Equation problems for algebra 1

Question 1

Addition Property of Equality

Answer 1

If you add the same amount to both sides of an equation, the two expressions in the equation remain equivalent.

Question 2

Division Property of Equality

Answer 2

If you divide the same amount from both sides of an equation, the two expressions in the equation remain equivalent.

Question 3

equals sign

Answer 3

A symbol of equality; =

Question 4

equation

Answer 4

A mathematical sentence showing two expressions are equal; contains an equals sign (=)

Question 5

expressions

Answer 5

A combination of numbers and operations

Question 6

inverse operations

Answer 6

Operations which undo each other.

Question 7

Multiplication Property of Equality

Answer 7

When you multiply both sides of an equation by the same value, the two expressions remain equivalent.

Question 8

solution

Answer 8

The value of a variable that makes an equation true.

Question 9

solve

Answer 9

To replace a variable with a value that results in a true sentence.

Question 10

Subtraction Property of Equality

Answer 10

When you subtract the same value from both sides of an equation, the two expressions remain equivalent.

Question 11

To solve an equation you must……

Answer 11

Get the variable alone

Question 12

To get the variable alone you must…..

Answer 12

Get rid of the things on the variable side

Question 13

To get rid of addition you must…….

Answer 13

Subtract on BOTH sides of the equation

Question 14

To get rid of subtraction you must……

Answer 14

Add on BOTH sides of the equation

Question 15

To get rid of division you must…..

Answer 15

Multiply on BOTH sides of the equation

Question 16

To get rid of multiplication you must….

Answer 16

Divide on BOTH sides of the equation

Question 17

x + 7 = 12

Answer 17

Subtract 7 from both sides leaving you with x = 5

Question 18

x - 8 = 17

Answer 18

Add 8 to both sides leaving you with x = 25

Question 19

x/12 = 36

Answer 19

Multiply 12 on both sides leaving you with x = 432

Question 20

4x = 12

Answer 20

Divide 4 on both sides leaving you withx = 3

Question 21

Two step equations mean you must…..

Answer 21

Get rid of the addition or subtraction first and then get rid of the multiplication or division second (by doing the opposite on both sides)

Question 22

3x + 12 = 36

Answer 22

Subtract 12 from both sides and get 3x = 24Then divide by 3 on both sides and getx = 8

Question 23

4x - 15 = 17

Answer 23

First you must add 15 to both sides to get4x = 32Then divide both sides by 4 and getx = 8

Question 24

7 - x/2 = 23

Answer 24

First you must get rid of positive seven (be careful this does not say - 7 so to get rid of positive 7 you must subtract 7 from both sides to get -x/2 = 16To get rid of the - and the 2 you must multiply both sides by -2 and getx = -32

Question 25

9 + x/15 = 21

Answer 25

First you must get rid of the positive 9 by subtracting 9 from both sides to getx/15 = 12Then you must get rid of 15 so you must multiply both sides by 15 to getx = 180

Question 26

To solve an equation you must......

Answer 26

Isolate variable

Question 27

To get rid of addition you must.......

Answer 27

Subtract on BOTH sides of the equation

Question 28

To get rid of subtraction you must......

Answer 28

Add on BOTH sides of the equation

Question 29

To get rid of division you must.....

Answer 29

Multiply on BOTH sides of the equation

Question 30

To get rid of multiplication you must....

Answer 30

Divide on BOTH sides of the equation

Question 31

Describe how to solvex + 7 = 12

Answer 31

Subtract 7 from both sides leaving you with x = 5

Question 32

Describe how to solvex - 8 = 17

Answer 32

Add 8 to both sides leaving you with x = 25

Question 33

Describe how to solvex/12 = 36

Answer 33

Multiply 12 on both sides leaving you with x = 432

Question 34

Describe how to solve4x = 12

Answer 34

Divide 4 on both sides leaving you withx = 3

Question 35

Two step equations mean you must.....

Answer 35

Get rid of the addition or subtraction first and then get rid of the multiplication or division second (by doing the opposite on both sides)

Question 36

Describe how to solve3x + 12 = 36

Answer 36

Subtract 12 from both sides and get 3x = 24Then divide by 3 on both sides and getx = 8

Question 37

Describe how to solve4x - 15 = 17

Answer 37

First you must add 15 to both sides to get4x = 32Then divide both sides by 4 and getx = 8

Question 38

Describe how to solve7 - x/2 = 23

Answer 38

First you must get rid of positive seven (be careful this does not say - 7 so to get rid of positive 7 you must subtract 7 from both sides to get -x/2 = 16To get rid of the - and the 2 you must multiply both sides by -2 and getx = -32

Question 39

Describe how to solve9 + x/15 = 21

Answer 39

First you must get rid of the positive 9 by subtracting 9 from both sides to getx/15 = 12Then you must get rid of 15 so you must multiply both sides by 15 to getx = 180

Question 40

Solvex - 6 = 78

Answer 40

x = 84

Question 41

Solve34 - x = 15

Answer 41

x = 19

Question 42

Solve8x = 64

Answer 42

x = 8

Question 43

Solve6x - 13 = 41

Answer 43

x = 9

Question 44

Solvex/8 - 22 = 14

Answer 44

x = 288

Question 45

Solvex/-2 - 15 = 15

Answer 45

x = -15

Question 46

Solve18 = 6x

Answer 46

x = 3

Question 47

Solve20 = 3x + 2

Answer 47

x = 6

Question 48

Solve48 = x/13 - 17

Answer 48

x = 845

Question 49

Solve98 = 12x + 2

Answer 49

x = 8