Equilibria in Aqueous Systems Flashcards

(34 cards)

1
Q

what is a common ion

A

A common ion is an ion that is present in a solution from two different sources
NaCl and HCl = common ion of Cl because it is produced but from different sources

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2
Q

common ion effect

A

it is a reduction of dissociation in weak acid/base due to a common ion already in a solution
- the presence of a common ion shifts the equilibrium towards reactants because le chantelier principle
CH3COOH –> CH3COO- + H+
CH3COONa –> Na+ + CH3COO-
this H+ reacts with the common ion to reform the acid - buffer
its a weak acid and the salt it produces - this forms a buffer system

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3
Q

Acid-Base Buffer

A

A solution that resists changes in pH when a small amount of either strong acid or strong base is added
weak acid + conjugate base OR weak base + conjugate acid
buffer ratio = [HA]/[A]

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4
Q

explain the buffer ratio

A

[HA]/[A] is large, which means there is more acid and less conj base –> more hydronium, more acidity

[HA]/[A] is small, which means there is more conj base than acid –> less hydronium, less acidity, more basic

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5
Q

what happens when you add a strong acid to a buffer system

A

a strong acid reacts with a weak base (A)
A- + H3O+ –> HA + H2O (reverse of acid dissociation)
HA conc increases, A conc decreases
= pH decreases, making it more acidic if HA > A

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6
Q

what happens when you add a strong base to a buffer system

A

it will react with the acidic component of the buffer (HA)
HA + OH- –> A- + H2O
[HA] decreases, [A] increases because it is being produced
= HA>A
= pH increases, more basic

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7
Q

the less the difference between HA and A in the buffer concentration ratio, the better/worse the buffer is

A

better
you want close concs of the weak acid and the conjugate base to = more effective in resisting pH changes

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8
Q

what is henderson-hasselbalch used for

A

pH = pKa + log ([A]/[HA])
helps us solve for pH directly without H3O
when the HA = A the log part becomes log1 which = 0
this leaves you with pH=pKa
usually, pKa is given in the equation or it can be solved by -log (Ka)
*the buffer is the most effective when HA = A

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9
Q

explain buffer capacity

A

the measure of the strength of the buffer - its ability to maintain the pH fluctuations following the addition of strong acids or strong bases
- depends only on concentration
- works best when [A] and [HA] are very close in magnitude + high in concentration
- if one component dominates, the buffer becomes less effective
GREAT CAPACITY = less pH flucuations

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10
Q

what is the absolute concentration in buffer systems

A

the more concentrated the buffer components - A and HA are, the greater the capacity
- increasing the capacity, increases the effectiveness of the buffer - less fluctuations

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11
Q

what are the relative concentrations in buffer systems

A

the closer the component concentrations are to each other, the greater the capacity = less fluctuations

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12
Q

what is the buffer range

A

the pH range over which the buffer is effective and related to the relative concentrations
The more differences the acid and base components are the less effective the buffer = lower buffer capacity (further away from 1)
If the [A]/[HA] component is bigger than 10 or less than 0.1 = poor buffer action
*buffers can have a usable range within +/- 1 pH unit of the pKa

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13
Q

Briefly how to prepare a buffer

A
  1. choose the conjugate acid-base pair
  2. calculate the ratio of the buffer concentrations
  3. determine the buffer concentration
  4. mix the solution and correct the pH
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14
Q

the acid-base titration curve

A

a plot of pH VS the volume of titrant added (in the burette)

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15
Q

what happens when you titrate a strong acid and a strong base together

A

A: pH = acidic with lots of H3O, the pH starts to increase and become a bit more basic once the base is constantly added - H3O conc slowly decreases

B: the pH rises very rapidly
- when the amount of dissociated OH from the base is ALMOST equal to the amount of H3O remaining

C: equivalence point, when the moles of OH = moles of H3O originally present
- anions of strong acid and cations of a strong base
- these anions and cations - salt - do not further react

D: pH continuously rises slowly to increase the pH, making it more basic as OH > H3O

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16
Q

where is the equivalence point for strong acids and bases relatively near?

