END OF TERM TEST

Question 1

What is mode?

Answer 1

The one that occurs most often

Question 2

What us the range?

Answer 2

The highest value-lowest value

Question 3

What is the median?

Answer 3

The value in the exact middle after putting numbers in order

Question 4

What is the mean?

Answer 4

Add all the values/how many values

Question 5

What would be the median if u had an even amount of numbers?

Answer 5

Find the midpoint of the 2 numbers (add the numbers/2)

Question 6

What is the equation for total?

Answer 6

Total=mean x frequency

Question 7

What is the equation for mean?

Answer 7

Mean=total/frequency

Question 8

What is the fx column?

Answer 8

The frequency column x the X column (other column)

Question 9

How to work out range in FT?

Answer 9

Look in the first column (X).
Highest value-lowest value

Question 10

How to work out the mode in FT?

Answer 10

Look in the first column (X). It id the value with the highest frequency

Question 11

How to work out median in FT?

Answer 11

Mp=sum of f+1/2

Find the mp then count down the f column. Remember the answer is in the X column.

Question 12

How to work out mean in FT?

Answer 12

Mean=sum of FX column / sum of F column

If it is class wdith then find the midpoint and multiply midpoint with frequency to get fx column. Find sum of fx and sum of f. Do sum of fx/ sum of f to get mean

Question 13

What to do when you have a class width instead of X column?

Answer 13

Modal class (class width answer)
Range (biggest number-smallest number- dont take away all the class width just one number)
Median class (class width answer)
ARE THE SAME

MEAN-
work out midpoint. Middle number of class width 0<h<_10
Midpoint-5
Work out FX (FREQUENCY X MIDPOINT)
SUM OF FX/SUM OF F

Question 14

What to do if u have to find x value in f or fx and u are given the mean

Answer 14

M=sum of fx/sum of x

Sum if f X mean

This = sum of fx

Solve for x

Question 15

Recurring decimals into fractions

Answer 15

Lex x= 0.88888
X10
Let 10x= 8.8888

10x-x=9x
8.888-0.888=8
9x=8
/9
X=8 over 9

Question 16

Index laws

Answer 16

BASES STAY THE SAME
if its a x u add
If its a / u takeaway
If theyre in brackets u times

ANYTHING TO POWER OF 0 IS 1
1 TO THE POWER OF ANYTHING IS 1
NEGATIVE POWERS IS RECIPROCAL

FRACTION POWER ROOT BY DENOMINATOR POWER BY NUMERATOR

Question 17

Pythagoras theorem

Answer 17

USE WHEN GIVEN 2 SIDES INORDER TO WORK OUT 3RD

RIGHT ANGLE TRIANGLE

LONG SIDE- S S A SR a^2+b^2=c^2
SHORT SIDE- S S D SR. c^2-b^2=a^2

Question 18

Quadratic nth term

Answer 18

Find first and then second differences

Second difference-2a
First difference-3a+b
First term-a+b+c

an^2 + bn + c

Question 19

HCF AND LCM

Answer 19

Draw prime factor tree in order to find the 2 numbers as a product of their primes

Draw a venn diagram
Start in the overlap ans weite any common numbers in it
Write remaining numbers on each side

HCF-TIMES EVERY NUMBER IN OVERLAP
LCM-TIMES EVERY NUMBER IN WHOLE BENN DIAGRAM

Question 20

Itteration

Answer 20

Xn+1= next answer
Xo-1st number u substitute/starting point

Step1 - input ur Xo num inti calc press EXE then press ON

step2- type ur expression into ur calc but replace Xn with ANS

step3- press EXE to find x1 x2 x3

Question 21

Solving inequalities

Answer 21

solve like regualr equation then replace w crocodile signs

Have to solve till u get x on its own- do inverse

NUMBER LINE
draw circle on number before x and cirlce on number after x
IF EQUAL TO THEN COLOUR IN OTHERWISE LEAVE BLANK

if only 1 number with x then draw circle on that number if equal to then colour
And draw arrow in direction depending on if number is less than or more than x

