Exam Revision Flashcards
(32 cards)
Find the equation of the tangent plane to the surface f(x, y, z) ≡ x^2+y^2+z^2=4 at the point (1, 1, 1)
The gradient of f is (2, 2, 4) at the point (x, y, z) = (1, 1, 1). The normal vector to the surface, and
therefore to the tangent plane is proportional to (2, 2, 4). The equation of the tangent plane
is of the form 2x+ 2y + 4z = K. Since the point (1, 1, 1) lies on the tangent plane we have
K = 2 + 2 + 4 = 8 and the equation of the plane is 2x + 2y + 4z = 8 or x + y + 2z = 4.
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