Energetics Flashcards
(34 cards)
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How can we identify a reaction as exothermic? (2) Give an example of an exothermic reaction. (1)
⇒ -ΔH ((reaction emits energy(EXO=EXIT)) (1)
⇒ Energy reactants > Energy products on an Enthalpy profile diagram. (1)
⇒ N₂ + 3H₂ ⇌ 2NH₃ (Formation of Ammonia) (1)
How can we identify an endothermic reaction? (2) Give an example of an endothermic reaction (1)
⇒ +ΔH ((reaction absorbs energy(EN-DO=EN-TRANCE)) (1)
⇒ Energy products > Energy reactions on an Enthalpy profile diagram (1)
⇒ 2NH₃ ⇌ N₂ + 3H₂ (Decompostion of Ammonia) (1)
What happens when a reaction takes? (1)
⇒ Reactant bonds are broken, and product bonds are formed. (1)
What type of reaction occurs when a bond is broken and vice vera (4)
⇒ To break bonds energy is required, thus making an endothermic reaction (1)
⇒ Stronger bonds require larger amounts of energy (+ΔH) (1)
⇒ To engineer bonds, energy is released, thus an exothermic reaction (1)
⇒ Stronger bonds release more energy when they form (-ΔH) (1)
Define: Enthalpy Change, and state its units (3)
⇒ Enthalpy change is the amount of heat energy taken in or given out during any change in a system (1)
⇒ provided the pressure is constant. (1)
⇒ KJ mol⁻¹ (1)
What are the two standard conditions for enthalpy change, hence state its symbol (3)
⇒ 100 kPa pressure (1)
⇒ 298 K (room temperature or 25 °C) (1)
⇒ Standard Conditions symbol: ΔH^⦵ (1)
Define the term standard enthalpy of formation. (3)
⇒ enthalpy change when 1 mole of a substance (1)
⇒ is formed from its elements (1)
⇒ and all substances are in their standard states (1)
Define the term standard enthalpy of combustion. (3)
⇒ Enthalpy change when 1 mole of a compound (1)
⇒ is completely burnt in oxygen (1)
⇒ under standard conditions (1)
Define standard enthalpy change of neutralisation? (3)
⇒ Enthalpy change when an acid and an alkali react together (1)
⇒ under standard conditions (1)
⇒ to give one mole of water. (1)
What is the general rule for engineering chemical reactions that are undergoing Standard enthalpy change of combustion? (1)
⇒ Since 1 mole of a substance is burned, we need to treat the substance as a constant and complete the chemical equation in any way that allows the substance to remain as having one mol (1)
e.g. ⇒ C₄H₁₀₍ᵩ₎ + 6.5O₂₍ᵩ₎ → 4CO₂₍ᵩ₎ + 5H₂O
What is the general rule for engineering chemical reactions that are undergoing Standard enthalpy change of Neutralisation? (1)
⇒ Water must stay as having 1 mol. (1)
⇒ e.g: NaOH(aq) + HCl(aq) → NaOH(aq) + H2O
What is the general rule for engineering chemical reactions that are undergoing Standard enthalpy change of Formation?
⇒ The Product can only have 1 mole (1)
⇒ e.g: Na(s) + 1/2Cl₂(g) → NaCl(s)
What is the equation for heat change, 𝓆?
𝓆 =mc∆T
𝓂 = mass of water (not substance we are investigating)
𝒸 = specific heat capacity (water)
∆𝒯 = temperature change (of the water)
What is the equation for molar enthalpy change for a reaction, ∆ℋ?
∆ℋ = -𝓆/moles
State Hess’s Law (1)
⇒ The enthalpy change in a reaction is independent of the route taken. (1)
Where do arrows originate from and where do they point in combustion and formation for Hess’s cycle? (2)
⇒ Formation: From the elements towards the main equation (upwards)
⇒ Combustion: From the main equation, towards the elements (going down)
What should be in the toolbox of the cycle if all data given is ∆cH⦵? (2)
⇒ CO2 (1)
⇒ H2O (1)
What is the equation for the standard enthalpy of combustion? (1)
⇒ [Σ∆cH reactants] - [Σ∆cH products] (1)
What is the equation for the standard enthalpy of formation? (1)
⇒ ∆H = [Σ∆fH products]-[Σ∆fH reactants] (1)
Define mean bond enthalpy. (2)
⇒ enthalpy to break 1 mole of a bond (1)
⇒ averaged over different molecules (1)
What should the states of all substances be when breaking bonds? (1)
⇒ Gaseous form/state (1)
Why does mean bond enthalpy differ from those determined using Hess’s Law? (2)
⇒ They are mean values (1)
⇒ Across a range of different compounds/substances containing that bond. (1)
What is the equation for Bond enthalpy? (1)
⇒ [Σ∆H bonds broken]-[Σ∆H bonds made] (1)
What is the formula for percentage uncertainty? (1)
% uncertainty = (uncertainty/measured value)x100
e.g: The resistance of a filament lamp is given as 5.0 ± 0.4Ω. Calculate the percentage uncertainty
→ (0.4/5.0)x100 = 8%