electricity - shocking! Flashcards

(15 cards)

1
Q

potential energy of charges

A

PE=-qEdeltaX

PE= QV

Why does this work?

Well, E= V/x, so in essence

PE=qV/x*x or simply

PE=qV

Note also that qE=F (electric force equals charge times electric field, the go between equation) SO really the first equation is no more than force*distance (work)

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2
Q

Voltage

A

kq/r

charge per distance

V=Q/Capacitance

Joules/coulomb

Work per charge

To increase voltage means to increase the amount of work that each charge can do.

Also, V=electric field * distance

kq/d^2*d= kq/d

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3
Q

Does it take energy to move a charge along an equipotential line? why or why not?

A

PE = QdeltaV

If the voltage doesn’t change, then no work is done

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4
Q

Capacitors

A

C=Q/V

coulomb/volt

charge per (charge per distance or work per charge)

epsilonA/d

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5
Q

Explain why a dielectric increases the maximum operating voltage of a capacitor even though the physical size of the capacitor doesn’t change.

A

The material of the dielectric may be able to withstand a larger electric field than air can withstand before breaking down to pass a spark between the capacitor plates.

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6
Q

When a dielectric is introduced, does the voltage go up or down?

A

Down

Being said, the battery’s voltage does not change. Does this mean that the voltage between the plates can actually be greater than the battery?

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7
Q

What is the potential energy of a capacitor?

A

PE=1/2QV

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8
Q

When you add a dielectric, what do you do??

A

C=KCnaught

C=KepsilonA/d

You can increase capacitance by increasing area, decreasing distance.

C=Q/V

You can also increase capacitance by decreasing the voltage (like using a dielectric).

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9
Q

When you are wondering about capacitance and electric fields and the possibility that the dielectric might break down, what do you remember?

A

C=Q/V

and V=electric field times distance

Often you’re not going to be given the voltage, but you’ll prob be given a distance and a max field strength before breakdown. There ya go.

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10
Q

capacitors in series

A

capacitance is the product/sum

charges same

I=I1=I2=I3=…

voltages add

V=V1+V2+V3+…

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11
Q

capacitors in parallel

A

capacitance simply adds

charges simply add

voltage is the same

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12
Q

resistors in series

A

resistance simply adds

current same

voltage adds

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13
Q

resistors in parallel

A

resistance is product/sum

different current

same voltage

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14
Q

power?

A

P=IV

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15
Q

plate of charges

A

E=Q/2epsilonA

parallel plate

E=Q/epsilonA

bc the positive negative plates reinforce each other

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