EXAM - Questions to Memorise Flashcards

1
Q

State and explain the angle which will produce the maximum range as the launch height increases

A

launch angle becomes less then 45

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2
Q

Explain terminal velocity

A

Terminal velocity occurs acceleration due to gravity is canceled out by the area resistance making the net force on an object 0.

Air resistance increases with velocity.

When parachuter deploys their parachute their velocity decreases and thus the air resistance slowly increase until a new terminal velocity is reached.

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3
Q

Describe and explain the effects of air resistance on:

  • vertical and horizontal components
  • max height
  • range
A

Vertical component:
slowed on way up and down (takes longer to fall from max height to ground)
Horizontal - deccelerates
Max Height - decreases max height (same flight time)
Range - Decreases range with sudden drop

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4
Q

Explain why Newton’s Law of Universal Gravitation is consistent with Newton’s third law of motion.

A

Newton’s 3rd Law states that the objects exert equal sized but oppositely directed forces as each other.

As the gravitational force on each star is proportional to the product of their two masses, the magnitude of force on both stars must be the same.

As gravitational force is attractive, the forces on the stars must be in opposite directions (towards the other star).

Hence, the gravitational force between the stars is consistent with Newton’s 3rd Law.

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5
Q

Explain why an object travelling in a circular path accelerate even though it has a constant speed.

A

As the direction of the object is constantly changing, its velocity is changing. As acceleration involves a change in velocity the object is therefore accelerating.

OR There’s a net force always perpendicular to the velocity. According to Newton’s 2nd Law, this force results in an acceleration.

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6
Q

Use one of Kepler’s Laws to explain why comets in highly elliptical orbits are only seen once in a large number of years, and when they are seen, they are only observed for a short period of time.

A

From Kepler’s 1st Law, the sun is at one focus of the comet’s elliptical orbit. As the orbit it highly elliptical, the comet passes close to the sun and turns again a large distance from the sun. It takes the comet a long time to travel the large distance to the far point of the orbit.

According to Kepler’s 2nd Law, the area swept per unit time is equal at all points along the orbit path. Hence, when the comet is close to the sun, it is traveling very fast and it only seen for a short time.

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7
Q

Explain how particles formed in the upper atmosphere are able to be detected, despite having short decay times.

A

Since particles formed in the upper atmosphere are moving at high speeds from the frame of reference of a stationary observer on Earth, time is dilated and moves slower for the particles. Therefore, in their frame of reference they only move a short distance, an observer on Earth will measure a significantly larger time period before it decays, and hence a greater distance is travelled. The means the particles can travel longer distances and be detected on Earth.

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8
Q

Explain why it is impossible to accelerate an object to he speed of light, even if it has a continuous force acting upon it.

A

As an object approached the speed of light, the kinetic energy approaches infinity. For an object to reach the speed of light, the work done on the object too would approach infinity. Since it is impossible to do an infinite amount of work on a mass, it is impossible to reach the speed of light.

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9
Q

Describe the path followed by an electron in a uniform electric field (with positive plate on the top)

A

The path followed by the electron is parabolic and towards the positive plate. This is because the electric force acting on it is constant in magnitude and direction (upwards towards positive plate). This force causes the vertical velocity to change; whilst its horizontal velocity remains constant thus causing parabolic motion.

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10
Q

Describe how Lenz’s Law is consistent with the Law of Conservation of Energy

A

Lenz’s Law states that an induced emf created by a change in magnetic flux, creates an induced current which opposes the change in magnetic flux producing the emf.

According to the Law of Conservation of Energy, energy cannot be created or destroyed.

The work done in overcoming the opposing force that is produced when a change in magnetic flux occurs is converted to electrical energy.

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11
Q

Describe the relationship between the oscillating electric and magnetic field and the direction of travel of an EM wave

A

The electric and magnetic fields oscillate perpendicular to each other and perpendicular to the direction of travel of the wave.

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12
Q

Give one reason why light from an incandescent source is not coherent

A

It does not give off waves with a constant phase relationship between them as the many charges in the hot filament oscillate randomly in both phase and frequency.

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13
Q

State one safety precaution that should be taken when using a laser

A

ONE of the following:

  • Do not darken the room in which you are using the laser
  • Do not place your eye or others in the path of the laser beam
  • Do not shine the laser onto reflective surfaces
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14
Q

Derive fmax = ev/h

A

Work done by the electric field in accelerating the electrons is equal to the gain in kinetic energy of the electrons
TF, eV = K

Max frequency occurs when an electrons loss all it energy to a single photon.
Ep = hfmax

TF, eV = hfmax
fmax = eV/h

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15
Q

Sketch a labeled graph of a typical spectrum produced by an x-ray tube.
Also state how the maximum frequency will change if he tube current is increased.

