Fluorescence Assay Flashcards

(35 cards)

1
Q

What is the basic principle of Fluorescence?

A

it its luminescence emiision of light from a substance

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2
Q

Where does emission takes place

A

at the excited state of the measured substance

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3
Q

Which is molecule can be used in fluorescence?

A

fluorescence (aromatic molecules)

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4
Q

what does the singlet state?

A

it is the lowest electronic energy level (stable configuration)

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5
Q

Does the singlet state showes flurophore?

A

NO, because of no excitation

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6
Q

What happend when light hit the molecule?

A

the Fluorophore absorbs the energy from the light, resulting in the excitation of the molecule to a higher energy level

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7
Q

Draw the jablonski-diagram

A

the exciation of the molecule

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8
Q

On what does the excitation level depends?

A

on the wavelength and the energy from the light source

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9
Q

what happend with the electrone at the higher energy level

A

it is in a unstable state, which leads to relaxation to a lowest energy level (s1)

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10
Q

What happend during the relaxation process?

A

it results in loss of energy

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11
Q

what is the excited lifetime?

A

it is the time at which the intercal concersion occur

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12
Q

what happend from s1-so state?

A

energy is being release and emitted as light

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13
Q

What is the emitted light

A

it is the fluorescence emission

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14
Q

compared the energy of both absorbt and emitted light

A

the emitted light is of lower energy than the absorb light

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15
Q

how is the energy level related to the wavlength?

A

lower energy, longer wavelenth

higher energy, shoter wavalength

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16
Q

what is the reason for the low energy of the emitted light?

A

it is because of the loss of engery during the relaxation process

17
Q

What affects the intensity of the emitted light

A

it is affected by the illimination deviation to lower and higher wavelength

18
Q

What is the stokes shift?

A

it is the difference between the excitation and emission maximal. in other words, the emission maximaum (longer wavelength) is is different from that of the absorb light (high energy, short wavelength)

19
Q

On what dose the stokes shift depends?

A

it depends on the energy loss during the relaxation of the flurophore molecule.

20
Q

which method can be used to determine the Limit of detection

A

Blank-value method and the Signal-to-noise ratio

21
Q

defind the Blank-value method

A

the chosen concentration is 10 times lower than the lowest concentration in the calibration curve

22
Q

Equation of the Blank-value method

A

LOD=3.3x Sd/m

23
Q

What is the Limit of detection

A

it is the smallest amount of analyste in the sample that is assumed to be higher than in a blank sample.

24
Q

When the S/N applied

A

it is applied tp procedures exhibiting baseline Noise.

25
How is the LOD with defind N/S defind
it is by comparing the minimum concentration at which the analyte can be detected from samples with knwon low concentration and blank samples
26
Equation of the S/N
S/N= 2H/h
27
why is the sensitivity of a Uv.is spectrometer easy to define?
it is because of the absoulte unit of measurement called the Absorbance value
28
LOD and LOQ
LOD: the smallest amount of the analyte in the sample which can be detected LOQ: quantitation of the smallest amount of the analyte
29
Equation of LOQ
LOQ= 3 * LOD
30
Disadvantges of the Fluori
``` Non-linearity temparaure ph effects inner-filter effects quenching ```
31
Non-linearity Fluori
occured due to higher concentration of the fluorophore, saturated
32
Quenching in Fluori
when there is an interaction of the excited fluorohore molecule with uts surrounding which leads to a decrease of the intensity
33
Disadvantges of UV-Vis
Selectivity, low sensitivity
34
Selectivity UV-vis
no distintion between the samples of interest and present contamination which abort at the same wavelength
35
low sensitivity UV-vis
sensitivity is higher at a higher concentration, leading to additional steps to oncrease the concentration of the sample