Enzyme Kinetics and Inhibition Flashcards

(70 cards)

1
Q

Irreversible Reactions

A –> P

A

Rate of P formation equals rate of A disappearance

Rate of P formation is directly proportional to the concentration of reactant

V= dp/dt= k[A]

V= -dA/dt= k[A]

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Characteristics of 1st order reactions

A

Exponent is 1

Units: s^-1

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Bimolecular irreversible reaction

A + B –> P

A

Rate of P formation equals rate of disappearance of A OR B

Rate of P formation (or A/B disappearance) is directly proportional to concentration of reactants

V= dp/dt = k [A] [B]

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Unimolecular reversible reaction

A P

A

V= dp/dt = k1[A] - k2[P]

^rate of P formation and rate of A disappearance

Rate gained = rate loss AT EQUILIBRIUM

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Equilibrium constant: Keq

A

K1/k2 = [P]/ [A]

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Steady state Assumption for Michaelis Menten

A

[ES] assumed to be unchanging

Michaelis Constant=
Km= (k2 +k3)/k1 > [E] and ES formation has negligible effect on S… [S]= constant = [S]t

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Formula for [ES] under steady state

A

[ES]= [E][S]/ Km = ([E]t [S])/ (Km + [S])

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Maximal Velocity

A

When E is saturate with S

[ES] = [E]t

Vo= k3 [ES] = k3 [E]t = Vm

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Michaelis Menten equation

A

V = Vm [S]/ (Km + [S])

~ hyperbolic curve ~

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

of active sites are filled

A

[ES]/ [E]t = v/Vm = [S]/ (Km + [S])

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Michaelis Menten Assumptions

A
  • Formation of ES complex between enzyme and substrate
  • no back reaction from product buildup (k4=0)
  • initial velocities used for analysis (t=0)
  • steady state for [ES]
  • negligible depletion of substrate [S]&raquo_space; [E]
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Michaelis constant

A

Km= (k2 + k3)/ k1

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Larger Km

A

Has a smaller v at the same [S]

Graph levels off at the same Vm but reaches it slower

Weak binding of the [ES] –> low affinity

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Vm=k3[E]t

A

Maximum rate when [ES] = [E]t

Proportional to k3

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Turnover number= k3=kcat

A
  • Catalytic ability
  • Typical values: 1-10^4 s^-1
  • Number of S molecules converted to P by one E molecule in unit time under saturation conditions
  • larger kcat –> larger v –> faster reaction
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Catalytic Efficiency- what happens when [S]

A

Typical physiological conditions

Plot of v versus [S] is learn with an apparent second order rate constant: k3/Km = kcat/Km –> proportional to that initial slope Vm/Km

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

What is catalytic efficiency?

A

Kcat/Km –> how well an enzyme reacts with dilute amounts of substrate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

Kcat/Km

A

Combines attributes of kcat and Km (characteristics of E-S interaction)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

Perfect enzymes

A

Have the highest kcat/Km values

Limited only by the rate of diffusion of substrate to enzyme

10^8 - 10^9

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

Slowest step of the enzyme reaction

A

Diffusion of substrate to enzyme

However overall reaction is fast

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
21
Q

Ideal substrate range

A

1/3 [KM] 2 [KM]

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
22
Q

Line-weaver Burke

A

Take double reciprocal of the MM equation

1/v = Km/Vm (1/[S] + 1/Vm

Slope= Km/Vm = Km/(kcat [E]t)

Y-intercept= 1/Vm

X-intercept= -1/Km

Low slope has a better catalytic efficiency

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
23
Q

Dis-advantages to the Lineweaver Burk Plot

A

Distorts errors at low [S]

Compresses data at high [S]

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
24
Q

Sequential Mechanism

A

Substrate bind to form a ternary complex with the enzyme before product is release

