Final Exam Flashcards

(54 cards)

1
Q

Mendel’s Law of Segregation

A

Mendel’s Law of Segregation states that during the formation of gametes (sperm and egg cells), the two alleles for a given trait separate, so that each gamete carries only one allele for that trait. This means that each parent contributes only one of their two copies of a gene to their offspring.

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2
Q

Mendel’s Law of Independent Assortment

A

Mendel’s Law of Independent Assortment states that the inheritance of one trait does not influence the inheritance of another trait. In simpler terms, this means that different genes and their corresponding alleles (variants of a gene) separate independently of one another during the formation of gametes (sex cells).

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3
Q

Recombinant Mapping

A

The # of recombinant offspring / total # of offspring x 100% = recombination frequency

Recombination frequency = map units = centiMorgan (cM).

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4
Q

Aneuploidy

A

a condition where a cell or organism has an abnormal number of chromosomes. This can be due to having extra chromosomes (trisomy) or missing chromosomes (monosomy). A normal human cell has 46 chromosomes

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5
Q

Crossing over

outcome

A

a crucial process in genetics where homologous chromosomes exchange genetic material during meiosis, leading to increased genetic variation in offspring

1 normal, one duplicated, one inversion and one deletion

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6
Q

Cytosine deamination into uracil and permanent mutation

A

can lead to permanent mutations because uracil, which has a different base-pairing behavior than cytosine, can be incorporated into DNA during replication, resulting in a C:G to T:A transition

This occurs when uracil, formed from the deaminated cytosine, pairs with adenine instead of guanine during DNA replication, leading to a change in the original DNA sequence.

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7
Q

Double stranded break and issue repairing

A

Double-stranded breaks are breaks where both strands of a DNA molecule are damaged.

This pathway uses a homologous DNA sequence (like a sister chromatid) as a template to repair the broken DNA strand. It’s considered the most accurate repair method.

This pathway rejoins the broken DNA ends directly, without needing a homologous template. It’s often used when HR is not available, but it can introduce small insertions or deletions at the repair site.

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8
Q

Base Excision Repair (BER)

A
  1. Base Removal:
    A DNA glycosylase enzyme recognizes and removes the damaged or incorrect base, creating an apurinic/apyrimidinic (AP) site.
  2. AP Site Processing:
    An AP endonuclease cleaves the sugar-phosphate backbone at the AP site, creating a single-strand break.
  3. Gap Filling and Ligation:
    DNA polymerase (Pol β) fills the gap with the correct nucleotide, and DNA ligase seals the nick, restoring the original DNA sequence.
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9
Q

One repair mechanism for DBS

A

This pathway uses an undamaged sister chromatid or homologous chromosome as a template to repair the break. This ensures a precise repair without introducing mutations. HR is initiated by the recognition of the DSB by proteins like the MRN complex (Mre11, Rad50, and Nbs1), which then facilitates the use of the homologous template for repair.

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10
Q

Compare genetic outcomes of meiosis and mitosis

A

Mitosis produces two genetically identical daughter cells from a single parent cell, while meiosis results in four genetically unique daughter cells, each with half the number of chromosomes of the parent.

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11
Q

Incomplete dominance

A

a heterozygous individual’s phenotype is a blend of the two homozygous phenotypes, rather than one being completely dominant over the other. This results in an intermediate trait where both alleles are expressed to some degree.

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12
Q

Codominance

A

In codominance, both alleles for a trait are expressed equally in a heterozygote, meaning the offspring exhibits both traits.

(EG: AB blood type)

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13
Q

Degrees of dominance

A

refers to how one allele’s expression masks or influences the expression of another allele in a heterozygote.

This can range from complete dominance, where the dominant allele completely hides the recessive allele, to incomplete dominance, where the heterozygote shows a blended phenotype, and co-dominance, where both alleles are expressed simultaneously.

