Exam 1 Flashcards
The two types of experiments Mendel carried out (explain)
- Self fertilization: pollen and egg from the same plant, naturally occurs in peas
- Cross fertilization: pollen and egg from two different plants, produces hybrids (offspring)
Describe how Mendel carried out crosses
- Remove anthers from flower 1
- Transfer pollen from anthers of flower 2 to the stigma of flower 1
- Plant the seeds
define
Characters
observable characteristics of an organism
eye color
define
Trait
specific properties of a character
blue eyes
What approach did Mendel use and what does it mean?
Emperical approach
* no hypothesis
* quantitative analysis of crosses would provide mathematical relationships that govern traits
* used to deduce empirical laws
define
Single factor cross
crossing two variants of the same characteristic
Describe Mendel’s single factor cross process
- Cross two true breadding plants (Parental generation)
- The offspring (F1) self fertilize
- The offspring (F2) are analyzed for their traits
Parental: TT x tt
F1: Tt x Tt
F2: TT + 2Tt + tt
result and conclusion of Mendel’s single factor cross
- F2 generation had a phenotype of 3:1
- he concluded that this mean that a trait must exist in a dominant and recessive form, not a blended form
- genes are inherited as discrete units
- Law of segregation
define
Genes
inheritable units that reman unchanged
define
Alleles
different versions of the same gene
explain
Law of Segregation
- two copies of a gene seperate from each other during meiosis
- each gamate carries a single allele of a given gene
Results/Conclusion of Mendel’s 2 factor crosses
- Law of independent assortment
- F2 generation had seeds with new combinations that were not present in the parental generation
Law of independent assortment
two different genes will randomly assort during meiosis
Mendel’s 2 factor crosses has a phenotype ratio of
9:3:3:1
Pedigree basic symbols
- circle = female
- square = male
- filled in = affected
Cystic fibrosis
basic facts
- recessive disorder
- gene encodes a protein CFTR regulating ion transport
- mutant causes altered CFTR
random sampling error
define
- deviation b/w observated and expected
- large for small samples
Product rule
how to and what it gives
- gives the probability that two or more independent events will occur
- multiple probabilities of the independent events
Two hetrozygotes for a disease want to start a family, what is the chance their first 3 kids will have the disease (recessive)
1/4 * 1/4 * 1/4 = 1/64
0.016
1.6%
Binomial expansion equation
what it is and what it gives
- gives all possibilities for a given set of unordered events
- P = [n! ÷ (x!(n-x)!)] p x qn-x
- P = prob of outcome
- n = total events
- x = events in one category
- p = probability of x
- q = probability of other event
Two brown eyes heterozygotes (Bb) have 5 children. What is the probability that 2 of the cuples 5 children will have blue eyes?
P = [5! ÷ (2!)(3!)] (1/4)2 (3/4)3
P = 0.26 or 26%
Chi squared
explained
- shows goodness of fit aka how close the observed is to the hypothesis prediction
- does not prove hypothesis is correct
x2 = SUM OF (O - E)2 ÷ E
High chi square vs low
- High indicates low probability that deviations in observed are due to random chance (reject hypothesis)
- low indicates deviations due to random chance (do not reject hypothesis)
Process of making a karyotype
- sample of blood centrifuged after stopping cells in mitosis
- put in hypotonic solution causes blood cells to enlarge
- Put on slide to see karyotype (organized representation of cell)