exam 3 : chapter 5 + 6

Question 1

the type of bond that results from side-on overlap of orbitals

Answer 1

pi bond (π)

Question 2

the type of bond that results from end-on overlap of orbitals

Answer 2

sigma bond (σ)

Question 3

true statements about the Lennard- jones potential diagrams

Answer 3

• When the nuclei are infinitely far apart, there is no repulsion or attraction between them: thus the potential energy approaches zero.
• As the internuclear distance decreases, the nuclear and electrostatic repulsions increase significantly , causing a steep increase in potential energy
• Once a balance is found between the attractive and repulsive forces, the outer orbitals are able to overlap, thereby allowing a bond to form.

Question 4

how to determine the pie and sigma bonds

Answer 4

single bond = 1 sigma bond

double bond = 1 sigma bond + 1 pi bond

triple bond = 1 sigma bond + 2 pi bonds