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14
Q

Dihybrid cross

A

a breeding experiment where two organisms, each heterozygous for two traits, are crossed. This results in a characteristic 9:3:3:1

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15
Q

Epistasis in regards to dihybrid cross and genes

A

a type of gene interaction where one gene’s allele masks or modifies the phenotypic expression of another gene at a different locus.

This interaction can alter the expected phenotypic ratios in a dihybrid cross, which typically predicts a 9:3:3:1 ratio when two genes are independently segregating.

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16
Q

sex-limited

A

a characteristic that is expressed in only one sex of a species, even though both males and females carry the gene for that trait

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17
Q

sex-influenced

A

a genetic trait where the expression of a gene differs between males and females, despite the gene not being on the sex chromosomes

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18
Q

X-linked inheritance

A

the passing down of genetic traits or disorders located on the X chromosome

In X-linked recessive inheritance, a single copy of a mutated gene on the X chromosome is enough to cause a condition

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19
Q

Lyon hypothesis in females and why is it necessary

A

The Lyon hypothesis, also known as X-inactivation, explains how females, having two X chromosomes, compensate for the potential “double dose” of X-linked genes compared to males who have only one.

One of the two X chromosomes in females is randomly inactivated in each cell during early embryonic development, preventing a double expression of X-linked genes.

This inactivation is essential for maintaining a balanced expression of X-linked genes in both sexes.

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20
Q

MELAS syndrome in children and mtDNA

A

MELAS syndrome, caused by mutations in mitochondrial DNA (mtDNA), is a mitochondrial disorder that typically manifests in childhood, often with symptoms appearing between ages 2 and 10.

MELAS is inherited maternally, meaning it is passed down from the mother to her children.

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21
Q

Mitochondrial DNA inheritance

A

primarily inherited from the mother, meaning that most of the mtDNA in a child’s cells is derived from their mother’s egg.

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22
Q

Template strand is 3’-5’

A

Yes, the template strand of DNA is read in the 3’ to 5’ direction. This direction is necessary for the enzyme DNA polymerase to synthesize a new DNA strand in the 5’ to 3’ direction, ensuring the new strand is complementary to the template.

23
Q

Formation of the DNA polymerase initiation complex at core promotor in eukaryotes

A
  1. TFIID and the TATA box:
    TFIID, a complex of proteins including TATA-binding protein (TBP), is the first to bind to the TATA box, a sequence-rich region in the core promoter. This interaction acts as the initial anchor for the assembly of the transcription machinery.
  2. Recruitment of GTFs:
    The binding of TFIID facilitates the recruitment of other general transcription factors, such as TFIIB, TFIIF, TFIIE, and TFIIH, to the promoter. These factors play various roles in unwinding the DNA, preparing it for transcription initiation, and recruiting RNA polymerase II.
  3. Pol II recruitment:
    Once the GTFs are assembled, RNA polymerase II (Pol II) is recruited to the promoter, forming the pre-initiation complex (PIC).
  4. PIC and initiation:
    The PIC is initially in a closed state, meaning the DNA around the transcription start site is still tightly bound. Before transcription can begin, the DNA must be unwound and the template strand loaded into the active site of Pol II, forming an open complex. This process requires the activity of some GTFs and other factors.
  5. Initiation and elongation:
    Once the open complex is formed, Pol II can initiate RNA synthesis, marking the beginning of the transcription elongation phase.
24
Q

Enhancer (transcription)

A

a DNA sequence that increases the rate of gene expression. They are cis-acting elements, meaning they act on the same DNA molecule as the gene they regulate.