A

Reaches a peak intensity
characteristic peaks
f-max when intensity is 0

Tube current will not change fmax

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16
Q

X-rays can be controlled by the filament current and potential difference across the tube.
Identify, giving reasons, which of these settings could be used to reduce the exposure time to the x-rays.

A

the exposure time can be reduced by increasing the filament current. The greater no. of electrons flowing through the filament per unit time -> the greater the no. of photons emitted per unit time
-> the shorter the exposure time would be.

17
Q

State one other in which the controllers of the X-rays can reduce their exposure time.

A

ONE of the following:

  • increase distance from the source
  • use adequate shielding
18
Q

State two characteristics of body tissue that affect the attenuation of a beam of X-rays.

A

TWO of the following:

  • Nature (density) of tissue
  • Thickness of tissue
  • Atomic no. of atoms in tissue
19
Q

Briefly describe the Davisson-Germer Experiment and state the significance of the results

A
Low energy (54eV) electrons were fired at the surface of a nickel crystal and any reflected electrons were detected, with the number of electrons and angle from the original direction measured. 
Low energy electron ensured the reflection was from the surface of the crystal rather than various layers inside the crystal.

Most electrons were reflected at angles less than 20° but some were reflected at greater angles.
The decrease in number of electrons as angle increased was expected. However, the increase beyond 35° and peak at 50° can only be explained by constructive interference.

Hence, the significance of results is that they show particles with mass can experience diffraction and interference and thus show wave behaviour.

20
Q

Describe the changes in the observed frequency distribution of light that would be produced if the temperature of the filament were increased.

A

As the temperatures increased, a higher range of frequencies is observed and all frequencies have a greater intensity. The peak frequency will increase.

21
Q

Define the term ‘ionisation energy’

A

The ionisation energy is the minimum energy required to remove an electron from an atom in its ground state.

22
Q

Absorption lines from hydrogen are observed in the visible part of the the suns spectrum.
Explain the presence of these lines.

A

the atmosphere of the sun is very hot and thus a significant number of hydrogen atoms are in the excited state rather than the ground state.

TF, the hydrogen atoms can absorb visible light from the sun and become more excited.

When these atoms return to ground state they release photons in random directions.

TF, fewer photons of these frequencies reach earth resulting in black lines on spectrum.

23
Q

Explain what is meant by the process of fluorescence

A

Fluorescence is emission of lower energy photons following the absorption of a single higher energy photon.

The high energy photon has an energy corresponding to one of the transitions for ground state to an excited state in an atom and thus excites the atom. The atom can return to ground state via a series of lower energy transitions, releasing a range of lower energy photons.

24
Q

Explain why there are no visible absorption lines for hydrogen at RT.

A

1

25
Q

Explain what a metastable state is

A

A metastable state is when an atom is able to remain in the excited state for a longer period of time.

26
Q

Explain why a metastable state is necessary for a population inversion to occur

A

Atoms in the metastable state remain in the excited state for a longer period of time.
This allows time for a larger number of atoms to be in the excited metastable state.
This results in a population inversion where more atoms are in the higher excited than the lower excited state.

27
Q

Explain why a population inversion is necessary to produce a laser beam

A

Fo stimulated emission to predominate over absorption a population inversion must occur. Lasers are produced by stimulated emission.
TF, a population inversion is necessary for a laser to be produced.

28
Q

Explain how line absorption spectra are produced

A

Line absorption spectra are produced when a continuous spectra is incident on the element in gaseous form.
Line absorption spectra appear as a continuous spectra with black lines showing the specific energy photons that are absorbed.
The photons absorbed match the energy transitions upwards from the ground state of the atoms.
When atoms return to the ground state they re-emit photons of the same frequency as those absorbed but very few in the initial direction.
Therefore, few reach the observer resulting in black lines.

29
Q

Explain how line absorption spectra can be used to identify elements.

A

The photons that are absorbed by different elements depend upon that element’s energy levels.
Since no two elements have the same energy levels, it is possible to match the photons absorbed to a specific element.

30
Q

What features show that an interference pattern is produced by two slits?

A

Equally spaced fringes

Wide fringes not sharp

31
Q

When a new wavelength is diffracted what features will change in the new pattern?

A

Distance between adjacent maxima

Colour of pattern

32
Q

In hydrogen spectrum starting/finishing at n=2 is what type of light?

A

Visible light

33
Q

In hydrogen spectrum starting/finishing at n=1 is what type of light?

A

UV light

34
Q

In hydrogen spectrum starting/finishing at n=3 is what type of light?

A

Infra-Red light

35
Q

Explain why the slits in a diffraction grating should be comparable with that of the light used in the experiment.

A

Interference requires overlap of the light from he different slits. This requires diffraction at large angles and this occurs when d approx = wavelength.

36
Q

Components of SHE question

A

1