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
25
Order sequential
Specific order for substrate binding and product leaving "A has to go in first"
26
Random sequential
Random order for substrate binding and product leaving "Either A or B can go into the reaction first"
27
Ping-Pong Mechanism (double replacement)
One substrate binds and release product before second substrate binds and release product A goes in P comes out * enzyme intermediate* B goes in and Q comes out
28
Reversible inhibition
Bind the enzyme with noncovalent interactions Dissociate rapidly Allow the enzyme to recover its original activity
29
Irreversible Inhibitors
Bind the enzyme with covalent interactions targeting a critical residue for catalysis Permanent inactivation of the enzyme
30
Competitive Inhibition
Binds to only the free enzyme Compete with substrate for active site Usually resembles shape and structure of substrate (or transition state) --> lacks functionality for reaction Hinders reaction by interfering with substrate binding and reducing amount of ES complex
31
Analysis of Competitive Inhibitors
reduced rate is same as noncompetitive inhibitor at very low [S] Degree of inhibition decreases with increasing [S] --> low substrate concentration is the best place for the inhibitor to work Km decreases Vm stays the same Kcat/Km decreases
32
Substrate analogs
Have key structural features that mimic the substrate
33
Transition state analogs
Stable compounds that resemble the transition state in structure and polarity or charge
34
Uncompetitive Inhibitor
Binds only to ES Complex (substrate must be bound to enzyme) at a site different from active site but created by substrate-enzyme interaction Lacks structural resemblance to substrate
35
How does a uncompetitive inhibitor work?
Hinders reaction by distorting active site and making catalytically inactive ^^catalytic residues cannot line up properly Km decreases by the same factor of Vm Vm decreases by the same factor of Km Catalytically efficiency stays the same (same slope)
36
Do the rate constants change during inhibition for uncompetitive inhibitors?
Rate constants don't change, we're looking at them when the inhibitors are present --> called apparent changes
37
How does the degree of inhibition change with uncompetitive inhibition?
Doesn't do much as low [S] (rate is same as control) but inhibition increases with increasing [S]
38
Noncompetitive Inhibition
Binds with same Ki to free enzyme or ES complex at site different from active site Lacks structural resemblance to substrate
39
How does noncompetitive inhibition work?
Hinders reaction by distorting enzyme structure and preventing alignment of catalytic center
40
Kinetics of Noncompetitive Inhibitors
Vm --> decrease Km --> no change Catalytic efficiency --> decrease *increasing [S] cannot overcome effects*
41
Degree of inhibition for noncompetitive inhibition?
Degrees of inhibition is constant with increasing [S]
42
% Inhibition
(1-voi/vo) X 100
43
Relative Rate
Voi/Vo
44
Relative rate- Competitive Inhibition [S]
1/(1+ [I]/Ki)
45
Relative rate- Competitive Inhibition [S] >> Km
1
46
Relative rate- Uncompetitive Inhibition [S]
1
47
Relative rate- Uncompetitive Inhibition [S] >> Km
1/(1+[I]/Ki)
48
Relative Rate- Noncompetitive Inhibition [S]
1/(1+[I]/Ki)
49
Relative Rate- Noncompetitive Inhibition [S] >> Km
1/(1+[I]/Ki)
50
Irreversible Inhibitors
Result in permanent inactivation by forming stable covalent bonds with functional groups involved in enzyme activity
51
What happens to [E]t and Vm with irreversible inhibitors?
[E]t decreases Vm decreases but no change in Km ^this is because inhibitors remove free enzymes from the reaction Operate within the active site
52
Irreversible Inhibitors- Group Specific Reagents
Group specific reagents covalently interact with specific side chains of enzyme residues
53
Irreversible Inhibitors- Affinity Labels
Structurally similar to substrate and covalently bind with active-site residues More specific than group specific reagents
54
Irreversible Inhibitors: Suicide Inhibitors
Also called mechanism-based inhibitors or suicide in activators Bind at the active site and "trick" the enzyme into activating the catalytic mechanism A chemically reactive intermediate is produced which covalently modifies the enzyme and results in permanent inactivation ^^permanent inactivation of the enzyme is a result of the enzyme's own participation
55
Doe Allosteric Control obey Michaelis Menten model?
Does not obey Michaelis-Menten Kinetics Shows a sigmoidal dependence of reaction velocity on substrate concentration
56
When would you use allosteric control?
These enzymes are typically rate-determining enzymes in metabolic pathways or at a junction where the substrate can be used for more than one pathway
57
How does Allosteric regulation work?
Involves noncovalent binding of a ligand (effector) to a site other than the active site (Regulatory or allosteric site) --> this binding affects the activity of the active site Allosteric enzymes are generally oligomers (>1 subunit) such that interaction on one subunit affects the others (+ or - cooperativity)
58
Homotropic effector
Effector is same as substrate Site is usually adjacent to active site (adjoining subunit) Interaction almost always increases activity (sigmoidal curve)
59
Heterotrophic Effector
Effector is different from substrate Site is "true" allosteric site Interaction increases or decreases activity
60
How is allosteric control different from inhibition?
Allosteric control actually changes the rate constants instead of the apparent change
61
What can allosteric control change?
Effector-induced conformational changes in the enzyme can alter activity by changing Km (k class) and Vm (v class) or both
62
Positive Effector (A)
Binds to activator site and increases activity --> decreases Km
63
Negative effector
Binds to inhibitory site and decreases activity --> increases Km
64
How can allosteric enzymes by controlled?
Thru feedback inhibition
65
Regulatory Proteins
Proteins that either have Stimulatory or inhibitory reversible interactions with enzymes
66
Calmodulin
Regulatory protein that stimulates activity Senses intracellular Ca2+ concentration and activates proteins when calcium levels rise
67
Antihemophilic factor (factor VIII)
Regulatory protein that stimulates activity Enhances activity of a serine protease to accelerate the blood clotting cascade
68
PKA
Regulatory protein that inhibits activity Inhibitors PKA catalytic subunits until binding of cAMP causes dissociation of regulatory and catalytic subunits
69
How does reversible covalent modifications work?
Catalytic properties of enzymes are modified by adding/removing charged groups (phosphate, sulfate, acetate) --> that causes conformational change and alter their function most common: the phosphorylation/dephosphorylation cycle of specific serine, threonine, and tyrosine residues Rate depends on the concentration of kinases (phosphate example)
70
Proteolytic Activation
Many enzymes are synthesized as an inactive precursor called a pro enzyme or zymogen