25
TATA box (transcription)
a DNA sequence, often located 25-30 base pairs upstream of a gene's transcription start site, that plays a crucial role in initiating transcription. It acts as a binding site for transcription factors and the TATA-binding protein (TBP), which helps recruit RNA polymerase to begin the process of RNA synthesis.
26
Terminator (transcription)
a terminator is a DNA sequence that signals the end of a gene or operon, causing RNA polymerase to release the transcribed RNA. This termination process is crucial for regulating gene expression and preventing continued transcription of downstream genes.
27
+1 nucleotide (transcription)
the first nucleotide of the newly synthesized RNA strand that is transcribed from the DNA template. This site is also known as the transcription start site or initiation site.
28
Silencer (transcription)
a DNA sequence that reduces or prevents the expression of a gene
29
Three types of posttranslational modifications of RNA
1. 5' Cap Addition 2. 3' Poly(A) Tail Addition 3. RNA Splicing
30
1. 5' Cap Addition:
A methylated guanine residue is added to the 5' end of the mRNA molecule, forming a cap structure. This cap protects the RNA from degradation by exonucleases and facilitates ribosome binding for translation.
31
2. 3' Poly(A) Tail Addition:
A long string of adenine nucleotides (poly(A) tail) is added to the 3' end of the RNA molecule. This tail also protects the RNA from degradation, enhances its stability, and assists in its export from the nucleus.
32
3. RNA Splicing:
Non-coding regions (introns) are removed from the pre-mRNA transcript, and the remaining coding regions (exons) are joined together to form the mature mRNA. This process ensures that the final mRNA contains only the necessary information for protein synthesis.
33
Benefits of introns
Introns enable alternative splicing, a process where different combinations of exons (coding regions) can be included in a single mRNA molecule enhance transcription by promoting RNA polymerase II activity or by attracting regulatory proteins. They can also contribute to the stability and transport of mRNA, ultimately leading to increased protein production.
34
Initiation of translation
the first stage where a ribosome binds to mRNA and prepares to synthesize a protein. This involves the small ribosomal subunit binding to the start codon (usually AUG) on the mRNA, with the help of an initiator tRNA carrying methionine. The large ribosomal subunit then joins, forming a functional ribosome ready for elongation.
35
Elongation of translation
In the process of translation, elongation refers to the step where the ribosome moves along the mRNA strand, adding amino acids to the growing polypeptide chain. This involves a cycle of decoding, peptide bond formation, and translocation. Elongation factors, like EF-Tu/eEF1A and EF-G/eEF2, play crucial roles in delivering aminoacyl-tRNAs and facilitating the ribosome's movement
36
Termination of translation
the final stage of protein synthesis where the ribosome encounters a stop codon (UAA, UAG, or UGA) in the mRNA, triggering the release of the completed polypeptide chain and the dissociation of the ribosome from the mRNA. This process is mediated by release factors, which recognize the stop codons and facilitate the release of the polypeptide
37
B-galactosidase
an enzyme that breaks down the sugar lactose into its two simpler sugar components, glucose and galactose regulated by the lac operon to conserve energy and resources. The enzyme is only produced when lactose is present and glucose is scarce.
38
Preventing B-galactosidase
the presence of a protein called the lac repressor when lactose is not available. This repressor binds to the operator region of the operon, blocking RNA polymerase from binding to the promoter and initiating transcription of the lacZ, lacY, and lacA genes, which include the gene for β-galactosidase. In the absence of lactose, the lac repressor protein binds to the operator region of the lac operon.
39
Basal level beta-galactosidase
Basal expression of beta-galactosidase, encoded by the lacZ gene, refers to the level of gene expression that exists even in the absence of an inducer, such as lactose Lactose binds to inhibitor so a repressor gene cannot bind but glucose is still present
40
High level beta-galactosidase
No glucose is present so ATP can bind to cAMP which binds to CAP. CAP binds to the CAP-binding site to allow for additional transcription
41
Why eukaryotic gene expression is more complex
1. More genes and located in the nucleus which must be transported to the cytoplasm 2.mRNA half life 3. Posttrans mods 4. Splicing
