Exam 1 Flashcards

1
Q

Who was the father of taxonomy and binomial nomenclature?

A

Linnaeus

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

What limits are there to binomial nomenclature?

A

It is based on observable traits and not how the organisms are related. Not suffieicnet for abcteria who only have a few observable traits (morphology, gram stain, sporulation, motility)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Who used 16s rRNA to make phyologenies?

A

Carl Woese

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

What makes 16s rRNA a good molecule for constructing phylogenies?

A

-Found in all organisms
-Fucntionally equivalent
-Homologous (derived from same ancestor)
-Not subject to lateral transfer
-Evolves slowly

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

What can you learn from a universal tree of life?

A

-Most life is microbial
-Chloroplasts and mitochondria arose from symbiosis with Cyanobacteria and Proteobacteria,
-The Last Common Ancestor (LCA) was probably a thermophilic, anerobic microorganismrespectively

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

How do you validate a universal tree of life?

A
  1. By comparing it to observable traits
  2. By using other molecules like ATPase, 23s rRNA, and ribosomal proteins
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

List three physiological/structural features that distinguish the Bacteria, Archaea and Eukarya from one-another.

A

-Eukarya have a nucleus while the other two don’t.
-Eukarya has multiple linear chromosomes while the others only have one circular chromosome.
-Eukarya have introns.
-Archaea are ether-linked lipids while the others have ester-links.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

List three physiological/structural features that can be used to argue that Archaea and Eukarya belong on the same branch of the Tree to the exclusion of Bacteria.

A

Neither has peptidoglycan. Both have histones and both use methionine for tRNA initiation while bacteria uses f-met

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

What are some limitations of 16s rRNA analysis?

A

-Cannot differentiate between closely related organisms
-Cannot account for horizontal gene transfer

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

How do you calculate dilution rate?

A

F/V flow rate/volume of culture vessel

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

How do you calculate the specific growth rate?

A

M=D or ln2/td (doubling time) needs to be in hours

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

What can you do in a chemostat but not batch culture?

A

Study physiology of slow growing
cells
* In the lab, E. coli doubles in ~30 min, but in the intestine ~12 hours!
* Mimic nature
* Feed toxic compounds
* Create microcosms (e.g., predator-prey dynamics with bacteria and
phage)
* Select certain mutants, like high affinity for a substrate.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

What does growth rate effect?

A

cell size, gene expression, and cell structure

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

How do you calculate doubling time?

A

take 2 points on the semilog graph. minutes/# doublings

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Why is doubling time important?

A

By comparing td under different growth conditions, you can figure
out what your organism prefers (37°C or 20°C? Glucose or
cellulose? Ammonia or alanine?)
* This gives clues to how the organism makes a living.
* By comparing WT to a mutant you can learn about the function of
specific genes.
* By keeping track of td you can tell whether your growth conditions
are same this month as last month, or the same in your lab as in
another lab.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Advantages of colony counts

A

Distinguishes live from dead cells
➢ Can detect low numbers of bacteria

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

Disadvantages of colony counts

A

But note that CFU is not necessarily the same as number of cells!
➢ Large errors if CFU used for bacteria that grow in clusters or chains

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

Advantages of direct count

A

Works for clumps/chains

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

Disadvantages of direct counts

A

➢ Poor detection limit: You need at least 106 cells/ml to see any in the
chamber, so not suitable for dilute cultures.
➢ Slow and laborious.
➢ Does not distinguish live cells from dead ones

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

Disadvantages of OD

A
  • OD measures mass, not number, so if turbidity doubles
    you could have twice as many cells or the same number of
    cells but they got twice a big.
  • OD detection limit about 107 cells/ml, so not suitable for
    dilute cultures (low population density)
  • OD increase is no longer linear at OD600 above approx. 0.8
  • Does not distinguish live versus dead cells
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
21
Q

Batch culture pros

A
  • Easy
  • Reproducible (concept of “balanced growth”)
  • Can get large samples of cell material for experiments/measurements
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
22
Q

Batch cultures cons

A
  • Limited time window to catch your samples
  • Hard to study growth under conditions of nutrient limitation
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
23
Q

You suspect that a bacterial culture contains approximately 108 cells/ml. How would you dilute and
plate this culture to obtain a countable plate in CFU assay?

