eigensystems and canonical forms take 2 Flashcards
(34 cards)
eigenvector:
a vector x is an eigenvector of A (a square matrix) if x is nonzero and Ax=λx where λ is a scalar
eigenvalue:
a scalar λ is an eigenvalue of A (a square matrix) if λ is nonzero and Ax=λx where x is nonzero
eigenpair:
an eigenvector and its associated eigenvalue, each eigenvector has one eigenvalue but each eigenvalue has many associated eigenvectors
characteristic polynomial:
p(λ)=det(λI-A)=0
spectrum:
set of all eigenvalues of A, written Λ(A)
algebraic multiplicity:
of λ, its multiplicity as a 0 of the characteristic polynomial, which I Think means the number of times λ appears as a root of p(λ)?
invariant subspace:
a subspace X in C^n is invariant for A if AX in X, that is, x in X implies Ax in X
matrices and subspaces:
let the columns of X in C^(nxp), p<=n, form a basis for a subspace Y of C^n, then Y is an invariant subspace for A iff AX=XB for some B in C^(pxp). when the latter holds, the spectrum of B is contained within the spectrum of A
similar:
A and B (both square) are similar if there exists a nonsingular matrix P such that B=P^(-1)AP
similarity transformation:
P^(-1)AP
transforming matrix:
P in a similarity transformation
unitarily similar:
B=U*AU where U is a unitary matrix
orthogonally similar:
A and B are real, B=U^(T)AU where U is a real orthogonal matrix
diagonalisable:
if a matrix A is similar to a diagonal matrix, A is diagonalisable or simple
schur’s theorem:
let A be square, then there exists a unitary matrix U and an upper triangular matrix T such that T=U^(-1)AU=U*AU
schur decomposition:
A=UTU*, equivalent to T=U^(-1)AU
schur vectors:
the columns of U
normal:
a matrix is normal if AA=AA
spectral theorem:
let A be square, then A is normal iff there exists a unitary matrix U and diagonal matrix Λ such that A=UΛU*
normalcy and orthogonal vectors:
an nxn matrix A is normal iff it has n orthogonal eigenvectors
diagonalisability and eigenvectors:
a square matrix A is diagonalisable iff A has n linearly independent eigenvectors
diagonalisability and eigenvalues:
a matrix with distinct eigenvalues is diagonalisable
the jordan canonical form:
any square matrix can be expressed in the form X^(-1)AX=J=
[J1(λ1)
…
Jp(λp)]
Jk=Jk(λk)=
[λk 1
λk 1
… …
1
Ak] in C^mkxmk
where X is nonsingular and m1+…+mp=n
jordan block:
the mkxmk matrices in the jcl