42
MTIIa
a type of gene encoding proteins called metallothioneins. These genes are part of a family of genes that play a role in heavy metal detoxification and homeostasis within cells. MTIIa is specifically upregulated by glucocorticoids, which are stress hormones.
43
No expression MTIIa
Repressors decrease transcription initiation PZ120 – binds over transcriptional start site
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Basal expression MTIIa
TFIID (and other basal transcription factors) to the TATA box SP1 – binds at proximal-promoter element GC (contains G-C base pairing)
45
Modulation of transcription by TF binding to enhancers
AP1, AP2, AP4 – regulated by external growth signals at ARE sites
46
High levels of MTIIA transcription stimulated by
1. Heavy-metal toxicity (MTF-1) Heavy metals bind to MTF-1 and induces a conformation change to allow TF function at MRE sites 2. Stress (glucocorticoid receptor) Stress causes vertebrates to secrete glucocorticoid Glucocorticoid binds receptor and induces a conformation change to allow TF function at GRE sites
47
why does methylation regulate gene expression
DNA Methylation — Mostly repressive What it is: The addition of methyl groups (–CH₃) to cytosine bases, usually at CpG islands near gene promoters. Effect: Methylation blocks transcription factors from binding to DNA. It also recruits proteins (like MeCP2) that condense chromatin and suppress transcription. Result: The gene is effectively silenced.
48
why does histone modification regulate gene expression
DNA is wrapped around histone proteins (forming nucleosomes). Histone tails can be chemically modified, and these marks affect how tightly DNA is wound. Common types: Acetylation (–COCH₃) — Activating Loosens chromatin → more accessible DNA Done by histone acetyltransferases (HATs) **Deacetyl
49
explain the imprinting on IGF2 alleles. Why is the paternal allele expressed and the maternal allele repressed?
IGF2 (Insulin-like Growth Factor 2) is a gene involved in fetal growth. On the Maternal allele: The ICR is not methylated. --This unmethylated ICR binds a protein called CTCF (CCCTC-binding factor). --CTCF acts as an insulator, blocking enhancers from activating IGF2. --So, IGF2 is silenced, and H19 is expressed instead. 🔓 On the Paternal allele: --The ICR is methylated. --Methylation prevents CTCF from binding. --Without the insulator, enhancers can activate IGF2. -So, IGF2 is expressed, and H19 is silenced.
50
Explain epigenetics and mouse color
More chemicals = more methylation preventing transcription No proteins = agouti color Their alleles may be for one color but due to epigenetic changes, their color changes based on their diet with little to huge impact
51
DNA Sequencing (Sanger method) Don't play every tune fast, silly
1. DNA Denaturation 2. Primer Annealing: A primer, a short sequence of DNA complementary to one end of the target DNA, is allowed to bind to the single-stranded DNA. 3. Chain Extension: DNA polymerase, an enzyme that synthesizes new DNA, extends the primer, adding nucleotides to the 3' end. 4. Chain Termination: The reaction mixture contains both normal dNTPs (deoxyribonucleotide triphosphates) and ddNTPs, which lack the 3' hydroxyl group necessary for further nucleotide addition. When a ddNTP is incorporated, the chain growth is terminated. 5. Fragment Separation: The resulting DNA fragments, each terminated by a ddNTP, are separated by size using gel electrophoresis. 6. Sequence Reading: The order of the ddNTPs, which are often fluorescently labeled, is read to determine the DNA sequence.
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Whole-genome sequencing (shotgun cloning)
Genomic DNA is cut into fragments and contigs made Entire chromosome is assembled by computer program Fragments are aligned based on identical DNA sequences
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🔑 Essential Elements in a Plasmid Vector
1. Origin of Replication (ori) Purpose: Allows the plasmid to replicate independently within the host cell 2. Selectable Marker Gene Purpose: Enables identification of cells that have taken up the plasmid. 3. Promoter (if expression is needed) Purpose: Drives transcription of the inserted gene (for expression vectors). 4. Antibiotic resistant gene 5. Inserted gene
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Bacteria and human insulin
Two strains of bacteria each produce one set of insulin polypeptide per strain Lactose exposure to activate operon Cleave off junk lactose section to purify for the polypeptide only Encourage full structure to form in purified solutions