DC Circuit Flashcards

(20 cards)

1
Q

What is Electromotive Force (EMF)?

A

The amount of energy given to each coulomb of charge to go around the circuit once.

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2
Q

What is Potential Difference (p.d.)?

A

Work done per unit charge; energy transformed from electrical to other forms per unit charge.

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3
Q

What is the difference between EMF and p.d.?

A

EMF is energy supplied to the circuit per unit charge; p.d. is energy used per unit charge.

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4
Q

What is Internal Resistance?

A

Resistance inside the power source that reduces the p.d. when current flows.

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5
Q

What equation defines voltage across a resistor?

A

V = IR

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6
Q

What equation defines voltage lost due to internal resistance?

A

V = E − Ir

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7
Q

What is the total EMF equation in a circuit with internal resistance?

A

E = IR + Ir

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8
Q

Rearranged EMF equation factoring total resistance:

A

E = I(R + r)

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9
Q

What is Kirchhoff’s First Law?

A

Sum of currents into a junction = sum of currents out; conservation of charge.

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10
Q

What is Kirchhoff’s Second Law?

A

Sum of EMFs = Sum of potential differences in a closed loop; conservation of energy.

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11
Q

Effective resistance in series?

A

R = R1 + R2 + … + Rn

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12
Q

Effective resistance in parallel?

A

1/R = 1/R1 + 1/R2 + … + 1/Rn

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13
Q

What is a potential divider?

A

A circuit that splits voltage into smaller parts using resistors.

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14
Q

How does a thermistor behave in a potential divider?

A

Resistance decreases as temperature increases.

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15
Q

How does an LDR behave in a potential divider?

A

Resistance decreases as light intensity increases.

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16
Q

What is a potentiometer?

A

A continuously variable potential divider used to compare potential differences.

17
Q

How is p.d. related to length in a potentiometer wire?

A

Potential difference is proportional to the length from the reference point.

18
Q

Use of potentiometer to compare EMFs?

A

Move the slider until the galvanometer reads zero; use length ratio to compare EMFs.

19
Q

Formula to compare EMFs using potentiometer:

A

E1/E2 = L1/L2

20
Q

If E1 = 10 V, XY = 1 m, XT = 0.4 m, what is E2?

A

E2 = (0.4/1.0) × 10 = 4 V