Discovery of an Electron and Electron Diffraction Flashcards

(32 cards)

1
Q

What is thermionic emission?

A

The release of electrons from a heated cathode due to the energy supplied by heat, similar to the photoelectric effect but with thermal energy.

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2
Q

What is meant by β€˜specific charge’ of an electron?

A

Specific charge is the charge-to-mass ratio of a particle:

𝑒/π‘š.

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3
Q

What equation relates kinetic energy to accelerating potential?

A

π‘’π‘‰π‘Ž = 1/2 π‘šπ‘£Β², where π‘‰π‘Ž is the accelerating potential.

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4
Q

How is speed of an accelerated electron calculated?

A

𝑣 = √(2π‘’π‘‰π‘Ž/π‘š).

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5
Q

Method 1 - Parallel plates with electric & magnetic fields: What’s the principle?

A

Balance electric and magnetic forces:

𝐸𝑒 = 𝐡𝑒𝑣 β‡’ 𝑣 = 𝐸/𝐡.

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6
Q

Method 2 - Magnetic field only (circular path): Key formula?

A

𝐡𝑒𝑣 = π‘šπ‘£Β²/π‘Ÿ β‡’ 𝑒/π‘š = 𝑣/(π΅π‘Ÿ).

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7
Q

Method 3 - Parabolic motion in electric field (no magnetic field): Why less common?

A

Requires electron speed, which depends on 𝑒/π‘š, making the method somewhat redundant.

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8
Q

What did Millikan’s experiment measure?

A

The charge of a single electron.

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9
Q

What forces act on an oil droplet at terminal velocity?

A

Gravitational force π‘šπ‘” = drag force 6πœ‹πœ‚π‘Ÿπ‘£.

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10
Q

How was radius of the droplet found?

A

Using π‘Ÿ = (9πœ‚π‘£Β²)/(2πœŒπ‘”).

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11
Q

How did Millikan calculate charge on a droplet?

A

When levitated in an electric field:

πΈπ‘ž = π‘šπ‘” β‡’ π‘ž = (π‘‰π‘š)/(𝑔𝑑).

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12
Q

What fundamental value did Millikan deduce?

A

𝑒 = 1.6 Γ— 10⁻¹⁹ C, the elementary charge.

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13
Q

What does electron diffraction demonstrate?

A

Electrons act like waves, showing interference patternsβ€”evidence of wave-particle duality.

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14
Q

What is the de Broglie wavelength formula?

A

πœ† = β„Ž/(π‘šπ‘£), where β„Ž is Planck’s constant.

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15
Q

Why do larger particles not diffract noticeably?

A

Their mass is too large, making πœ† too small to observe.

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16
Q

How do we adjust electron speed to observe diffraction?

A

Electrons must be fast enough to pass through foil but not too fastβ€”higher speed β†’ smaller πœ†.

17
Q

Why do electrons accelerate toward the anode?

A

Because of the electric field created by a potential difference between the negatively charged cathode and the positively charged anode.

18
Q

What form of energy do electrons gain during acceleration?

A

Kinetic energy: πΈπ‘˜ = 1/2 π‘šπ‘£Β².

19
Q

How is potential difference related to energy and charge?

A

𝑉 = πΈπ‘ž β‡’ 𝐸 = π‘žπ‘‰.

20
Q

How do you calculate electron speed from an electron gun?

A

𝑣 = √(2π‘’π‘‰π‘Ž/π‘š), where π‘‰π‘Ž is the accelerating voltage.

21
Q

How is electric field strength between plates calculated?

A

𝐸 = 𝑉/𝑑, where 𝑑 is the separation between plates.

22
Q

What force acts on an electron in an electric field?

A

𝐹 = 𝑒𝐸.

23
Q

What direction is force on a moving charge in a magnetic field?

A

Perpendicular to both the velocity and the magnetic field (Fleming’s Left Hand Rule).

24
Q

What provides centripetal force in electron circular motion in a magnetic field?

A

Magnetic force: 𝐹 = 𝐡𝑒𝑣 = π‘šπ‘£Β²/π‘Ÿ.

25
Final expression for specific charge using circular path method?
𝑒/π‘š = (2π‘‰π‘Ž)/(π΅Β²π‘ŸΒ²).
26
Why is the parabolic motion method less reliable for specific charge?
Because 𝑒/π‘š appears in both time and acceleration, often cancelling out.
27
Final form of specific charge from this method?
𝑒/π‘š = (𝑑²𝑣²)/(𝑉𝑙²), where 𝑉 is the PD across plates.
28
Why does electron diffraction occur with metal foils?
The gaps between atoms (~picometer scale) are small enough to cause wave-like diffraction of electrons.
29
What pattern does electron diffraction produce on a screen?
Concentric rings (fringes), similar to optical interference patterns.
30
What does this pattern prove?
Electrons have wave-like properties; supports de Broglie’s hypothesis.
31
Who proposed matter has a wavelength?
Louis de Broglie (1920s).
32
Why don’t we see diffraction in large objects like humans?
Their de Broglie wavelength is extremely small due to large mass, making diffraction unobservable.