Question 22

EXPANDING

Answer 22

Use the grid method for both double and triple brackets

Remeber to times not add and simplify

Question 23

FACTORISE

Answer 23

X^2 -6x +5=0
3 TERMS 2 BRACKETS
(X-5) (x-1)=0
X= 5 or X=1

TIMES TO LAST NUMBER

IGNORE THE MINUS SIGNS IF ANY

UR ANSWER WOULD BE OPPOOSITE SIGN TO WHSTS IN BRSCKET

2 TERMS = 1 BRACKET (EXCEPT DOTS)
3 TERME = 2 BRACEKETS

2 brackets- add to the number infront of x
Times to the mumber at the end

1 bracket common HCF

DOTS-square root of each number 2 brackets 1 plus 1 minus

Question 24

Reverse percentage

Answer 24

ORIGNAL ALWYAS EWUAL TO 100%

Find 10% FURST TO WORK OUT 100%

PERCENTAGE INCREASE x1.number
PERCENTAGE INCREASE X0. 100/1000-NUNBER

Question 25

Compound interest

Answer 25

Final = oringial value x (1+ interest rate /annum as a decimal) ^ number of years IF RHE WUESTION ASKS FOR A INTEREST RATE AS PERCENTAGE REMEBRR TO GIVE AS PERCENTAGE

Question 27

Simplifying algebraic fractions

Answer 27

Factorise both the top and bottom in either double bracket or single bracket You should have one bracket which is the same on both the top and the bottom. They should cancel each other out, leaving you with your answer. Eg.3x^2+11x-4. X^2 +3x-4

Question 28

Fibonacci sequence

Answer 28

The two terms add to get rhe next one In order to work out avlue of the letter add all sequences and divide by rhe coeffiecient Turn into simultaneous ewuation by timsing to get same a value to cancel out

Question 29

Scatter graphs first

Answer 29

Correlation- positive negative no Cirlce off point (annomaly) Line if best fit - line foloows pattern starting from first point to last point Use line of best fut to work out estimate

Question 30

Error intervals

Answer 30

If number begins with eg 8.3 then 8.3<_ y <8.4 Say ur nunber is 3.7 Ur nunbers before and after will be between 3.6-3.7 and 3.7-3.8 So 3.65 <_ x <3.75

Question 31

Frequency polygons

Answer 31

Work our midpoint of class width Y axis is frequency and x axis is number data Plot the midpoint (x) against frequency (y) for whole table Join the coordinates (NOT FROM 0,0) BUT FROM FIRST POINT TILL LAST POINT WITH LINES TO CREATE A SHAPE DONT JOIN FIRST AND LAST POINTS

Question 32

Coordinate geometry -length if line

Answer 32

Y=mx+c Midpoint To find length- use pythagoras Turn into right angle eith hupotenuse beinf x. See how far u gone along x axis by finding difference of 2 points See how far along the y acis u gone by finding difference of 2 points Use them to do pythagoras Can leave answer as square root

Question 33

Coordinate geometry-gradient of line

Answer 33

Repsent graduent as m= So how ever much we go up when we go 1 across Draw small triangles go one across and see how much up u go to reach the line can be a half or if negative correlation then - number

Question 34

Couldn’t geometry-perpendicular and parrallel

Answer 34

Perpendicular meet a right angle-opposite gradient Parrallel lines- same gradient Opposite sign fraction into whole number or number into fraction 1/ denominator number

Question 35

Coordinate geometry-equation of line

Answer 35

Y=mx+c M is gradient C is y intercept where the y acis is crossed Leave x and y as x and y Given two coordinates M=y2-y1/x2-x1 should get 1 number as answer after simplify Thats gradient Substitute coordinate 1 into the equation to find c (y intercept) (2,5) Y=3x+c 5=3x2+c 5=6+c C=-1 Equation- y=3x-1 IF ANDWER (GRADIENT) IS FRACTION THEN WRITE IT INTO EQUATION Y=mx+c Substitute y and x for coordinates Times every term by rhe denominattor of fraction Then solve to get c on its own and thats ur y gradient Then write into ewution y=mx+ c with x snd y ad x and y