Exponent and radical SAT Flashcards
(47 cards)
Which of the following expressions is equivalent to the expression above?
√75x^4/ √12x^7
SIMPLIFY FIRST :
√ 75 x.x.x.x : 12 x.x.x.x.x.x.x =>
√75 : 12x³
√3 . √25 : √3 . √4 x√x
5 : 2x√x
Which of the following expressions is equivalent to the expression above?
5¹/³ - 5 ^³/4
1) Radicals sum -> turns to multiplying : the big one will be ¹ . ¹ - big one ; The small one will be 1 . ^small one
- 5¹/³ - 5 ¹ - ³/4 . 5¹
- 5¹/³ - 5 ¹/³ . 5¹
(ISOLATE) 5¹/³ ( 1 - 5)
Y + Y²/ Y -²/³
Y- ²/³ => go to the numerator
(y+y²) y²/³ => y.y²/³ + y² . y²/³
y^5/3 + y ^7 /3
x - 5√x + 6 = 0
1) ISOLATE THE RADICAL x +6 = +5√x 2) Take out the radical : ² (x+6)² = 25x x+12x + 36 - 25x = 0 x - 13x + 36 = 0
sum ( -13x) and product (36) :
-9 + -4 and -9.-4
CONVERT THE SIGNALS
+ 9 e +4
√x² - 4x - 4 = 0
√ extends to -4x-4
1) TAKE OUT THE RADICAL:
(√x² - 4x - 4)² = 0²
x² - 4x - 4 = 0
sum ( -4x) and prod ( -4) = -2.-2
CONVERT THE SIGNALS = +2
√y² -15y - 4 = 0
ratio extends to y-15
What is the sum of all solutions
√y² - 15y = + 4
y² - 15y = 4²
y² - 15y - 16 = 0
-15² - 4.-16.1 = 225 + 64 = 289
- (-15) +- 17 : 2
+1 and -16
REPLACE THE ROOTS
y² - 15y = 16
1² +15 = 16 (v)
-16² - 15.16 = 16 (v)
-1 + 16 = 15
x - 5√x + 6 = 0
ISOLATE THE RADICAL:
(x+6)² = (+5√x )²
x² + 12x + 36 = 25x
x² - 13x + 36 = 0
-13² - 4.36.1
169 - 144 = 25
-(-13) +- 5 : 2
4 and 9
REPLACE THE ROOTS
4² - 13. 4 + 36 = 0 (v)
9² - 13.9 + 36 = 0 (v)
4+ 9 = 13
√3z + 6 - z = 2
! the √ extends to 3z+6
What is the largest solution to the above equation?
ISOLATE THE ROOTS
(√3z + 6)² = 2+z )²
3z + 6 = z² + 4z + 4
z² +z - 2 = 0
- 1 + 2 = 1
- 1.2 = -2
INVERT THE SIGNALS
-1 and +2
2√9x - 6 = 10 - 2 √x
2√9x = 2 √x => 2.3√x = 2√x -16 = 8√x 8/16 = √x 2 = √x = 4
Don’t solve the quadratic form in traditional way, rather:
15y - 5√y = 0
SIMPLIFY AS POSSIBLE
:3
(3y - √y = 0) ²
9y² - y = 0
QUADRATIC = FACTOR
y (9y -1) = 0
EQUAL 0
y = 0 9y-1= 0 y = +1/9
Don1t solve the quadratic for, rather
5t = 5√t
factor it out and equals to 0
25t² = 25.t 25t² - 25t = 0 5t ( 5t - 5) = 0 5t = 0 -> t = 0 5t-5 = 0 5t = 5 -> 1
Ratio + both numerator and denominator has x
-2x + 14/3x = 4
-2x + 14 is one numerator to 3x which is denominator
- MULTIPLY the denominator in BOTH SIDES ( eliminate denominator )