A

-A countable plate has about 100 colonies.
-Dilute 1 ml culture into 9 ml fresh media. Now the concentration is 107 cells/ml.
-Repeat several times for a total of 5 dilution steps. You are down to 103 cells/ml.
-Spread 0.1 ml on a plate, incubate overnight, count colonies the next day. Alternatively, you can do a
further dilution and plate 1 ml.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
24
Q

Theme 1 of metabolism

A

A reduced compound gets oxidized, releasing energy
that is captured as ATP

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
25
Theme 2 of metabolism
Cellular redox reactions require electron carriers * NAD+ is a diffusible electron shuttle in the cytoplasm * Quinones are a diffusible electron shuttle in membranes * Iron-sulfur clusters, heme and flavins are incorporated into proteins (so not diffusible unless the protein diffuses).
26
Theme 3 in metabolism
Energy is captured in two ways * Ion gradient across a membrane (e.g., proton motive force) * “High energy bonds” as in ATP These can be used directly but are also interconvertible
27
What is the role of resonance stabilization in energy?
Products are more stable than reactants (ATP) giving them a much lower energy and resulting in a large release of energy Ex: NAD+ is a key electron carrier in metabolism NAD+ has more resonance stabilization that NADH Therefore, it is “hard” to put electrons into NAD+, but once they are there it is “easy” for NADH to donate those electrons to something else, like an electron transport chain. One can say NADH is a carrier of “high energy electrons”
28
Them 4 in metabolism
Two mechanisms of ATP synthesis ➢ Substrate level phosphorylation ➢ Harnessing a proton motive force (PMF)
29
What is glycolysis
converts glucose to pyruvate while producing a little ATP and a little NADH.
30
What is the most common pathway for glycolysis in bacteria?
mbden-Meyerhof Pathway (EMP) the most common pathway for converting glucose to pyruvate.
31
Steps in glyoclysis
-Phosphorylate glucose twice and isomerize it to fructose -Split it down the middle to produce triose phosphates -Oxidize the triose phosphates with concomitant formation of high-energy phosphate bonds -Harvest ATP from the doubly phosphorylated triose phosphates
32
Fermentation themes
1. Recovery of NAD+ that was reduced elsewhere in pathway 2. Stepwise reduction of carbonyl groups to alcohols 3. Sometimes generate an ATP if possible, usually via a CoA intermediate (SLP)
33
Conserved things in fermentation
Conserved features of these pathways are * Redox balance * Carbon redox patterns (e.g., acid to aldehyde to alcohol) * A site for energy conservation by substrate level phosphorylation * Variable features of these pathways are the specific substrates, intermediates and end products
34
What is the Stickland Reaction?
(fermentation of amino acids by some Clostridia) Ferment amino acid pairs One acts as the e- donor, the other as the e- acceptor Alanine/glycine pair is textbook exampleAlanine oxidized to acetate + C02 Glycine reduced to acetate Themes: recovery of NAD+, R-CoA intermediate allows synthesis of ATP by SLP.
35
Why can't glycolysis end with 2 ATP and 2 NAD?
NADH needs to be regenerated
36
TCA or Krebs cycle
1. Pyruvate from glycolysis converted to acetyl-CoA and fed into TCA cycle 2. Two carbons will be lost as CO2 as the cycle turns 3. Two turns per glucose 4. Direct synthesis of ATP (via Succinyl-CoA intermediate and GTP) 5. Generate 1 FADH2 6. Generate 3 NADH + H+ Each FADH2 will make 2 ATP in the ETC, while each NADH will make 3
37
Electron acceptors in respiration
O2, SO4, CO2, NADP
38
During glycolysis by the Embden-Meyerhof pathway a total of 4 ATP are produced, but the pathway is said to yield only 2 ATP per glucose. Explain this discrepancy.
Two ATP are invested at the start of the pathway, so the net gain is 2 ATP.
39
Which of the following produces CO2? Glycolysis TCA Cycle ETC with O2 as final electron acceptor Lactic acid fermentation Stickland fermentation of an alanine-glycine pair
Which of the following produces CO2? Glycolysis -NO TCA Cycle-YES ETC with O2 as final electron acceptor - NO Lactic acid fermentation – NO Stickland fermentation of an alanine-glycine pair - YES
40
Consider a hypothetical E. coli mutant that that cannot transfer electrons from NADH to O2 because it lacks a functional ETC. Would such a mutant grow in minimal media containing glucose as the energy source? Explain your reasoning.
Yes, such a mutant can grow by glucose fermentation. As noted in one of the slides, E. coli carries out the mixed acid fermentation, but the question did not specify that you include the name of the pathway.
