Electrolysis Flashcards
(18 cards)
suggest ONE way to remove ions of metal which are LESS REACTIVE than zinc from the zinc sulphate solution before electrolysis
Add Zn(s)/ Mg(s)/ Al(s) to DISPLACE ions of less reactive metals
Why it is NOT necessary to remove ions of metals which are MORE REACTIVE than Zn from the solution
- Zn2+ ions will be preferentially discharged
- ions of more reactive metals will remain in the solution
( Zn > ↑reactive metal in E.C.S/ Zn is a stronger oxidizing agent)
Y car bumpus coated with a layer of nickel prior to the chromium-planting process
- As an undercoat
- to protect the steel from corrosion
after the chromium layer has been scratched off
Y H2SO4(aq) is used in the chromium-plating bath
- To increase electrical conductivity/
2. To provide mobile ions
Y H2SO4(aq) is used in the chromium-plating bath
- To increase electrical conductivity/
2. To provide mobile ions
Why the volume of chlorine collected is significantly smaller than theoretical volume
- Chlorine dissolves in water
Cl2(aq) + H2O(I)→ HOCl(aq) + HCl(aq)
Why the volume of chlorine collected is significantly smaller than theoretical volume
- Chlorine dissolves in water
Cl2(aq) + H2O(I)→ HOCl(aq) + HCl(aq)
Advantages of carrying out experiments in MICROSCALE
- Reduce chemical waste produced
- Shorten the time required for conducting an experiment
- Require less working space for carry out an experiment
state what will happen to the bulb
when heating is stopped
and
the molten lead(ll) bromide is allowed to cool down gradually room temperature
The light bulb gradually goes out.
1. T°C↓,
→movement of ions slow down
→a smaller current flows through the external circuit
2. When PbBr2 becomes solid,
→Ions are no longer mobile
→no currents flow through the external circuit
Is it possible to deuce the formula of water from the results of the electrolysis
(Cathode: 2H+(aq) +2e- → H2(g))
(Anode: 4OH-(aq)→ O2(g) + 2H2O(l)+ 4e-)
√
1. volume of H2(g) collected : volume of O2(g) collected
= 2:1
2. In water, H & O combine in mole ratio of 2:1
3. The ATOMICITY of H & O both =2
→ the formula of water = H2O
Why is it necessary to coat the handles with copper before they are nickel-plated
To make the knobs a conductor of electricity for the nickel-plating process
Nickel Electroplating
Why is it necessary to maintain the pH of the electrolytic bath within a small range
(Add Boric acid to maintain pH: 4~6)
- At low pH,
→H+(aq) instead of Ni2+(aq) will be discharged at the cathode.
→the current efficiency will decrease - At high pH,
→Ni2+(aq) will be precipitated as Ni(OH)2(s)
***It is necessary.
How boric acid functions in the nikel-plating bath
H3BO3(aq) is a weak acid.
→the dissociation of H3BO3(aq) can
1. replenish the ions lost by discharge at the cathode
2. maintains the pH of the electrolytic bath
How impure copper can be purified by electrolysis
- The impure Cu(s) anode becomes Cu2+(aq)
2. Cu2+(aq) in solution discharge on the pure Cu(s) cathode
Why is the concentration of Cu in CuSO4(aq) solution decreases during purification of Cu?
- At anode,
→ Fe(s) & Zn(s) dissolves as ions(Fe2+(aq) & Zn(aq))
→ they lose e- more readily than Cu
∴Cu2+(aq) ions decreases gradually - At cathode, Cu2+(aq) ions are always preferentially discharged
State TWO advantages of
building a factory in which
CONTACT PROCESS is carried out near the chemical plant (electrolysis: purification of Cu)
- SO2(g) available as resources for Contact process
- Prevent air pollution induced by SO2(g)
- The cost of transportation of SO2(g) is minimized
It is known that only cations can pass through the membrane (~porous device).
Y NaOH solution of higher concentration is eventually obtained
(at anode: ↑[NaCl(aq)])
(at cathode: ↓[NaCl(aq)])
(Higher lower)
- Unreacted Na+(aq) ions the anode side
→ can pass through the membrane to the cathode side - ∵H+(aq) ions are discharged at the cathode,
→ OH-(aq) remain/ are excess
→→higher concentration of NaOH is obtained
Why it is NOT recommended to use
a high current density in electroplating of Cu by electrolysis
- H2(g) gas bubbles HINDER THE DEPOSITION of Cu(s) in the surface of the metallic object
- → a loose spongy Cu deposit can be easily flaked off