Exam II Flashcards
(29 cards)
Confidence interval is obtained as Select one: a. point estimate ± critical value b. point estimate ± standard error c. point estimate ± margin of error
c. point estimate ± margin of error
Given the sample proportion (p ̅) and sample size, n, we wish to obtain the confidence interval estimate of the population proportion (p). The margin of error of the confidence interval estimate is obtained as
Select one:
a. z(α/2) ×√((p(bar)(1-(p(bar))))/n)
b. z(α/2) ×√((p(1-p))/n)
a. z(α/2) ×√((p(bar)(1-(p(bar))))/n)
Margin of error is obtained as Select one: a. point estimate ± critical value b. critical value × standard error c. point estimate × critical value
b. critical value × standard error
Suppose (1-α)=0.9. The critical value, zα/2 , is obtained in Excel using Select one: a. –NORM.S.INV(0.05) b. –NORM.S.INV(0.1) c. –NORM.S.INV(0.2)
a. –NORM.S.INV(0.05)
Suppose (1-α)=0.95 and n = 20. The critical value tα/2, can be obtained in Excel using Select one: a. –T.INV(0.025, 19) b. –T.INV(0.05, 19) c. –T.INV(0.1, 19)
a. –T.INV(0.025, 19)
Suppose σ=36 and sample size n = 81. What is the standard error (S.E) of x ̅? Select one: a. 0.45 b. 4 c. 13.5
b. 4
The sample proportion, p(bar) = 0.25 and n=36. At the 99% confidence level, the margin of error is computed to be 0.05. Which one of the following represents the 99% confidence interval estimate of p? Select one: a. 0.25 ± 0.05 b. 0.25 ± 0.025 c. 0.25 ± 0.07
a. 0.25 ± 0.05
The sample proportion, p(bar) = 0.25 and n=36. The standard error of p(bar) (rounded to two decimal places) is given by Select one: a. √((0.25*0.75)/36) = 0.07 b. 0.25/√36 = 0.04 c. √(0.25*0.75) = 0.43
a. √((0.25*0.75)/36) = 0.07
We have n=15, x ̅=10, s=4 and (1-α)=0.99. The standard error of x ̅ (rounded to two decimal places) is Select one: a. 0.27 b. 1.03 c. 7.5
b. 1.03
We have n=15, x(bar)=10, s=4 and (1-α)=0.99. Using Excel and after rounding to two decimal places, the critical value, tα/2, is Select one: a. 2.98 b. 1.76 c. 2.14
a. 2.98
When one increases the confidence level (1-α), say from 0.90 to 0.95,
Select one:
a. margin of error will increase
b. the resulting confidence interval will capture the population parameter more often
c. both A and B are correct
c. both A and B are correct
When the population standard deviation (σ) is known and we wish to estimate μ, the margin of error is obtained as Select one: a. zα/2 × s/√n b. tα/2 × s/√n c. zα/2 × σ/√n
c. zα/2 × σ/√n
When the population standard deviation (σ) is NOT known and we wish to estimate μ, the margin of error is obtained as Select one: a. zα/2 × s/√n b. tα/2 × s/√n c. zα/2 × σ/√n
b. tα/2 × s/√n
Which one of the following is a point estimator? Select one: a. μ b. x (bar) c. p
b. x (bar)
We have n=15, x(bar) =10, s=4, and (1-α)=0.99. We wish to obtain the 99% confidence interval estimate of μ. What is the margin of error (rounded to two decimal places)?
3.07
Given the following: D: μ≥1000; E: μ<1000 D and E represent respectively. Select one: a. H(a) and H(0) b. H(0) and H(a) c. Type I error and Type II error
b. H(0) and H(a)
The value 1000 in question 1) above represents Select one: a. H(0) b. H(a) c. Hypothesized value
c. Hypothesized value
In hypothesis testing, the level of significance, α, represents
Select one:
a. The probability of making Type II error
b. The probability of making Type I error
c. The hypothesized value
b. The probability of making Type I error
An error that occurs when we fail to reject H(0) while false is called Select one: a. Type I error b. Type II error c. α
b. Type II error
Which one of the following cannot be an alternative hypothesis H(a)? Select one: a. p > 0.3 b. p ≥ 0.3 c. p < 0.3 d. p ≠ 0.3
b. p ≥ 0.3
Questions 6 to 10 are related. Based on a random sample of n=15 observations, we have obtained a sample mean of x(bar)=1050. The goal is to test: H(0): μ≤1000 and H(a): μ>1000 Assume that x is normally distributed with σ=150. What is the standard error (σ (x bar) )? Rounded to two decimal places. Select one: a. 150/15 = 10 b. 150/√15 = 38.73 c. None of the above
b. 150/√15 = 38.73
To conduct the test as given in question 6), which test statistics, is appropriate? Select one: a. t b. z c. F d. None of the above
b. z
Building on question 7), what is the value of the test statistics? Rounded to two decimal places. Select one: a. (1050-1000)/38.73 = 1.29 b. (1050-1000)/10 = 5 c. None of the above
a. (1050-1000)/38.73 = 1.29
Using α=0.1, what is the critical value (use Excel) for testing the hypotheses in question 6)? Rounded to two decimal places. Select one: a. –T.INV(0.1, 14) = 1.35 b. –NORM.S.INV(0.1) = 1.28 c. –T.INV(0.05, 14) = 1.76 d. -NORM.S.INV(0.05) = 1.64
b. –NORM.S.INV(0.1) = 1.28