Emsat math algebra Flashcards
Anything to the exponent of 0 is
Anything to the exponent of 0 is equal to one, for negative numbers it is equal to negative one
For polynomials (if there is a negative sign on a multiplication all signs must be example if it was -(x+5)
For polynomILS (if there is a negative sign on a multiplication all signs must be switched to begative, example if it was -(x+5)=-x-5
When you put pie in your calculator you must be in
If you re dealing with an angle degree you must be using
When you put pie in your calculator you must be in RADIAN MODE.
If you re dealing with an angle degree you must be using DEGREE MODE.
degree to radians . To convert Degree to radian you multiply the degree by pie/180
Radian to degree. To convert Degree to radian you multiply the degree by pie/180
When you want to put a number before teh square root. Use
You can use complex numbers by:
Conjugate is :
If there is a degree symbol, looks like a circle on the top right of the number, then use:
When you want to put a number before teh square root. Use SHIFT square root and a 3 should pop up and you can change that number.
Nearest one hundredth is the
If you want to put an x in your calculator, just use Alpha where the Pie button is.
When solving deraratives you can use your aclauclotr to solve it
Nearest one hundredth is the second number after the decimal.
If you want to put an x in your calculator, just use Alpha where the Pie button is.
When solving deraratives you can use your aclauclotr to solve it
For derivative questions you put x instead of F.
The calculator counts the derivative as a value, that means you put x =1. Which then for this example the answer was -5.So you are done using the derivative functions and simplify calculating
X coorinfate of the vertex can be found using the formula. X= -b/2a
When y=x. Then every unit to the righ you go
Y=x^2. This means that if x=5. Then Y=5^2
Y=x^2. This means that if x=5. Then Y=5^2
Then every unit to the righ you go up one
We can also find zero by:
We can also find zero by factoring
So it would be (x-h)(x-k)= 0
And h and k would be zeros
The unit circle:
The point p(x,y) being found this way is called
The circumference of a unit circle is
The area of a circle is: pie radius^2
The point p(x,y) being found this way is called the terminal point determined by the real number
The unit circle: is the circle of radius 1 centered at the origin in the xy-plane. Its equation is x^2 + y^ 2= 1
Unit circle part 2:
Figure 8 shows that to find the reference number t, it’s helpful to know the quadrant in which the terminal point determined by t lies. If the terminal point lies in Quadrant I or IV, where x is positive, we find t by moving along the circle to the positive x-axis. If it lies in Quadrant II or III, where x is negative, we find t by moving along the circle to the negative x-axis.
So pie / 3 = ½, square root 3 over 2. Since square root of 1=1 we remove it.
pie /4 = square root 2/2, square root 2/2
Pie / 6= square root 3/1 and 1 / 2
When number negative it is in quadrant 4 or 3.
(look at photos on phone for the picture)
unit circle 3:
the functions cosine, tangent cosecant, secant, and contangent are also defined by using the coordinate of p(x,y)
Proving trignomric idetieis
Sin t =y Cosine = x Secant = 1/x cosecant t = 1/y (y does not equal zero) Tangent t = y/x (x does not equal zero) Cotangent = x/y (y does not equal 0)
There is quotient identieis (look at phone pictures)
Reciprocal identities: Csc t = 1/sin t Sec t = 1/ cost t Tan t = sin t/ cost t Cos t = cos t/ sin t
Pythagorean identities:
sin^2(theta) t + cos^2 theta = 1
Tan^2 theta + 1 = sec^2 t
1+ cos^2 theta = csc ^2 t
A vector is: Terminal point is: Vector formula (what two things does it need)
A vector is an object that has both a magnitude and a direction
Terminal point is the end point
If a vector v is represented in the plane with initial point p(x1,y1) and terminal point q(x2,y2) then V= {x2-x1,y2-y1)