41
In the reaction H2 + ½ O2 → H2O, what is the electron donor and what is the electron acceptor? What is the redox state of the H and the O at the start? At the end?
H2 is the donor and its redox state is 0 at the start, +1 at the end. O2 is the acceptor and its redox state is 0 at the start, -2 at the end.
42
Would you expect Clostridium difficile to grow on minimal media with alanine as the sole source of energy? What about E. coli? Explain your reasoning. You can assume C. difficile is incubated anaerobically but the E. coli culture is aerobic.
C. difficile→ No, it requires an electron acceptor such as glycine to ferment alanine. E. coli → Yes, alanine gets deaminated to pyruvate (look at the C. dif pathway I presented in class), and pyruvate can enter the TCA cycle.
43
E. coli can respire glucose with either oxygen O2 or nitrate (NO3-) as terminal electron acceptor. If given a choice, which do you think would be preferred? Use the Redox Tower from the lecture slides to justify your answer.
O2 is preferred because the energy drop is larger. The E0’ for the Nitrate/nitrite couple is +0.42 but for the O2/H20 couple it is +0.82.
44
Recall that the PMF powers not only ATP synthesis but also many transporters and flagella. How does a bacterium like E. coli generate a PMF when it is growing by fermentation?
Some of the ATP from fermentation is hydrolyzed by the F1F0 ATP “synthase” to generate a PMF. In other words, the F1F0 ATP synthase runs backwards.
45
How many CO2 are released per pyruvate in the TCA cycle? How many NAD+ and how many FAD are reduced?
2 CO2, 3 NADH and 1 FAD
46
What is the nernst equation
ΔG°‘ = -nFΔE0‘ = -2 x 96.48 kJ/V x 1.24 V = -239 kJ
47
What change in energy is minimally required for an organism
The cutoff for growth is about -30 kJ/mol
48
How do black smokers work
Superheated water (350°C) comes up from the mantle carrying dissolved minerals. The minerals ppt when the hot water mixes with cold sea water (2°C), creating black “smoke”. Sea water has lots of oxygen, allowing for bacteria to respire the reduced compounds emerging from the smoker. Sulfide oxidation is most important. The bacteria also fix CO2
49
How do the tube worms live?
Symbiosis with sulfur-oxidizing bacteria. The tubeworms have an internal organ called the “trophosome” that houses vast numbers of sulfur-oxidizing bacteria
50
How does the tube worm symbiosis work?
* CO2, O2 and H2S absorbed into blood in brachial plume; blood delivers these inorganic compounds to bacteria in trophosome (shown in blue) * Bacteria oxide H2S to produce ATP (an example of aerobic respiration). * The ATP (and reductant) are used to fix CO2 * Major N source is nitrate (NO3-), which the bacteria reduce to ammonia (NH3) and incorporate into amino acids. * Some of the organic molecules made by the bacteria pass into the blood; the tubeworm uses these for energy and biosynthesis
51
Describe the rumen's bacterial content
100-150 Liters 39°C pH 5.5-7 Anaerobic Well-mixed Typical cow rumen contains ~400 bacterial species at ~1010 bacteria per ml.
52
Rumen biochemistry
cellulose is converted to glucose using cellulase from bacteria. Feremnting bacteria then turn glucose into volatile fatty acids which go into the cows blood stream as energy. Methanogenic archaea take the leftover CO2 and H to make methane
53
Why are methanogens important?
Without methanogens the pathway grinds to a halt and the ruminant starves because the build up of H2 prevents fermentation. The H2 is an electron sink that the fermenters need to recover their NAD+.
54
How does salmonella produce inflamamtion
Neutrophils migrate into the lumen of the intestine, where they release reactive oxygen species (ROS) * ROS oxidizes thiosulfate to tetrathionate Bottom line: Salmonella provokes host inflammation to create its own private electron acceptor, thereby gaining a huge growth advantage over the “healthy” gut bacteria!
55
What are VFAs, how are they made in the rumen, and how does the ruminant benefit from them?
VFA = volatile fatty acids. Short-chain compounds like acetate, propionate, butyrate. They are produced by bacteria that ferment sugars released from cellulose and other complex carbohydrates derived from plant material. The VFAs diffuse across the rumen wall and enter the cow’s blood stream, ultimately to become a major source of energy for the cow which would otherwise be unable to digest cellulose.
56
How does the microbial consortium in the rumen allow herbivores to get energy from complex plant polysaccharides?
