Exam 3 Flashcards
(38 cards)
Br2
Addition of Br and H (in one or 2 places)
H3CC=_CNa
Na is the spectator, add the leftover compound in place of the leave in group
Linda’s catalyst
Pairs with H2, breaks triple bond into a double
I mol Br
Anti addition, add Br to both sides cis
H2SO4
Forms ketone
BH3, THF
Connects to triple bond and pushes it down a carbon to make double bond, can leave oxygen on the end
H2
Lindlar, makes a triple bond a double
Na
(Excess) hydrogens on opposite sides of the triple bond and makes a double bond
NaH
Takes H off compound, easy for next to be added
OsO4
Cis OH on both sides of the double bond
SOCl2
Is swapped for the OH group and inverted
PBr3
Is swapped with the OH group
CN
Swaps with leave in group and inverts
H2SO4
Drops OH forms a double bond
TsCl
Pyridine, drops H from OH and added Ts (no inversion)
H2CrO4
Makes ketone (1+2 alcohol)
PCC
Double bond to oxygen (1) ketone (2)
IBX
Double bond to oxygen (1) ketone (2)
Sn2
Approach from opposite of the leave in (inverts)
Molecule is negative
(One bump left is higher then right)
Sn1
Step1- leave in group breaks off
Step 2- fast step (OH)
(Two bumps decreasing
E2
Removal of the beta carbon proton
MAKES DOUBLE BOND
(One bump)
E1
Step 1- remove leave in group
Step 2- fast step FORMS DOUBLE BOND
( two bumps)
Electrophilic addition
Opens double or triple bond and adds OH
(Two bumps)
Radical addiontion
ROOR, opens double bond and gains a hydrogen and Br