Exam 1 Flashcards
(14 cards)
Important derivatives
tan
sec
tan⁻¹
ln(x)
logₐ(x)
sin(3x)
sin(x²)
e^(-x²)
Rule:
tan(x) -> sec²(x)
sec(x) -> sec(x)tan(x)
tan⁻¹(x) -> 1/[1+x²]
ln(x) -> 1/x
logₐ(x) -> 1/ [x ln(a)]
sin(3x) -> 3cos(3x)
sin(x²) -> 2x cos(x²)
e^(-x²) -> -2xe^(-x²)
Rule: multiply constant inside
Derivative rules
Product:
uv = u’v + uv’
Quotient:
u/v = [u’v - uv’] / v²
Chain:
f(g(x) -> f(g’(x) * g(x)
Important integrals
1/x
1/[1+x²]
sin(3x)
Rule:
1/x -> ln|x|
1/[1+x²] -> tan⁻¹(x)
sin(3x) -> 1/3 * -cos(3x)
Rule: multiply by reciprocal
Graphs:
1/x
1/x²
ln(x)
eˣ
1/√x
Refer to goodnotes
Unit circle angles
0, π/6, π/4, π/3, π/2
π/2, 2π/3, 3π/4, 5π/6, π
π, 7π/6, 5π/4, 4π/3, 3π/2
3π/2, 5π/3, 7π/4, 11π/6, 2π
Integration by u-substitution and recycling
u ≠ x
recycle if u = x and the equation is linear
Position and velocity functions
Position is the integral of velocity
Velocity is the derivative of position
Setting up and solving FTC
P(b) - P(a) = ∫ᵇₐ P’(t) dt
Determining area of shaded region by graph and equation
If scanning horizontally:
∫ upper function - lower function ∆x
- In terms of x
If scanning vertically:
∫ right function - left function ∆y
- In terms of y
Disks
∫ π r² h dx
r² should be in terms of x
∫ π r² h dy
r² should be in terms of y
Washers
∫ π r² h dx
r² in terms of x, with (outer function)² - (inner function)²
∫ π r² h dy
r² in terms of y, with (outer function)² - (inner function)²
Shells
Riemann rectangle going horizontally:
2π ∫ x * (upper function - inner function) dx
- functions should be in terms of x
Riemann rectangle going vertically:
2π ∫ y * (right function - left function) dy
- functions should be in terms of y
exponents in the reciprocal
sign changes
Displacement vs. Distance
Displacement: x
Distance: |x|