Derivations Flashcards

(14 cards)

1
Q

Superheterodyne Reciever

A

multiplication of two signals

carrier signal sc(t) and local oscillator slo(t)

sc(t) * slo(t) = sin(2πfct) * sin(2πflot)

sin(x) = (e^ix - e^-ix) / 2i

answer

sc(t) * slo(t) = 1/2 cos(2π(fc-flo)t) - 1/2cos(2π(fc+flo)t)

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2
Q

Radar Equation - Simple

A

Isotropic antenna and no attenuation loss

Power density = Pt/4πR^2

Including gain

Power density = PtGt/4πR^2

Encapsulate reflectivity by assuming an isotropic source

Pr = PtGtσ/4πR^2

Returns the observed echo power flux at the recieving antenna

Pr = PtGtσ/(4πR^2)^2

G = 4πAe/λ^2

Pr = PtGtσAe/(4πR^2)^2

Rearrange for R

Rmax occurs when Pr = Smin

Monostatic Radar when Gt = Gr = G

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3
Q

Radar Equation - Including System Noise

A

Reciever Noise

N = k To βn

βn = ∫ |H(f)|^2 df / |H(f0)|^2

Noise figure

Fn = Nout/kToβnGa

or Fn = Sin/Nin / Sout/Nout

Rearrange for Sin and subsitute Nin = k To βn

Smin occurs when we have (Sout/Nout)min

Subsitute this into our Radar equation

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4
Q

Radar Equation - Pulse Integration

A

Integration efficiency factor

Ei(n) = (S/N)1 / n(S/N)n

integration improvement factor

Ii(n) = nEi(n)

putting into Radar equation

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5
Q

Surveillance Radar Equation

A

Draw diagram

L1 x L2 = Ae

Tscan = Ti . φ/θ

rearrange for θ

n = fp Ti

θ = λ^2/Ae

substitute for θ and rearrange for Ae (1)

The average power of a pulse train is

Pav = Pt τ fp = Pt fp/β (2)

recall simple Radar equation in the form of Ae^2 substitute (1) and (2)

cancel and rearrange as required

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6
Q

Doppler frequency shift

A

phase length of the two-way path

φ = 2π/λ . 2R
φ = 4π/λ . R

moving target -> rate of change is

dφ/dt = ω = 4π/λ . dR/dt

dR/dt = vr

fd = ω/2π

=> fd = 4π/2πλ . vr

fd = 2vr/λ

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7
Q

Matched Filter

A

Noisy input to the IF is the signal to be recovered plus additive Gaussian noise

r(t) = s(t) + n(t)

where n(t) has spectral height N0/2

Output of the filter is given by the convolution integral

y(t) = (t ∫ 0) r(τ) h(t-τ) dτ

signal part

ys(t) = (t ∫ 0) s(τ) h(t-τ) dτ

noise part

yn(t) = (t ∫ 0) n(τ) h(t-τ) dτ

SNR = ys^2(t)/E[yn^2(t)]

denominator

E[yn^2(t)] = E{[(t ∫ 0) n(u) h(t-u) du][(t ∫ 0) n(v) h(t-v) dv]}

= N0/2 (t ∫ 0) h^2(t-u) du

numerator

Cauchy-Schwartz inequality

<S,Q>^2 <= |S|^2 |Q|^2

=> [(t ∫ 0) s(u) h(t-u) du]^2 <= (t ∫ 0) s^2(u) du (t ∫ 0) q^2(u) du

equality is reached when q(u) = cs(u)

=> [c (t ∫ 0) s(u) du]^2

putting it back together we get the SNR maximised when h(t-u) = cs(u)

SNR = 2/N0 (T ∫ 0) s^2(u) du

SNR = 2εs/N0

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8
Q

Matched Filter Frequency Response

A

Take the Fourier Transform of the Impulse response function

H(f) = c (T ∫ 0) s(T-u) exp(-i2πfu) du

r = T - u

u = T - r

du = -dr

u = 0 -> r = T and u = T -> r = 0.

= cexp(-i2πfT) (T ∫ 0) s(r)exp(i2πfr) dr

= cexp(-i2πfT) [ S(f)]*

=> |H(f)| = c|S(f)|

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9
Q

Radiometry

A

L = d^2φ/dAdΩ

φ = LAsΩd

Where

Ωd = Adcosθd/r^2

It is θd or θs depending on what is given

If the source and detector are parallel θd = θs =θ

θs = tan ^(-1)(r/h)

use trig to find r based on the variables given

For off axis detection include another cos term

For a point source φ = I ΩL

ΩL = AL/r^2

E = dφ/dA

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10
Q

Lambertian Source

A

φh = ( ∫ h) LAscosθsdΩd

using spherical coordinates

φh = LAs2pi 1/2

M = dφ/dA

M = Lπ

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11
Q

Fly-past dynamics

A

y1 = x0 y1(dot) = 0
x1 = x0/tan(A)

x1(dot) = -V = d/dt(xac)

use the chain rule

x1(dot) = -V = -x0/sin^2(A) dA/dt

rearrange for dA/dt

for second derivative use the chain rule again and subsitute for dA/dt

use double angle trig sin2x = 2sinxcosx

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12
Q

Delay line canceller

V1 = ksin(2πfdt - Φ0)

A

V1 = ksin(2πfdt - Φ0)

V2 = ksin[2πfd(t-Tp) -Φ0]

V1-V2

sinA-sinB = 2sin[(A-B)/2]cos[(A+B)/2]

determine A-B/2 and A+B/2

Substitute back into V1-V2

Only consider the sign term and divide by k

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13
Q

Fourier transform tutorial 1

g(t) = Arect(t/T)cos(2πfct)

rect(t) = { 1 , -1/2 < t < 1/2
{ 0 , t > 1/2

A

Fourier transform
H(f) = (inf int -inf) f(t) exp(-2πft) dt

Substitute rect into g(t) and change the limits this is f(t)

Convert cos to exponential

Take the integral using the limits

Convert to sin upon completion of the integral

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14
Q

Doppler shift for a pulse Doppler radar for a single delay line canceller.

A

r12 = r1 - r2

||r12|| = sqrt{(x1-x2)^2 + (y1-y2)^2}

Take time derivative

d||r12||/dt = [(x1-x2)(x1(dot)-x2(dot)) + (y1-y2)(y1(dot)-y2(dot)]/||r12||

x1(dot) = v1 sin φ1
y1(dot) = v1 cos φ1

x2(dot) = v2 sin φ2
y2(dot) = v2 cos φ2

fd = -||r12||/lambda

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