Enzymes Part 2 (Kinetics) Flashcards

(47 cards)

1
Q

Endergonic Reaction

A
  • ΔG > 0
  • Non-spontaneous; requires input of energy
  • Products have higher free energy than the reactants
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2
Q

Exergonic Reaction

A
  • ΔG < 0
  • Spontaneous
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3
Q

How can an endergonic reaction be driven to move forward?

A

By coupling it with an exergonic (favorable) reaction

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4
Q

Main molecule utilized in enzyme coupled reactions:

A

ATP

  • adenine (nitrogenous base)
  • ribose (5 carbon sugar)
  • three phosphate groups
  • -3.5 total charge
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5
Q

ATP has a high energy phosphate bond. Removal of 1 phosphate group leads to ADP and gives off a considerable amount of energy.

What type of reaction occurs and how much energy is given off?

A
  • hydrolysis (a phosphate bond is cleaved)
  • ΔG = -30.5 kJ/mol
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6
Q

ATP + H2O → ADP + Pi

ΔG =

A

-30.5 kJ/mol

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7
Q

ADP + Pi → ATP

ΔG =

A

+30.5 kJ/mol

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8
Q

What is the molecular basis for the large amount of energy given of by the conversion of

ATP + H2O → ADP + Pi

A
  • Electrostatic repulsion between the three phosphates destabilizes ATP molecule.
    • ATP has -3.5 charge
    • ADP has -2.5 charge
  • After hydrolysis, an individual phosphate can be stabilized by resonance stabilization, which makes it more stable than its form in ATP.
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9
Q

Equilibrium is a state of:

A

maximum stability

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10
Q

A process is spontaneous and can perform work only when it is:

A

moving toward equilibrium

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11
Q

Reaction velocity versus [E]:

A
  • more enzyme = faster rate.
  • linear correlation
  • substrate has more enzyme to bind to, increases [ES], increases product formation.
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12
Q

Reaction velocity versus [S]:

A
  • rate increases asymptomatically with increasing [S]
  • Velocity initially increases linearly, but then stabilizes and becomes constant when all enzyme active sites are saturated.
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13
Q

If you want to increase Vmax, you need to increase:

A

[E]

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14
Q

E + S ⇔ ES ⇒ E + P

What is Km?

A
  • Michaelis Constant
  • Conversion of E + S ⇔ ES
  • reflects affinity for a substrate to an enzyme
  • Km = [S] at ½Vmax
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15
Q

E + S ⇔ ES ⇒ E + P

What is Kcat?

A
  • Rate of ES ⇒ E + P
  • (Kcat)([E]) = Vmax
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16
Q

(Kcat)([E]) =

A

Vmax

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17
Q

Michaelis Menten Equation

A
  • v = initial velocity at a given [S]
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18
Q

½Vmax =

A

Km

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19
Q

Lineweaver-Burk Plot Equation:

A
  • x-intercept = -1/Km
  • y-intercept = 1/Vmax
20
Q

Km only changes with:

A

pH and temperature

Does not change with [E] or [S]

21
Q

Numerically, Km =

A

[S] at ½Vmax

22
Q

Smaller the Km:

A
  • higher affinity of enzyme for substrate
  • “tighter ES binding”
23
Q

Larger the Km:

A
  • lower affinity of enzyme for substrate
  • “less tight ES binding”
24
Q

Vmax is linearly dependent on:

25
Kcat only changes with:
* pH and temperature * does not change with [E] or [S] * a constant
26
Conceptually, Vmax is:
maximum velocity with which the enzyme can catalyze the reaction
27
Conceptually, Kcat is:
* kcat = (Vmax)([E]) * turnover number of an enzyme reflecting the number of moles of substrates converted to products per sec per mol of enzyme * ES converted to E + P
28
Higher the Kcat:
* more product produced per second per mole of enzyme * "high turnover:
29
Fastest way to regulate enzyme activity:
* phosphorylation/dephosphorylation of the enzyme * most phosphorylation occurs on the serine, threonine, and tyrosine amino acids of an enzyme (all have -OH groups)
30
Slowest way to regulate enzyme activity:
extracellular signalling
31
Enzyme regulation by specific proteolysis:
* irreversible
32
The two types of enzyme inhibitors:
1. irreversible 2. reversible * competitive * uncompetitive * noncompetitive
33
Irreversible inhibitors are:
* molecules that covalently bind to an active site amino acid of the enzyme to inhibit the activity. * substrate analogs * Examples: 1. penicillin 2. sarin (nerve gas) 3. aspirin
34
Reversible inhibitors are:
* molecules that bind reversibly to inhibit enzyme activity * Three kinds: 1. competitive 2. uncompetitive 3. noncompetitive
35
Competitive inhibitors:
* reversible * bind to active site of enzyme, compete with the substrate for active site slots. * Km INCREASED, Vmax UNCHANGED * can be overcome by increasing [S]
36
Noncompetitive inhibitors:
* reversible * bind to a separate site of the enzyme (not the active site) * Km UNCHANGE, Vmax DECREASED * increasing [S] does not help since their is no competition for the active site
37
Example of a competitive inhibitor:
* statins * inhibit enzyme involved in cholesterol synthesis
38
Transition State Analogs:
* potent inhibitors * stable molecules that resemble geometric and/or electronic features of the highly unstable transition state * binding is often much tighter than the substrate because they fit all elements of the active site
39
Allosteric Enzymes:
* have two binding sites: 1. active site (for substrate) 2. allosteric site (for a noncompetitive inhibitor or effector) * all are oligomeric (\>1 peptide sequence) * allosteric molecules do not resemble substrates
40
V versus [S] curve of allosteric enzymes:
* sigmoidal (S-shaped) * due to cooperative substrate binding
41
The two equilibrium states of allosteric enzymes:
1. R-state (active; strong substrate binding) 2. T-state (inactive; weak substrate binding)
42
Allosteric activators stabilize:
* the R-state (active) of an allosteric enzyme * increases substrate binding * increases activity
43
Allosteric inhibitors stabilize:
* the T-state (inactive) of an allosteric enzyme * decreases substrate binding * decreases activity
44
K-type Allosteric Inhibitor:
* increase K0.5 (DECREASES AFFINITY) * no effect on Vmax
45
K-type Allosteric Activator:
* decreases K0.5 (INCREASES AFFINITY) * no effect on Vmax
46
V-type Allosteric Inhibitor:
* decreases Vmax * no effect on K0.5 * no effect on affinity
47
V-type Allosteric Activator:
* increases Vmax * no effect on K0.5 * no effect on affinity