(33 cards)

1
Q

3 reasons carbon can form so many compounds.

A
  • can form 4 covalent bonds with other atoms
  • can form single, double or triple bonds
  • can bond to other c atoms to form chains
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2
Q

define hydrocarbon

A

A compound containing carbon and hydrogen only

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3
Q

define aliphatic

A

relating to or denoting organic compounds in which carbon atoms form open chains

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4
Q

define alicyclic

A

relating or denoting to organic compounds that combine rings and chains / cyclic and aliphatic properties

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5
Q

define aromatic

A

organic compounds containing a planar unsaturated ring of atoms which is stabilised by the bonds forming the ring. possibly including a benzene ring

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6
Q

define saturated

A

.a molecule or substance where the atoms are only linked with single bonds

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7
Q

define unsaturated

A

.a molecule or substance containing non-single bonds

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8
Q

define homologous series

A

a series of organic compounds which have the same functional group but with each succesive memberdiffering by one CH2

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9
Q

define functional group

A

a group of atoms responsible for the characteristic rections of a compound

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10
Q

General formula for alkanes

A

C(n)H(2n+2) (saturated chain)

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11
Q

General formula for cycloalkanes

A

CnH2n (saturated circle of bonds)

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12
Q

General formula for alkynes

A

C(n)H(2n-2) (includes a triple bond)

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13
Q

skeletal formula

A

A simplified organic formula with hydrogen atoms removed from alkyl chains leaving just carbon skeleton and associated functional groups

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14
Q

Displayed formula

A

The relative positioning of all the atoms in a molecule, including bonds between them

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15
Q

Alkane (formula of functional group)

A

C-C

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16
Q

Alkene functional group formula

17
Q

Haloalkane functional group formula

A

R-I
R-Cl
R-Br
etc.

18
Q

Alcohol functional group

19
Q

Aldehyde functional group

A

R-C(-H)=O
Trigonal planar structure where R is a C chain or a hydrogen

-al

20
Q

ketone functional group

A

R-C(-R)=O
R is only a C chain

-one

21
Q

Carboxcylic acid functional group

A

R-C(-OH)=O
R is a H or a C chain

-oic acid

22
Q

Define structural isomers

A

Same molecular formula but different Displayed formula

23
Q

3 types of structural isomers

A

Chain isomer
-hydrocarbon chain may be branched or unbranched
-stem names for these isomers are different
Position isomer
- The hydrocarbon chain stays the same in these isomers but the position of the functional group is found at different points along the chain
- the numbers are different
Functional group isomer
-The functional group is different
-the prefix or suffix is different in the naming eg, cyclo- and -enes could have the same molecular formula

24
Q

Define an Alkane

A

Saturated hydrocarbons

25
General hydrocarbon of formula CxHy combustion
CxHy + (x + 1/4y)O2 -----> xCO2 + 0.5yH2O
26
Why is incomplete combustion dangerous?
carbon monoxide is toxic and can cause death by preventing haemoglobin from carrying oxygen to respiring tissues Because CO is colourless and odorless it can be difficult to detect
27
Why are yellow flames from Bunsen burners yellow?
The yellowness is caused by glowing soot particles indicating incomplete combustion, the outside of any glassware used will become blackened with soot.
28
Reaction of alkanes with halogens /HCl
Substitution reaction CH4 + Br2 -----> CH3Br + HBr UV light is required as it provides the energy to break initial bonds
29
Define a radical //notaion
A radical is a species with an unpaired electron A dot similar to a bullet point after the element
30
Radical substitution 3 stages?
initiation, propagation, termination
31
Radical substitution, stages, info and equations
* = to the bullet point thingy Initiation stage initiation generates radicals for the reaction Br2 ----UV-----> 2Br* UV light provides energy required for the HOMOLYTIC bond breaking of Br-Br Because the covalent bond between the Br's contains two shared electrons, when this bond is broken both atoms recieve one of the two shared electrons. Giving both atoms an unpaired electron and creating radicals Propagation stage for every radical used in this reaction a new radical is produced. Br* + CH4 ---> HBr + CH3* CH3* + Br2 -----> CH3Br + Br* ``` Termination stage 2 radicals combine to produce a product that is not radical CH3* + Br* -----> CH3Br Br* + Br * -----> Br2 CH3* + CH3* ------> C2H6 ```
32
By reacting propane with bromine a chemist tried to make 1-bromo propane. WHat mixture of products did he make and how were they formed?
1-bromopropane -- formed by simple radical substitution 2-bromopropane -- formed by substitution at a different point in the C chain 1,1(/1,2/1,3) -dibromopropane ---was formed by further substitution Hexane --- when two C3H7* combined 1-bromohexane ---- substitution of the hexane side product 2,3,5-tribromohexane -- formed by multiple substitution of hexane side product
33
3 limitations of radical substitution
-Further substitution can occur -Substitution at different points of C chain can occur - C chain may change length / double It is difficult to synthesis only 1 product