-2x+14 = 12x
14x - 14 = 0
14x = +14
x = 1
ratio with x = ratio :
y/4y -3 = 2 /3
CROSS MULTIPLY 2y = 12y - 9 10y - 9 = 0 1oy = +9 y = 9/10
quadratic form don’t need to be solved in trad way :
FACTOR IT AND EQUALS 0 w² = √108w )² w² -108w = 0 w ( w-108) = 0 w=0 w= +108
√ = the answer is only _ numbers
√100 =
a) -10
b) +10
c) -10 + 10
d) 0.1
b
in positive numbers
3/c+4 + 1/4
a) 1
b) 4/ c+ 8
c) c+16 / 4c+16
- same denominator = denominator 1. denominator 2 => MMC 4 (c+4)
- Multiply needed number to the same denominator
3/c+4 x 4 = 12/ 4(c+4)
+ 1/4 x 4 = 4/4(c+4)
12/ 4(c+4) + 4/4(c+4) = 16/4(c+4)
C
x/ x² +5x - 14 + 7/ x² +5x - 14
a) x+7/ 2x² + 10x - 28
b) x7 / x² +5x - 14
c) 1/x-2
d) 1 /x+2
X+7 / x² +5x - 14
NO SUCH ANSWER IN THE OPTIONS : FACTOR, SIMPLIFY
x+7 / (x - 2) (x+7)
CUT the same
c) 1/x-2
SIMPLIFY AS POSSIBLE
x²/x-2 + 4/2-x
x is different with 2
ALWAYS REMAINS THE X - number
4/2-x (.-1) => -4/x-2
x² /x-2 -4/x-2 = x² - 4 /x-2
NO SUCH ANSWER = FACTOR, SIMPLIFY
(x -2) (x+2) / (x-2) - since there is no number.x
CUT
x+2
5m/m² -24mn + 144m² + 2n/ m²-144n²
a) 5m² +60nm - 2n² / (m-12) (m+12)
b) 5m² + 60nm - 24n² / (m-12)² (m+12)
c) 5m² + 60nm - 24n² / (m-12) (m+12)²
- FACTOR
5m/ (m -12n)² + 2n/ (m-12n) (m+12n) - since there is no number.x - Same denominator : multiplies down and up the needed number
5m/ (m -12n)² (. m+12n) = 5(m+12n) / (m -12n)² (m+12n)
2n/ (m-12n) (m+12n) = 2n (m-12n) / (m-12n)² (m+12n)
B
x³+ 7x² + 10x /x² + 2x
a) x+ 5
b) x+8
c) x³ + 6x²+ 8x
- factor
x (x² + 7x + 10) / x ( x+2)
x ( x+5) (x+2) / x ( x+2) - CUT x and (x+2)
x+5
if P(x) = g² + 10g + 25 and Q(x) = g+5, so P(x) . Q(x) =
a) (g³+5)²
b) (g+5)³
c) (g+5) (g+5)
d) (g²+5)²
- factor
g²+10g+25 = (g+5)²
(g+5)² . g+5 = g+5)³
The equation s = (t+3)²(t+2)(t+1)(t)(t-1). How many roots are there.
(t+3)² = -3
(t+2) (t+1) = t² + 2t + 2 -> +1
t (t-1) = t = 0 and t-1= 0 = +1
THERE ARE -3,+1,0 3 roots
A polynomial function f is defined as f(x)=(10x-3)(4x+1)(5x-2.)
What is the sum of all of the zeros of function f?
10x-3 = +3/10 -> 0.3
4x + 1 = -1/4 -> -0.25
5x-2 = +2/5 -> 0.4
Sum them
A polynomial function P is defined as P(x)=0.5(3x+5)(3x-1) parenthesis in the x‑plane?
0.5 ( 3x+5) (3x-1) = 0
(3x+5) (3x-1) = 0/0,5
3x+5 = 0 ; 3x-1 = 0
x = -5/3 x = +1/3