Definitions/Theorems to Know Flashcards
(6 cards)
Precise Definition of a Limit
Let ๐(๐ฅ) be defined for all ๐ฅ โ ๐ over an open interval containing a. Let L be a real number. Then,
lim ๐ฅ โ ๐ ๐(๐ฅ) = ๐ฟ
If, for every ๐ > 0, there exists a ๐ฟ > 0, such that if 0 < |๐ฅ โ ๐| < ๐ฟ, then |๐(๐ฅ) โ ๐ฟ| < ๐.
Proof Statement for Precise Definition of a Limit
Choose a ๐ฟ = ___. Thus, it follows that if 0 < |๐ฅ โ ๐| < ___, then |๐(๐ฅ) โ ๐ฟ| < ๐. This completes the proof.
A function is continuous ifโฆ
It can be drawn on a graph without lifting the pencilโ meaning thereโs no sudden jumps, holes, or breaksโand at every point the functionโs value is equal to the limit at that point.
A function is differentiable ifโฆ
Its derivative exists at every point in its domainโ meaning it is continuous and doesnโt have any sudden changes in slope.
Conditions for Mean Value Theorem and Conclusion
Ifโฆ
1) Function is continuous on the closed interval [a,b]
2) The function is differentiable on the open interval (a,b)
Thenโฆ
There exists a point c in the interval (a,b) such that fโ(c) is equal to the functionโs average rate of change over [a,b], f(b) - f(a) / b - a
Steps to Solving Can Minimization Problem
1) Form surface area equation
2) Express h in terms of r using volume equation and plug into area equation, this is now the function
3) Determine domain of the function in context of the problem (0,โ)
4) Take the derivative of the function and find the critical points
5) Use the first derivative test to confirm the minimum
6) Find the full dimensions