Cellulose degrading microbes convert cellulose to free sugars, which are then taken up and fermented to VFAs by fermenting bacteria. The VFAs provide energy to the cow, as described above (ultimately they enter the TCA cycle).
57
Explain what is meant by producer, primary consumer and secondary consumer. Provide an example of each from the hydrothermal vent ecosystem.
Producer = autotroph. Lithoautotrophic bacteria like the one that lives in Riftia trophosomes and gets energy by oxidizing sulfide to sulfate is an example. Primary consumer = an organism that eats the producers. Sea vent crabs eat bacteria. Secondary consumer = an organism that eats the primary consumers. An octopus that eats the crabs is an example.
58
Diagram Riftia pachyptila and use your cartoon to explain how an animal with neither a mouth nor an anus can obtain “food.”
H2S, O2, CO2 and NO3- are taken up by the worm in the gill plume, which is highly vascularized and exposed to sea water. These chemicals are abundant in the vicinity of deep sea hydrothermal vents because they are dissolved in superheated water that comes up from magma below. (Except for O2, which dissolves into sea water at the ocean surface.) The chemicals are of no use to the tube worm (except for O2—the tube worm is an aerobe with a metabolism like ours). The worm’s circulatory system transports the chemicals to the trophosome, where they diffuse into cells called bacteriocytes. Bacteriocytes are packed with symbiotic Proteobacteria that get their energy by oxidizing H2S with O2 as terminal electron acceptor. While most of the electrons liberated from H2S are used to make a PMF and thus ATP, some are diverted to biosynthesis, such as reduction of CO2 to make sugars. This is possible because the bacteria are autotrophs and have a Calvin Cycle like plants do. Meanwhile, the bacteria also reduce nitrate to ammonia, which they incorporate into glutamate and glutamine. From there the N can be transferred to various other N-containing molecules. Some of the carbon compounds and amino acids are exported to the Riftia. In summary, Riftia “feeds” the bacteria small molecules (H2S, O2, CO2 and NO3-). The bacteria are amazing biochemists who can turn these simple compounds into all the complex molecules that make up their cells. In return the bacteria “feed” their host sugars and amino acids.
59
The bacteria found as intracellular symbionts in bacteriocytes of Riftia pachyptila can be isolated and grown in pure culture in the lab. If you were designing a growth medium to isolate these organisms, what would you use as the energy source? As the carbon source? Would you incubate your plates aerobically or anaerobically? Explain your reasoning.
* Energy source = H2S, the preferred electron donor * C source = CO2 because the organism is an autotroph and fixes CO2 using the Calvin Cycle like plants do. So, would not add glucose (or the like) to the plates! * Incubate aerobically because O2 is the terminal electron acceptor for sulfide oxidation. Contrary to popular belief, there is plenty of O2 in seawater. Our lungs are not designed to extract dissolved O2, so we can’t breathe under water, but the O2 is there.
60
Salmonella in the gut can obtain energy from fermentation of carbohydrates or from respiring carbohydrates with tetrathionate as terminal electron acceptor. Where does the tetrathionate come from?
Anaerobic bacteria in the lumen of the small intestine make sulfide, H2S, as a byproduct of their metabolism. Because sulfide is toxic, our cells oxidize it to the harmless form thiosulfate,S2O32-. In response to a Salmonella infection our body mobilizes neutrophils, which transmigrate across the intestinal epithelium and release “reactive oxygen species” (ROS) in the lumen of the small intestine. The ROS is intended to kill invading pathogens, but some of it reacts with thiosulfate, converting it to tetrathionate, S4O62-.
61
magine that you infect a mouse orally with WT and ttrA mutant Salmonella (ttrA encodes one of the subunits of tetrathionate reductase). You observe that the animals dosed with WT Salmonella develop diarrhea, whereas those that received the ttrA mutant do not. How do you explain these findings?
he ttrA mutant Salmonella probably can’t colonize the gut because this mutant would not be able to use tetrathionate as terminal electron acceptor. Salmonella can grow by fermentation, but it is not very competitive against the dedicated fermenters (mostly Bacteroides and Clostridia) that make up our normal intestinal microbiota.