Exam 2 Flashcards

(50 cards)

1
Q

Delta S (universe) > 0; Delta G < 0

A

Process is spontaneous as written

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2
Q

Delta S (universe) = 0; Delta G = 0

A

Reversible (process is not spontaneous in either direction) - system is at equilibrium

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3
Q

Delta S (universe) < 0; Delta G > 0

A

Process is spontaneous in reverse direction

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4
Q

Delta H = (-); Delta S = (-); -T Delta S = (+)

A

Spontaneous at low temp

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5
Q

Delta H = (+); Delta S = (+); -T Delta S = (-)

A

Spontaneous at high temp

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6
Q

What is physically happening to make Delta S&raquo_space;> 0?

A

Formation of ions, ion-solvent interactions, increased disorder

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7
Q

What is physically happening to make Delta H&raquo_space;> 0?

A

Absorbing heat in the dissolution process

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8
Q

If Delta G = 0, what equation can you use?

A

0 = Delta S (system) - T Delta S (system)

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9
Q

Rate of disappearance and rate of appearance

A

stoichiometric value of reactant / stoichiometric value of product = disappearance of reaction is ____ the appearance of product

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10
Q

Information we can get from kinetics

A

Speed, factors that influence speed; molecular mechanism (how the reaction occurs)

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11
Q

How do chemicals react?

A

must collide with enough energy and in the correct orientation

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12
Q

The more homogeneous the mixture of reactants

A

the faster the molecules can react

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13
Q

As the concentration of reactants increases

A

the likelihood that reactant molecules will collide increases

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14
Q

Catalyst

A

speed up reactions by changing the mechanism of the reaction; not consumed during the course of the overall reaction

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15
Q

Rate law

A

Rate = k[A]^n[B]^m ; n = reaction order of A; m = reaction order of B; overall reaction order = n + m

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16
Q

Determining Rate laws using Initial rates (change the concentration of only one of the reactants)

A

Rate 2/Rate 1 = k[B2]^n [C2]^m / k[B1]^n [C1]^m

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17
Q

Zero Order Equations

A

[At] = [Ao] -kt

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18
Q

Zero Order Graph

A

m = -k; y-intercept = [Ao], concentration as a function of time

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19
Q

1st order Equations

A

ln [At]/[Ao] = -kt ; [At] = [Ao]e^-kt

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20
Q

2nd order Equations

A

1/[At] - 1/[Ao] = kt; 1/[At] = kt + 1/[Ao]

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21
Q

Zero Order Equations

A

0.5[Ao] /k = t1/2

22
Q

1st order Equations

23
Q

2nd order Equations

A

1/k[Ao] = t1/2

24
Q

Transition State

A

The (rare) arrangement of atoms at the energy maximum during the course of the reaction

25
Activation Energy
the energy required to overcome the reaction barrier
26
k = Ae^(-Ea/RT)
A is the frequency factor, Ea is the activation energy, T is the absolute temperature
27
Intermediates are written
written below the line at each step
28
Transition states are written
above the line
29
the number of steps in the mechanism is indicated by
counted based on the bottom of each "hill"
30
A catalyst influence the rate of a reaction by altering
the value of Ea
31
A catalyst does not alter
the delta E of a reaction
32
catalysts are often prepared so they have ________ surface areas
very large
33
the rate-determining step is
the slowest reaction
34
unimolecular
only on reactant involved; A ---> products
35
Bimolecular
two molecules must collide to produce products; A + B ------> Products; 2A -----> Products
36
Termolecular
three different molecules must collide; A + B + C ----> Products; A + 2B -----> Products; 3A ------> Products
37
Exothermic reaction graph
reactants are higher than the products
38
Endothermic reaction graph
reactants are lower than the products
39
Homogenous Catalyst
has the same phase as the molecules in the reaction
40
Heterogenous Catalyst
has a different phase than the molecules in the reaction
41
Equilibrium is a state of dynamic molecular behavior, meaning that
reactants turn into products and products turn into reactants at equal rates
42
Equilibrium can only be achieved in a ______ system
closed system
43
Kf/Kr = keq
forward and reverse reactions
44
Equilibirum constant expressions
product/reactants; only gas and aqueous
45
Kc<<< 1
Reactant Favored, reactant predominates at equilibrium
46
Kc>>>1
Product Favored, product predominates at equilibrium
47
Qc has the same form as Keq
but there is no assumption of equilibrium
48
Q
System has too much reactant; shift toward product
49
Q=K
System is at equilibrium
50
Q>K
System has too much product; shift toward reaction