17
Q

explain the weak acid + strong base titration curve

A

A: pH starts a bit higher, not as acidic as the strong acid, starts with less H3O

B: curve rises gradually (buffer-region, half-way point)
- HPr reacts with the strong base to produce Pr
- half of the HPr is equal to the amount of Pr made (pH = pKa)

C: equivalence point - where the solutions have the same amounts of [HPr] = [Pr]

D: the pH increases slowly beyond the equivalence point as excess OH is added

18
Q

where is the equivalence point for weak acids and strong bases relatively near?

A

above a pH of 7
shifted upwards
starting pH is higher and EP is higher

19
Q

explain weak base and strong acid titration curves

A

displays the same shape as the weak acid curve but inverted so it starts with a basic pH
A: starts with low amounts of OH, and a relatively high pH

B: buffer region zone - where pH = pKa. this is when the HB = B (weak base ALMOST = conj acid)

C: equivalence point, shifted
- where HB = exactly B and the concentrations of H3O and OH are equal

D: excess H3O from the addition of more strong acid, this makes the pH very low

20
Q

where is the equivalence point for weak base and strong acids relatively near?

A

pH is shifted downwards below 7

21
Q

what is an indicator and how does it work with monitoring pH

A

a weak organic acid whose colour (A) differs from the colour (B) of its conjugate base because the 2 species have slightly different structures
When the pH is lower = H3O is higher = [Hln]&raquo_space; [ln]
As the pH increases = H3O decreases [Hln] &laquo_space;[ln]
this ratio = Henderson-hasselbalch [ln]/[Hln]
When the ratio = 0.1 the acid colour is seen (1:10)
When the ratio = 1 the acid and base colours (1:1)merge to form an intermediate hue
When the ratio = 10 the base colour is seen (10:1)

22
Q

how do you choose the acid-base indicator

A

the endpoint occurs when the indicator changes colour
- you choose an indicator with a colour change that is close to the pH of the EP - you want to see the end point happening via bright colour change

23
Q

what is the Ksp

A

solubility product constant
- equilibrium constant for the dissolution of a slightly soluble compound
Solid Iron + H2O —> P1 + P2
Ksp expressions don’t have denominators (products/reactants) because the reactants are pure solids/water
at equilibrium = saturation

24
Q

why can’t you always assume a salt completely dissociates

A

some compounds partly dissociate and undissociated, this increases the solubility

25
Adding a common ion ___ the solubility of a slightly soluble salt
decreases - when a common ion is added to the OG equations - the solubility of the main reactant has decreased - le chatliers principle - adding more of a common ion on the product side, shifts the equilibrium to the reactants, making it dissolve less
26
when fewer Ag+ ions are produced the solubility of AgCl ____
decreases solubility is defined based on how well it dissociates - when your solving for solubility, you are solving for s
27
Ksp = [Ag][Cl], how would you rearrange this so that you are solving for solubility
[Ag] = [Cl] = s = solubility of AgCl (s)(s) = Ksp Ksp = s^2 s = sqroot of Ksp
28
Ksp = [Ag][Cl], how would you rearrange this so that you are solving for solubility after adding a common ion
AgCl --> Ag + Cl NaCl --> Na + Cl Ksp = [Ag][Cl] Ksp = (s)(s) Ksp = (s)(c + s) assume s is small compared to the concentration of the common ion, c Ksp = (s)(c) s = Ksp/c
29
what is the effect of pH on solubility
calcium carbonate --> calcium + carbonate ions - the carbonate ions will react with water, OH or H depending on the conditions if they are neutral or not - in neutral/basic conditions, the carbonate will react with water or OH and = minor effect on solubility - in acidic conditions CO3 + H3O --> HCO3 this rxn occurs strongly and removes it from the OG eqn, this causes the reaction to shift to the right, increasing the solubility (le chatelier)
30
Qsp
reaction quotient = the ratio at any time
31
Ksp
the ratio of products/reactants at equilibrium only
32
Qsp = Ksp
equilibrium - saturated solution
33
Qsp > Ksp
over saturated - will shift to the reactants to form more solid (reverse dissolving) until it is back to just saturated
34