Energetics II Flashcards
(113 cards)
How does an ionic compound form
Metallic atoms transfer electrons to nonmetallic atoms to form positive and negative ions which attract to form a lattice
Melting point and boiling point of ionic substances?
High
Lots of energy to overcome strong electrostatic attraction between oppositely charged ions
Standard enthalpy change of formation definition
Enthalpy change when one mole of a compound is formed from its elements under standard conditions
Enthalpy of lattice formation (AKA lattice energy) definition
Enthalpy change when one mole of a solid ionic lattice is formed from its gaseous ions
Making bonds so exothermic so always NEGATIVE VALUE
Lattice energy is always…
And it is a measure of…
Negative
Ionic bond strength
General born-haber cycle to work out lattice energy if have to do calculation?
Gaseous ions -lattice enthalpy—> ionic solid (on top)
Elements (on bottom)
Arrow form elements up to gaseous ions - atomisation, ionisation, atomisation, electron affinity etc.
Arrow from elements to ionic solid - enthalpy of formation
Steps to convert elements to gaseous ions
1) Change elements in standard form to gaseous state (enthalpy of atomisation)
2) Change gaseous metal atoms to (positive) ions (ionisation energy)
3) Change gaseous non-metal atoms into (negative) ions (atomise first if diatomic then electron affinity)
Standard enthalpy of atomisation definition
Enthalpy change when one mole of gaseous atoms are produced from one mole of an element under standard conditions
Eg. 1/2Br2 (l) —-> Br- (g)
Always positive because have to supply energy to atomise
First electron affinity
XXXX
Enthalpy change for one mole of gaseous atoms
to gain one mole of electrons
to form one mole of gaseous ions with a 1- charge
Eg. X(g) + e- —-> X-(g)
——————
First electron affinity is exothermic for atoms that normally form negative ions WHY???
Second electron affinity
Enthalpy change when one mole of gaseous 1- ions
gains one electron per ion to produce
one mole of gaseous 2- ions
Eg. X-(g) + e- —-> X2- (g)
——————
Second electron affinity is ENDOTHERMIC because energy must be taken in to overcome repulsion between already negative ion and electron you are trying to add
Equation for lattice enthalpy
(energy change of elements to ionic solid aka enthalpy of formation) - (energy change the elements to gaseous ions)
Going round the cycle it’s negative gaseous ions to elements + enthalpy of formation of ionic solid from elements
How can we calculate the theoretical lattice enthalpy? And what do we assume?
Visualise perfectly spherical ions in a lattice
Calculate all forces of attraction and repulsion in the lattice
Assume perfect ionic model where ions are 100% ionic and spherical and attractions are purely electrostatic.
What kind of values are the values determined by the born-haber cycle?
Value is determined by experiment
Reflect the actual value
(We assumed perfect ionic model but if the experimental value is different we know this assumption was wrong and there is covalent character which is causes this difference)
What does a MORE -VE value of lattice enthalpy of FORMATION mean?
And LESS -VE value?
More negative value More exothermic More heat energy released Stronger bonds made Stronger lattice
Less negative value Less exothermic Less heat energy released Weaker bonds made Weaker lattice
What does a great a difference between the experimental and theoretical value of the born-haber cycle mean?
Greater degree of covalency in the lattice (and thus more polarisation)
Perfect ionic model
Ions are 100% ionic and spherical
Attractions are purely electrostatic
Polarised ionic bonding
Cation attract electrons
What does the extent of polarisation depend on?
How much
the cation pulls the electrons (polarising power)
The anion lets the electrons be pulled away (Polarisability)
Factors which increase polarisation in ionic compounds?
1) size of cation (smaller cation attracts e- more so more polarising)
2) size of anion (larger anion more polarisable)
3) increased charge of cation or anion
What type of polarisation would
K+F- have?
Low polarisation
K is a large cation
F is a small anion
low charge (both +/-1)
What type of polarisation would
Al3+ (I-)3 have?
High polarisation
Al3+ is a small cation (more polarising power)
(I-)3 is a large anion (more polarisable)
More +ve value of lattice DISSOCIATION enthalpy means
More +ve value of dissociation enthalpy More heat energy taken in More endothermic Stronger bonds had to be broken Stronger lattice
Less +ve = weaker lattice
High polarisability (Anion) High polarisation (cation)
LARGE ANION
SMALL CATION
What causes polarisation and what does a greater polarisation mean?
Covalency causes polarisation
Greater polarisation means more covalent character