Exercise 8: ALCOHOLS Flashcards

1
Q

which is the
active component of alcoholic
beverages, is just one and most common
among the large family alcohols.

A

Ethanol (ethyl alcohol)

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2
Q

organic compounds composed of an aliphatic carbon atom with a
hydroxyl (-OH) functional group

 very common and may exist freely in nature

 exhibit some unique set of physicochemical properties mainly due to
the presence of the hydroxyl functional group

A

Alcohols

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3
Q

 the is a functional group of all alcohols, hence the
general formula of ROH, where R is the alkyl group

A

hydroxyl group

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4
Q

 some of the properties of alcohols depend on the

A

length of the alkyl chain attached to the hydroxyl group

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5
Q

 C with the –OH group attached to one other carbon atom
 general formula:

A

primary (1°) alcohol

RCH2OH

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6
Q

 C with the –OH group attached to two other carbon atoms
 general formula:

A

 secondary (2°) alcohol

R2CHOH

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7
Q

 C with the –OH group attached to three other carbon
atoms
 general formula:

A

 tertiary (3°) alcohol

R3COH

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8
Q

generally have higher boiling points as compared to hydrocarbons
having the same molecular masses

mainly due to the in between the OH
groups

A

BOILING POINT

intermolecular H-bonding

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9
Q

boiling point = number of C in the aliphatic chain
boiling point  = branching in aliphatic carbon chain 

A

Increase. Increase
Decrease, increase

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10
Q

governed by its ability to perform intermolecular H-bonding with
polar solvents

A

SOLUBILITY

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11
Q

 are usually formed in between the OH group of alcohol
and water (which makes alcohol soluble with H2O)

however, the longer the alkyl chain is, the - alcohol
becomes soluble with water

A

H-bonds

lesser

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12
Q

acidic in nature because of their ability to react with active metals
(e.g. sodium, potassium,) forming the corresponding

A

ACIDITY
alkoxide

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13
Q

acidity is due to the

A

polarity of the hydroxyl bond

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14
Q

acidity  = when an electron donating group is attached to the
hydroxyl group as the electron density increases on the oxygen
atom

A

Decrease

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15
Q

primary alcohols are - than secondary and tertiary
alcohols

A

more acidic

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16
Q

PROPERTIES OF ALCOHOLS

A

Boiling point
Solubility
Acidity

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17
Q

alcohols exhibit a
range of
spontaneous
chemical
reactions due to

A

the cleavage of
C-O and O-H
bonds

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18
Q

JONES TEST (CHROMIC ACID TEST) results

n-butyl alcohol

A

blue-green solution
changes color much faster

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19
Q

JONES TEST (CHROMIC ACID TEST) results

sec-butyl alcohol

A

blue-green solution
changes color much slower

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20
Q

JONES TEST (CHROMIC ACID TEST) results

tert-butyl alcohol

A

orange solution
n/a

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21
Q

used to distinguish primary and
secondary alcohols from tertiary alcohols

 positive result: blue-green solution

A

JONES TEST (CHROMIC ACID TEST)

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22
Q

 reagent: Jones reagent ();

A

chromium oxide CrO3 in sulfuric acid H2SO4

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23
Q

JONES TEST (CHROMIC ACID TEST) named after

A

named after Ewart Jones

24
Q

JONES TEST (CHROMIC ACID TEST) principle: detect polar functional groups that can
be oxidized:

  • are oxidized to carboxylic acid while
  • to ketones; the
  • is reduced to a - species, which often precipitates in acetone
A

1° alcohols and aldehydes

2° alcohols

orange hexavalent chromium (Cr6+), blue-green trivalent chromium (Cr3+)

25
LUCAS TEST results n-butyl alcohol
Clear colorless soln N/a
26
LUCAS TEST results n-butyl alcohol
clear colorless solution n/a
27
LUCAS TEST results sec-butyl alcohol
two-layer solution forms layer much slower
28
LUCAS TEST results tert-butyl alcohol
Turbid solution immediate
29
LUCAS TEST results benzyl alcohol
turbid solution often immediate
30
used to distinguish tertiary and secondary alcohols from primary alcohols  positive result: turbid solution/formation of two layers
LUCAS TEST
31
 reagent: Lucas reagent
zinc chloride ZnCl2 in concentrated hydrochloric acid HCl)
32
 positive result: lucas test
turbid solution/formation of two layers
33
LUcas test named after
Howard Lucas
34
positive result: Jones Test
blue-green solution
35
LUCAS TEST principle: SN1 mechanism to produce - which appears as white precipitate or cloudiness of the solution; often give immediate results like tertiary alcohols
insoluble alkyl chloride benzyl, allylic and propargylic alcohols
36
ESTERIFICATION REACTION results methanol + salicylic acid
minty odor immediate
37
function of test: used to demonstrate reactivity of alcohols with carboxylic acids when heated with acid catalyst  positive result: methanol with salicylic acid results to minty odor (methyl salicylate); esters results to characteristic fruity-like odor
ESTERIFICATION REACTION
38
 positive result: Esterification rxn
methanol with salicylic acid results to minty odor (methyl salicylate); esters results to characteristic fruity-like odor
39
reaction is both slow and reversible
Fischer esterification reaction;
40
TEST FOR METHANOL COLOR
red-violet ring at the junction of the two layers with dark red flocculent precipitate
41
function of test: demonstrate oxidation of alcohols through partial oxidation and dehydrogenation using hot catalyst (heated copper)
TEST FOR METHANOL
42
TEST FOR METHANOL  principle: methanol is oxidized to - using - as catalyst; to detect if methanol was oxidized, - is added to the solution and - is added dropwise to induce color change, precipitates and layer formation (method was introduced by)
methanal (formaldehyde), heated copper resorcinol, concentrated sulfuric acid) Robert Mulliken
43
IODOFORM TEST results ethanol
clear colorless solution
44
IODOFORM TEST results isopropyl alcohol
turbid yellow solution with canary yellow precipitate
45
IODOFORM TEST results methanol
clear colorless solution
46
function of test: used to identify methyl ketones or secondary alcohols adjacent to a methyl group  positive result: turbid yellow solution/canary yellow precipitate
IODOFORM TEST
47
 reagent: Wagner’s reagent ; is used to decolorize the solution
iodine in potassium iodide) sodium hydroxide
48
 positive result: Iodoform Test
turbid yellow solution/canary yellow precipitate
49
Iodorm Test principle: I2 in KI in NaOH reacts only for compounds with the structure to form (canary yellow precipitate); does not work for all alcohols or ketones and does not work also for water-insoluble compounds
RCH(OH)CH3 or RC=OCH3, iodoform
50
ACROLEIN TEST results glycerol
pungent acrid odor
51
used to detect the presence of glycerol  positive result: pungent acrid odor
ACROLEIN TEST
52
 sample: - a polyhydroxy alcohol (triol) obtained as a by- product from the manufacture of soap used as a moisturizing agent in cosmetic formulations
glycerol
53
AcroleinTest  principle: when heated with, glycerol is dehydrated to form
potassium bisulfate (KHSO4), propenal (acrolein)
54
eagent: Wagner’s reagent
Iodoform Test
55
reagent: Lucas reagent
Lucas Test
56
reagent: Jones reagent
Jones Test